Find the SA. Complete in your notes

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Presentation transcript:

Find the SA. Complete in your notes. 1. 2. 3. 4. 5 Minute Check Find the SA. Complete in your notes. 1. 2. 3. 4.

Find the SA. Complete in your notes. 1. 5 Minute Check Find the SA. Complete in your notes. 1.

Find the SA. Complete in your notes. 1. 5 Minute Check Find the SA. Complete in your notes. 1. SA=30+30+208+192+80=540units²

Find the SA. Complete in your notes. 1. 5 Minute Check Find the SA. Complete in your notes. 1. F = 12∙5 ÷2=30 p = 12+5+13= 30 h = 16 SA = 2F + ph SA =2∙30+30∙16 SA = 60 + 480 SA = 540 ft²

Find the SA. Complete in your notes. 2. 5 Minute Check Find the SA. Complete in your notes. 2.

Find the SA. Complete in your notes. 2. 5 Minute Check Find the SA. Complete in your notes. 2. 10 10 43.5 150 150 150 15 43.5 8.7 SA=150+150+150+43.5+43.5=537ft²

Find the SA. Complete in your notes. 2. 5 Minute Check Find the SA. Complete in your notes. 2. F = 8.7∙ 10 ÷2=43.5 p = 10+10+10= 30 h = 15 SA = 2F + ph SA =2∙43.5+30∙15 SA = 87 + 450 SA = 537 ft²

Find the SA. Complete in your notes. 3. 5 Minute Check Find the SA. Complete in your notes. 3.

Find the SA. Complete in your notes. 3. 5 Minute Check Find the SA. Complete in your notes. 3. 3 3.9 21 21 21 7 3 3.9 2.6 SA=21+21+21+3.9+3.9=70.8in²

Find the SA. Complete in your notes. 3. 5 Minute Check Find the SA. Complete in your notes. 3. F = 3∙ 2.6 ÷2=3.9 p = 3+3+3= 9 h = 7 SA = 2F + ph SA =2∙3.9+9∙7 SA = 7.8 + 63 SA = 70.8 in²

Find the SA. Complete in your notes. 4. 5 Minute Check Find the SA. Complete in your notes. 4.

Find the SA. Complete in your notes. 4. 5 Minute Check Find the SA. Complete in your notes. 4. 8 5.3 15.9 6 68.9 78 104 13 15.9 SA=68.9+78+104+15.9+15.9=282.7cm²

Find the SA. Complete in your notes. 4. 5 Minute Check Find the SA. Complete in your notes. 4. F = 5.3∙ 6 ÷2=15.9 p = 5.3+6+8= 19.3 h = 13 SA = 2F + ph SA =2∙15.9+19.3∙13 SA = 31.8 + 250.9 SA = 282.7cm²

Chapter 9 Review Find the area. Complete in your notes. 1. 2.

Chapter 9 Review Find the area. Complete in your notes. 1.

1. Area=15+8+12+25+5=65ft² Chapter 9 Review Find the area. Complete in your notes. 1. 12 15 5 25 5 5 3 5 1 8 Area=15+8+12+25+5=65ft²

1. Top Rectangle 6 · 7 = 42ft² Bottom Rectangle 6 · 8 = 48ft² Overlap Chapter 9 Review Find the area. Complete in your notes. 1. Top Rectangle 6 · 7 = 42ft² Bottom Rectangle 6 · 8 = 48ft² Overlap 5 · 5 = 25ft² Total Area 42 + 48 - 25= 65ft² 5 5

Chapter 9 Review Find the area. Complete in your notes. 2.

2. Area=4+1+1+4+5=15m² Chapter 9 Review Find the area. Complete in your notes. 2. 1 5 1 1 1 4 1 1 4 Area=4+1+1+4+5=15m²

2. Top Rectangle 5 · 2 = 10m² Bottom Rectangle 3 · 2 = 6m² Overlap Chapter 9 Review Find the area. Complete in your notes. 2. Top Rectangle 5 · 2 = 10m² Bottom Rectangle 3 · 2 = 6m² Overlap 1 · 1 = 1m² Total Area 10 + 6 -1=15m² 1 1

Lesson10.5 Surface Areas of Pyramids Wednesday, April 6 Lesson10.5 Surface Areas of Pyramids

Surface Areas of Pyramids Objective: To find the surface area of pyramids.

Surface Areas of Pyramids The surface area (SA) of a three dimensional figure is the outer face or exterior boundary of the figure.

Surface Areas of Pyramids A pyramid is a three-dimensional figure with faces that meet at a common vertex. vertex

Surface Areas of Pyramids The shape of the base determines the name of the pyramid.

Surface Areas of Pyramids A pyramid has at least three triangular sides, called lateral faces.

Surface Areas of Pyramids The slant height is the distance from the vertex to the mid-point of a side of the base.

Surface Areas of Pyramids As with prisms, the shape of the base determines the name of the pyramid.

Surface Areas of Pyramids There are many types of pyramids. We will only be concerned with regular triangular pyramids and square pyramids.

Surface Areas of Pyramids All pyramids that we will be working with will be regular pyramids, meaning the bases will either be a square or equilateral triangle.

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 1 – Draw the shape of the base. Draw this in your notes.

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 1 – Draw the shape of the base.

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 2 – Include the dimensions of the base.

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 2 – Include the dimensions of the base. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 3 – Draw the lateral faces. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 3 – Draw the lateral faces. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 4 – Include the dimensions of the faces. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 4 – Include the dimensions of the faces. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 5 – Find the area of each section and add. 7 7

Surface Areas of Pyramids Find the SA of regular pyramid. To Find the SA of a Pyramid. Step 5 – Find the area of each section and add. 31.5 31.5 7 31.5 49 7 31.5 SA = 49+31.5+31.5+31.5+31.5 = 175cm²

Surface Areas of Pyramids Find the SA of regular pyramid. Do this on your own.

Surface Areas of Pyramids Find the SA of regular pyramid. SA=9 + 6.75+6.75+6.75+6.75 = 36in² 6.75 3 in 4.5 in 6.75 9 6.75 3 in 6.75

Surface Areas of Pyramids Find the SA of regular pyramid.

Surface Areas of Pyramids Find the SA of regular pyramid. SA = 7+10+10+10=37 ft² 10 10 4 ft 5 ft 3.5 ft 4 ft 7 4 ft 10

Surface Areas of Pyramids Find the SA of regular pyramid.

Surface Areas of Pyramids Find the SA of regular pyramid. SA = 25 + 20.5+20.5 +20.5+20.5= 107 ft² 20.5 5 ft 8.2 ft 20.5 5 ft 25 20.5 20.5

Surface Areas of Pyramids Find the SA of regular pyramid. 2 1 2 m 2 1 2 m

Surface Areas of Pyramids Find the SA of regular pyramid. SA = 6 1 4 + 6 1 4 + 6 1 4 + 6 1 4 + 6 1 4 = 31 1 4 m² 6 1 4 2 1 2 2 1 2 5 6 1 4 6 1 4 6 1 4 6 1 4

AIR Review In a bag of marbles, 3/5 of the marbles are blue and the rest are red. If the number of red marbles is doubled and the number of blue marbles stays the same, what fraction of the marbles will be red?

AIR Review In a bag of marbles, 3/5 of the marbles are blue and the rest are red. If the number of red marbles is doubled and the number of blue marbles stays the same, what fraction of the marbles will be red? 3/5 are blue 2/5 are red The ratio of blue to red is 3/2. If the red marbles are doubled, the ratio of blue to red would be 3/4. Now the ratio of red to total is 4/7. total

AIR Review Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, How far did she ride in 15 minutes? How long did it take her to ride 6 miles? How fast did she ride in miles per hour? What was her pace in minutes per mile?

AIR Review Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, How far did she ride in 15 minutes? 20 𝑚𝑖 150 𝑚𝑖𝑛 = ? 15 𝑚𝑖𝑛 20 · 15 ÷ 150 = 2 miles How long did it take her to ride 6 miles? How fast did she ride in miles per hour? What was her pace in minutes per mile?

AIR Review Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, How far did she ride in 15 minutes? How long did it take her to ride 6 miles? 20 𝑚𝑖 150 𝑚𝑖𝑛 = 6 𝑚𝑖 ? 150 · 6 ÷ 20 = 45 min How fast did she ride in miles per hour? What was her pace in minutes per mile?

AIR Review Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, How far did she ride in 15 minutes? How long did it take her to ride 6 miles? How fast did she ride in miles per hour? 20 𝑚𝑖 150 𝑚𝑖𝑛 = ? 60 𝑚𝑖𝑛 20 · 60 ÷ 150 = 8 miles per hour What was her pace in minutes per mile?

AIR Review Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, How far did she ride in 15 minutes? How long did it take her to ride 6 miles? How fast did she ride in miles per hour? What was her pace in minutes per mile? 150 𝑚𝑖𝑛 20 𝑚𝑖 = ? 1 𝑚𝑖 150 · 1 ÷ 20 = 7.5 min per mile

Surface Areas of Pyramids Agenda Notes No Homework– Homework Practice 10.5 Due by the end of class Chapter 9/10 Test – Monday, April 11 Accum Review 10– Due Monday, April 11