Chapter 7: The Quantum-Mechanical Model of the Atom ( )

Slides:



Advertisements
Similar presentations
Quantum Mechanics Chapter 7 §4-5. The de Broglie Relation All matter has a wave-like nature… All matter has a wave-like nature… Wave-particle.
Advertisements

Electron Configuration and New Atomic Model Chapter 4.
Why are electrons restricted to specific energy levels or quantized? Louis de Broglie – proposed that if waves have particle properties, possible particles.
Lecture 2210/26/05. Moving between energy levels.
Chapter 71 Atomic Structure Chapter 7. 2 Electromagnetic Radiation -Visible light is a small portion of the electromagnetic spectrum.
Quantum Mechanics  Bohr’s theory established the concept of atomic energy levels but did not thoroughly explain the “wave-like” behavior of the electron.
Electrons in Atoms The Quantum Model of the Atom.
Chapter 4 Notes for those students who missed Tuesday notes.
Arrangement of Electrons In Atoms
-The Bohr Model -The Quantum Mechanical Model Chemistry.
CHM 108 SUROVIEC FALL 2015 Quantum Mechanical Model.
-The Bohr Model -The Quantum Mechanical Model Warner SCH4U Chemistry.
Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Section 1 The Development of a New Atomic Model Properties of Light.
Chapter 6 Electronic Structure of Atoms. Waves To understand the electronic structure of atoms, one must understand the nature of electromagnetic radiation.
Electrons in Atoms Chapter 5. Duality of Light Einstein proved that matter and energy are related E = mc 2 Einstein proved that matter and energy are.
Electronic Structure of Atoms © 2009, Prentice-Hall, Inc. Chapter 7 Electronic Structure of Atoms.
1 The Quantum Mechanical Model of the Atom Chapter 7.
-The Bohr Model -The Quantum Mechanical Model Mrs. Coyle Chemistry.
Chapter 5/1© 2012 Pearson Education, Inc. Wavelike Properties of Matter The de Broglie equation allows the calculation of a “wavelength” of an electron.
Chapter 6 Electronic Structure of Atoms. The Wave Nature of Light The light that we can see with our eyes, visible light, is an example of electromagnetic.
Quantum Theory the modern atomic model. Bohr Model of the Atom a quantum model proposed by Niels Bohr in 1913 It helped to explain why the atomic emission.
Quantum Atom. Problem Bohr model of the atom only successfully predicted the behavior of hydrogen Good start, but needed refinement.
Quantum Theory and the Electronic Structure of Atoms Chapter 7 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Arrangement of Electrons in Atoms
Chapter 7 Lecture Lecture Presentation Chapter 7 The Quantum- Mechanical Model of the Atom Sherril Soman Grand Valley State University © 2014 Pearson Education,
The Quantum Model of the Atom Section 4.2. Bohr’s Problems Why did hydrogen’s electron exist around the nucleus only in certain allowed orbits? Why couldn’t.
Arrangement of Electrons in Atoms 4-2 The Quantum Model of the Atom.
1 Chapter 7: Periodicity and Atomic Structure Renee Y. Becker Valencia Community College CHM 1045.
Quantum Theory Chang Chapter 7 Bylikin et al. Chapter 2.
River Dell Regional High School Unit 3 – Electron Configurations Part C: Quantum Mechanical Model.
Electronic Structure of Atoms 6.4 The Wave Behavior of Matter 6.5 Quantum Mechanics and Atomic Orbitals 6.6 Representation of Orbitals.
Chapter 7: Quantum theory of the atom Chemistry 1061: Principles of Chemistry I Andy Aspaas, Instructor.
Quantum Atom. Problem Bohr model of the atom only successfully predicted the behavior of hydrogen Good start, but needed refinement.
Chemistry I Chapter 4 Arrangement of Electrons. Electromagnetic Radiation Energy that exhibits wavelike behavior and travels through space Moves at the.
Modern Model of the Atom The emission of light is fundamentally related to the behavior of electrons.
The Quantum Mechanical Model Chemistry Honors. The Bohr model was inadequate.
The Quantum Mechanical Picture of the Atom
Quantums numbers & the probability of where an electron may be found
Atomic Structure Figure 6.27.
7.4 The Wave Nature of Matter – 7.5 Quantum Mechanics and the Atom
Quantum mechanical model of the atom
The Bohr Model, Wave Model, and Quantum Model
Atomic Models Scientist studying the atom quickly determined that protons and neutrons are found in the nucleus of an atom. The location and arrangement.
Atomic Theory.
The Atom and Unanswered Questions
Electronic Structure of Atoms
III. Quantum Model of the Atom (p )
The Quantum Mechanical Model
Quantum Theory Light Theory Part 4.
Chapter 7 The Quantum-Mechanical Model of the Atom
Tools of the Laboratory
Chapter 7: Atomic Structure
The Quantum Model of the Atom
Islamic University - Gaza
Chapter 4 Electrons as Waves
The Quantum Model of the Atom
The Quantum Mechanical Model
Chapter 7: The quantum-mechanical model of the atom
Chapter 6 Quantum Mechanical Model & Electron Configurations
III. Quantum Model of the Atom (p )
III. Quantum Model of the Atom (p )
III. Quantum Model of the Atom (p )
Quantum Theory Electrons!.
The Bohr Model, Wave Model, and Quantum Model
Presentation transcript:

Chapter 7: The Quantum-Mechanical Model of the Atom (7.4-7.5) By: Gagana Yaskhi

Quantum-Mechanical Model Quantum-mechanical model was first proposed by Louis de Broglie At the time, electrons were thought to have wave nature If an electron beam passes through 2 slits, an interference pattern occur but it is not caused by pairs of electrons interfering with each other, it is caused by single electrons interfering with themselves The wave nature of the electron is an inherent property of individual electrons

De Broglie Relation Single electron traveling through space has wave nature and its wavelength is related to kinetic energy shorter wavelengths move faster and have higher kinetic energy de Broglie relation: λ= h/mv λ is wavelength h is Planck’s constant (6.626 x 1023 J·s) m is mass of electron v is velocity

Practice Problem Calculate the wavelength of an electron traveling with a speed of 2.65 x 106 m/s. (Hint: mass of electron=9.11 x 10-31 kg) λ= h/mv= (6.626 x 1023 J·s)/(9.11 x 10-31 kg)(2.65x 106 m/s) λ= 2.74 x 10-10 m

Uncertainty Principle Electron diffraction experiment, that was performed to show which slit an electron travels through by using a laser beam directly behind slits, determined than we can never both see the interference pattern and simultaneously determine which hole the electron goes through We can’t observe the wave and particle nature of the electron at the same time Wave and particle nature are complementary properties (exclude one another; the more we know of one, the less we know of the other) Velocity of electron= wave nature Position= particle nature

Uncertainty Principle Heisenberg’s uncertainty principle: Δ x x mΔ v ≥ (h/4 π) Δ x is uncertainty of position Δ v is uncertainty of velocity m is mass The more accurately you know position of electrons (smaller Δ x) the less accurately you know velocity (bigger Δ v) An electron is observed as either a particle or wave but not both at once

Indeterminacy and Probability of Distribution Map Particles move in a trajectory (path) determined by the particle’s velocity, position, and forces acting on it according to Newton’s laws of motion Position and velocity are required to predict trajectory so we cannot know the trajectory of electrons Newton’s laws of motion are deterministic (the present determines the future) In quantum mechanics, probability distribution maps statistically show where an electron is most likely to land under given conditions as we cannot know its exact trajectory Indeterminacy describes the behavior of an electron because future path of an electron cannot be determined

Quantum Mechanics and the Atom Since velocity is directly related to energy, position and energy are complementary properties Orbital: probability distribution map showing where an electron is most likely to be found Spatial distribution of electron is important to bonding Mathematical derivation of energies and orbitals for electrons comes from Schrödinger’s equation: Wavefunction describes wavelike nature of electrons H= total energy(kinetic and potential) of the electron in at atom E= actual energy of electron Ψ2 represents an orbital

Quantum Mechanics and the Atom Each orbital is specified by 3 quantum numbers: n= principal quantum number integer that determines overall size and energy of orbital: n=1,2,3… For hydrogen atoms, energy with quantum number n (En) = -2.18x10-18 J (1/n2) (n= 1,2,3,…) l= angular momentum quantum number Integer that determines shape of orbital: l=0,1,2…(n-1) ml= magnetic quantum number Integer that specifies orientation of orbital: m= +l to -l

Quantum Mechanics and the Atom A fourth number ms= spin quantum number specifies orientation of spin of electron Electrons can spin up (ms=+½) or spin down (ms=-½) Each combination of n,l, and ml specifies an atomic orbital n=1, l=0, ml=0 is 1s orbital Orbitals with same n value are in the same principal levels or principal shell Orbitals with same n and l are in the same sublevel (subshell) # of sublevels = n # of orbitals in any sublevel= 2l + 1 # of orbitals in a level= n2

Practice Problem What are the quantum numbers and names (for example, 2s, 2p) of the orbitals in the n=4 principal level? How many n=4 orbitals exist? n=4; therefore, l= 0,1,2,and 3 16 orbitals total l Possible ml values Orbital name 4s (1 orbital) 1 -1,0,+1 4p (3 orbitals) 2 -2,-1,0, +1, +2 4d (5 orbitals) 3 -3, -2, -1, 0, +1, +2, +3 4f (7 orbitals)

Atom Spectroscopy Explained When an atom absorbs energy, an electron in a lower energy level is promoted to a higher one The new configuration is unstable and the electron falls back to the lower energy orbital and releases a photon of light equal to the energy difference between the two levels Δ E= Efinal - Einitial = -2.18 x 10 -18 J (⅟nf2 - ⅟ni2) Δ Eatom = -Ephoton Transition between orbitals further apart in energy produces light in higher energy and shorter wavelength

Practice Problem Determine the wavelength of light emitted when an electron in a hydrogen atom makes a transition from an orbital in n=6 to an orbital in n=5. Δ Eatom= E5 - E6 = -2.18 x 10 -18 J (⅟52 - ⅟62) = 2.664 x 10-20 J Δ Eatom = -Ephoton= +2.664 x 10-20 J λ= hc/E =(6.626 x 1023 J·s)(3.00 x 108 m/s)/ (2.664 x 10-20 J) = 7.46 x 10-6 m