File System Implementation

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Presentation transcript:

File System Implementation CSSE 332 Operating Systems Rose-Hulman Institute of Technology Print packet for Homework on File System.

File-system structure File structure Logical storage unit Collection of related information File system resides on secondary storage (disks) File system organized into layers File control block – storage structure consisting of information about a file

Typical file control block A per-file FCB contains many details about a file. It has a unique identifier number to allow association with a directory entry. The directory entry contains the name of the fine and the inode number on a LINUX system. On other systems, file block information is included. It also contains file type information. In NTFS, this is stored in the master file table. In UNIX, this is the same as the inode.

In-memory file system structures Each process has an open-file table that contains a pointer to the appropriate entry in the system-wide open –file table.

Virtual file systems Virtual File Systems (VFS) provide an object-oriented way of implementing file systems. VFS allows the same system call interface (the API) to be used for different types of file systems. The API is to the VFS interface, rather than any specific type of file system. So how do we plug in a file system? Most OS’es including UNIX offers a VFS that interfaces with any file system that we wish to add.

Schematic of virtual file system But on these disks, files are stored in directories. How should directories be implemented so they can be searched efficiently?

Directory implementation Linear list of file names with pointer to the data blocks. simple to program time-consuming to execute Hash Table – linear list with hash data structure. decreases directory search time collisions – situations where two file names hash to the same location fixed size O(n) vs O(1 + n/k) where k  number of slots or buckets for values.

Allocation methods An allocation method refers to how disk blocks are allocated to files: Contiguous allocation Linked allocation Indexed allocation How do we actually organize the data component of files on disk?

Contiguous allocation of disk space Each file has a simple directory entry

Contiguous allocation Each file occupies a set of contiguous blocks on the disk Simple directory entry only starting location (block #) and length (number of blocks) are required Random access Wasteful of space dynamic storage-allocation problem Files cannot grow

Linked allocation Each file is a linked list of disk blocks: blocks may be scattered anywhere on the disk. pointer block =

Linked allocation (2) For the directory entry, ONLY the starting address of the file is really needed. The end address is not needed; the file ends when the next block pointer points to NULL.

Linked allocation (Cont.) Simple – need only starting address Free-space management system – no waste of space No random access Mapping Q LA/511 R Assume block is of size 512 words and pointer occupies 1 one. A word may be 4 or 8 bytes long. Displacement is R + 1 because first word holds the pointer. FAT is a simple variation of the Linked allocation method. In FAT, a section of the disk, at the beginning of each volume is set aside to contain the table. Table has one entry for each block & is indexed by block number. Unused block is indicated by a value of 0. To find a block, find the index of the first block with a value of 0. Block to be accessed is the Qth block in the linked chain of blocks representing the file. Displacement into block = R + 1 File-allocation table (FAT) – disk-space allocation used by MS-DOS and OS/2.

File-allocation table

Indexed allocation Brings all pointers together into the index block. Logical view. index table

Example of indexed allocation

Indexed allocation (Cont.) Need index table Random access Dynamic access without external fragmentation, but have overhead of index block. Mapping from logical to physical in a file of maximum size of 256K words and block size of 512 words. We need only 1 block for index table. Q LA/512 R Q = displacement into index table R = displacement into block

Combined Scheme: UNIX inode (4K bytes per block) Data that would otherwise be in the File control block is stored in the inode.

Inode 128 bytes (64 bytes in older systems) each Statically allocated Root inode (inode 2) is the root (/) of the filesystem (inode 0 marks unused directory slots and inode 1 is reserved for future use)

i-node: Each directory entry contains an i-node number and a file name. The i-node number is used to index into the i-node table or the i-list. Each i-node contains the attributes of a single file.

Free space management 0  block[i] free  1  block[i] occupied Bit vector (n blocks) 1 2 n-1 … 0  block[i] free 1  block[i] occupied bit[i] = 

Free space management Bit map requires extra space. Example: block size = 212 bytes (4096 Bytes) disk size = 234 bytes (16 GByte) n = 234/212 = 222 bits (4Mbits=512 KBytes) Linked list (free blocks) Cannot get contiguous space easily No waste of space Grouping Grouping - A free block contains n pointers to free blocks - The last pointer among n pointers points to another block that contains another n free block pointers. Example Suppose that the size of a disk block and the size of a pointer are 4KB and 4 bytes, respectively. Suppose that the system implements the grouped linked list for free-space list. What is the number of disk IO to obtain 10,000 blocks?

Free space management Pointer to free list Bit map Need to protect: Pointer to free list Bit map Must be kept on disk Problem: Copy in memory and disk may differ. Cannot allow for block[i] to have a situation where bit[i] = 1 in memory and bit[i] = 0 on disk. Solution: Set bit[i] = 1 in disk. Allocate block[i] Set bit[i] = 1 in memory Disk is non volatile

Free space management Every block is assigned an ID in sequential order In a reserved part of the disk, a list of the IDs of free blocks is maintained The ID size depends on the number of blocks on disk The number of blocks required to hold the IDs depends on how many blocks are free