Single crystal XRD.

Slides:



Advertisements
Similar presentations
Objectives By the end of this section you should:
Advertisements

Reciprocal Space Learning outcomes
Don’t Ever Give Up!.
X-RAY DIFFRACTION TECHNIQUE
Electromagnetic Waves G5 - X Rays. Coolidge tube (X-ray tube) K = Hot filament cathode A = Tungsten anode U h = Heater Voltage (e.g. 12V) U a = Accelerating.
Bragg’s Law nl=2dsinΘ Just needs some satisfaction!! d Θ l
Lecture 20 X-Ray Diffraction (XRD)
X-ray Diffraction. X-ray Generation X-ray tube (sealed) Pure metal target (Cu) Electrons remover inner-shell electrons from target. Other electrons “fall”
Lecture 21 (12/11/2006) X-Ray Diffraction (XRD) Theory and Analytical Technique.
Crystal diffraction Laue Nobel prize Max von Laue
Experimentally, the Bragg law can be applied in two different ways:
AP Physics Chapter 28 Quantum Mechanics and Atomic Physics
Planes in Lattices and Miller Indices
CHAPTER 3: CRYSTAL STRUCTURES X-Ray Diffraction (XRD)
Determination of Crystal Structures by X-ray Diffraction
4. Investigations into the electrical properties of particular metals at different temperatures led to the identification of superconductivity and the.
XRD Line Broadening With effects on Selected Area Diffraction (SAD) Patterns in a TEM MATERIALS SCIENCE &ENGINEERING Anandh Subramaniam & Kantesh Balani.
Topic 13: Quantum and Nuclear physics “The wave nature of matter” Matter behaving as a wave? Ridiculous!
Internal – External Order We described symmetry of crystal habit (32 point groups) We also looked at internal ordering of atoms in 3-D structure (230 space.
X-Ray Crystallography The most important technique for mineralogy The most important technique for mineralogy Direct measurement of atomic arrangement.
Followed by a few examples of
Reciprocal lattice How to construct reciprocal lattice
CHAPTER 2 : CRYSTAL DIFFRACTION AND PG Govt College for Girls
Lecture 8b X-Ray Diffraction. Introduction I History 1895 Wilhelm Conrad R ӧ ntgen discovered X-rays 1905 Albert Einstein introduces the concept of photons.
Solid State Physics 2. X-ray Diffraction 4/15/2017.
I am not an expert on any of this!
X-Ray Diffraction. The XRD Technique Takes a sample of the material and places a powdered sample which is then illuminated with x-rays of a fixed wave-length.
Yat Li Department of Chemistry & Biochemistry University of California, Santa Cruz CHEM 146C_Experiment #3 Identification of Crystal Structures by Powder.
Indexing cubic powder patterns
1 Recap  X-rays are very short EM radiation, 0.01 nm – 10 nm  It’s the reverse process of photoeletricity but at much higher energy scale ( 100 eV –
X-ray Diffraction (XRD) and Forensic Geology X-ray diffraction pattern for goethite X-ray diffractometer (XRD) laboratory.
X-Ray Diffraction ME 215 Exp#1. X-Ray Diffraction X-rays is a form of electromagnetic radiation having a range of wavelength from nm (0.01x10 -9.
Catalysis and Catalysts - X-Ray Diffraction (XRD) X-Ray Diffraction Principle: interference of photons by reflection by ordered structures n = 2d sin 
Submitted By:- Nardev Kumar Bajaj Roll NO Group-C
Analysis of XRD Test.
Rocks Minerals and Crystals By Guest Scientist Dr. David Walker LDEO-Columbia University.
CHE (Structural Inorganic Chemistry) X-ray Diffraction & Crystallography lecture 2 Dr Rob Jackson LJ1.16,
X-ray Diffraction Outline Crystals and Bragg Diffraction
Properties of ElectroMagnetic Radiation (Light)
An- Najah university- Nablus -Palestine
Chapter 7 X-Ray diffraction. Contents Basic concepts and definitions Basic concepts and definitions Waves and X-rays Waves and X-rays Crystal structure.
GHSGT Review Day 2 – Describe the Properties of a Wave.
X-Ray Diffraction Dr. T. Ramlochan March 2010.
PHYS 430/603 material Laszlo Takacs UMBC Department of Physics
Diffraction Basics Coherent scattering around atomic scattering centers occurs when x-rays interact with material In materials with a crystalline structure,
 The behavior of a wave is greatly influenced by the medium in which it is traveling.  The wave frequency remains unchanged in different medium.  The.
X-ray powder diffractometer X-ray powder diffractometer.
Crystallography : How do you do? From Diffraction to structure…. Normally one would use a microscope to view very small objects. If we use a light microscope.
THE X-RAY DIFFRACTOMETER AND OTHER XRD INSTRUMENTATION Precession Camera.
Essential Parts of the Diffractometer X-ray Tube: the source of X Rays Incident-beam optics: condition the X-ray beam before it hits.
X-RAY METHODS FOR ORIENTING CRYSTALS
Prepared By – Amit $hah M.Pharm 1 st sem QA Roll NO :- 03 Guided By – Mr. Pinak R. Patel Assistant Professor Dept. P’ceutical Chem. D Dharmaj Degree Pharmacy.
X-ray Crystallography - The Beginning
Lecture 10 X-Ray Diffraction.
Quantum Mechanics and Atomic Physics
CHARACTERIZATION OF THE STRUCTURE OF SOLIDS
Ch.4 Atomic Structure of Solid Surfaces.
youtube. com/watch. v=WIoS7WJDZT8 youtube
Chem E5225 – Electron Microscopy P
General Physics (PHY 2140) Lecture 28 Modern Physics Quantum Physics
X-ray diffraction.
Chem5410 Q1 2/20 & 2/27/’06 1. What is so-called a single-crystal?
X-ray powder diffractometer.
The Electromagnetic Spectrum
X-Ray Diffraction and Reciprocal Lattice
Effetto fotoelettrico
X-ray powder diffractometer.
Bragg Diffraction 2dsinq = nl Bragg Equation
Electromagnetic Spectrum
A. The Solid State Classification of Solid Structures
Presentation transcript:

Single crystal XRD

Energy as a function of wavelength X-rays – High energy, highly penetrative electromagnetic radiation Energy E = hn = hc/λ Because n = c/λ is the frequency c is the speed of light in a vacuum λ is the wavelength h is Planck’s constant λ(X-rays) = 0.02-100Å (avg. ~1 Å) λ(visible light) = 4000-7200Å As λ gets smaller, energy E gets bigger.

Powder X-ray Diffraction When the geometry of the incident X-rays impinging the sample satisfies the Bragg Equation, constructive interference occurs and a peak in intensity occurs. The powder improves the chance that all possible planes are sampled. The sample rotates through angles θ while the detector counts photons.

Kb would make confusing double peaks The Copper anode makes two strong peaks, Ka and Kb. The Kb would cause confusing double peaks, so we filter it out with a Nickel filter.

Calculations Recall last time we had a homework problem A strong peak is recorded at a 2q = 28.29 degrees. Calculate d using Bragg’s Law. Assume a l = Ka for copper of 1.54 Å. and use n=1 Hint: 2q is given, you need q. a. 1.625 angstroms b. 3.15 angstroms We used Braggs Equation nλ = 2d sin θ

Instrument Plots Here is a typical plot with a strong reflection at 2q = 28.29. Lets look at the other reflections

The next stronger peak There is another reflection at 2q = 47.12. Calculate d. nλ = 2d sin θ

The next stronger peak There is another reflection at 2q = 55.74. Calculate d. nλ = 2d sin θ

Identification A mineral with d - spacings of 3.15, 1.93, 1.65 is Fluorite, CaF2 After we have the d-spacings, we want to calculate the dimensions of the unit cell, and decide which planes are giving strong reflections. This will allow us to check our model building ideas.

Calculating Unit Cell Size A formula exists for calculating the dimensions of the unit cell for each crystal system. For Isometric crystals such as Fluorite or Halite, the formula is simple a2 = d2 (h2 + k2 + l2) where the (hkl) are the Miller indices Let’s try it with Halite, where the XRD reports d = 2.8, 1.98, 1.62, 1.404

Halite NaCl d d2 x (h2 + k2 + l2) for the zones sum of squares 1 2 3 4 5 6 2.8 7.84 7.84 15.08 23.52 31.36 39.20 47.04 1.98 3.92 3.92 7.84 11.76 15.68 19.6 23.52 1.62 2.62 2.62 5.24 7.86 10.48 13.1 15.72 1.40 1.97 1.97 3.96 5.94 7.86 9.9 11.88 Discussion: which is a2 ? Which zones made which reflections?

Homework and Lab Now complete the last question on HW8-9, then do the lab using your data printouts from your unknown.