CHE1031 Lecture 11: Chemical equilibrium

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Presentation transcript:

CHE1031 Lecture 11: Chemical equilibrium Lecture 11 topics Brown chapter 1 1. Concept of equilibrium 15.1 Equilibrium reactions are reversible 2. The equilibrium constant 15.2 Law of mass action Equilibrium constant expressions 3. Working with equilibrium expressions 15.3 What does Kc tell us? Kc & direction of reaction 4. Le Chatelier’s Principle 15.7 Application to Haber reaction Changes of concentration Changes in volume & pressure Changes in temperature 5. Catalysts & equilibrium

Le Châtelier’s principle Equilibrium reactions respond to disturbances: Concentration Temperature Pressure The general process of advancing scientific knowledge by making experimental observations and by formulating hypotheses, theories, and laws. It’s a systematic problems solving process AND it’s hands-on….. Experiments must be done, data generated, conclusions made. This method is “iterative”; it requires looping back and starting over if needed. [Why do you think they call it REsearch?] Often years, decades or more of experiments are required to prove a theory. While it’s possible to prove a hypothesis wrong, it’s actually NOT possible to absolutely prove a hypothesis correct as the outcome may have had a cause that the scientist hasn’t considered.

Le Châtelier’s principle Le Chatelier’s Principle – If a system at equilibrium is disturbed by a change in temperature, pressure or concentration, the system will shift to a new equilibrium position to counteract the disturbance. Disturbance? Adding product or reactant Removing product or reactant Changing volume, thus pressure Changing temperature N2 + 3H2 2NH3 Typically, we say that the equilibrium: Shifts to the right (towards products) Shifts to the left (toward reactants) What does adding H2 do? How could you shift the reaction left? Shifts rxn right – makes NH3 Add NH3 Remove N2 Remove H2 p. 635-7

Applying Le Châtelier’s to the Haber rxn N2 + 3H2 2NH3 How is Le Chatelier’s Principle employed here to increase production of NH3? NH3 is cooled, condensed and collected. When it’s removed from the system it’s loss shifts equilibrium to the right… …causing more NH3 product to be made. p. 649-50

Changes in volume & pressure Changes in volume tend to cause changes in pressure that “disturb” the system. Reducing volume increases pressure and that shifts equilibrium in whichever direction reduces moles of gas….and vice versa. N2O4 2NO2 1. Initial equilibrium 2. Plunger decreases volume & increases pressure & concentration, particularly of NO2. 3. Equilibrium has shifted left in order to decrease the moles of gas in cylinder. p. 649-51

Le Châtelier’s example What happens to the equilibrium of this reaction if the volume of the system is increased? 2SO2 + O2 2SO3 When the volume is increased, pressure on the system decreases. So to stay as close as possible to the original equilibrium position, the reaction needs to produce MORE molecules; more volume so need more molecules to maintain the original density of gases. So to get more molecules the reaction shifts to the left (3 moles) away from the right (2 moles). p. 649-51

Effects of temperature changes The direction of shift depends on whether the reaction in question is exothermic or endothermic via Le Châtelier’s Principle. Endothermic: reactants + heat products Exothermic: reactants products + heat Co(H2O)6 + 4Cl-1 CoCl4-2 + 6H2O ΔH = + pink blue 1. Room temp 2. Heating bath Favors products since the endothermic rxn uses heat as a reactant. 3. Cooling bath Favors reactant since lack of heat doesn’t allow product to be produced. It reduces [reactant]. p. 649-51

Another Le Châtelier’s example Consider this equilibrium reaction: N2O4 2NO2 ΔH = + 58 kJ In which direction does the reaction shift when: N2O4 is added NO2 is removed Pressure Is increased by addition of N2 Volume is increased Temperature is decreased Shifts right towards product, driven by added reactant. Shifts right towards the now depleted product c) Shifts left since there are only half as many moles of reactant as product d) Shifts right since the larger volume can accommodate more moles Shifts left since the reaction is endothermic and requires heat as reactant. Reducing the heat is like reducing [reactant]. p. 649-53