Physics 212 Lecture 15 Ampere’s Law.

Slides:



Advertisements
Similar presentations
Chapter 22: The Electric Field II: Continuous Charge Distributions
Advertisements

Sources of the Magnetic Field
Physics 1304: Lecture 12, Pg 1 The Laws of Biot-Savart & Ampere  dl I.
© 2012 Pearson Education, Inc. A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2)
C. less, but not zero. D. zero.
Today’s Concept: Ampere’s Law
Unit 4 Day 8 – Ampere’s Law & Magnetic Fields thru Solenoids & Toroids Definition of Current Ampere’s Law Magnetic Field Inside & Outside a Current Carrying.
Chapter 28 Sources of Magnetic Field
Physics 1502: Lecture 18 Today’s Agenda Announcements: –Midterm 1 distributed available Homework 05 due FridayHomework 05 due Friday Magnetism.
Chapter 29 Electromagnetic Induction and Faraday’s Law HW#9: Chapter 28: Pb.18, Pb. 31, Pb.40 Chapter 29:Pb.3, Pb 30, Pb. 48 Due Wednesday 22.
Examples of Magnetic Field Calculations x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x r a  dl I.
a b c Gauss’ Law … made easy To solve the above equation for E, you have to be able to CHOOSE A CLOSED SURFACE such that the integral is TRIVIAL. (1)
III.A 3, Gauss’ Law.
For the wire carrying a flow of electrons in the direction shown, is the magnetic field at point P - P (a)to the right (b)to the left (c)up (d)into the.
Wed. Feb. 18 – Physics Lecture #30 Magnetic Fields 1. Magnetic Fields 2. Magnetic Moments & Torque 3. Ampere’s Law Warm-Up, Discuss with Neighbors: Wire.
W09D1: Sources of Magnetic Fields: Ampere’s Law
Electricity and Magnetism Review 1: Units 1-6
Biot-Savart Law, Ampère’s Law Fields and forces for current in straight wires Ampère’s Law.
Physics 202, Lecture 13 Today’s Topics Magnetic Forces: Hall Effect (Ch. 27.8) Sources of the Magnetic Field (Ch. 28) B field of infinite wire Force between.
Copyright © 2009 Pearson Education, Inc. Ampère’s Law.
Physics 2102 Magnetic fields produced by currents Physics 2102 Gabriela González.
Physics 2112 Unit 4: Gauss’ Law
L P X dL r Biot-Savard Law L P X dL r Biot-Savard Law.
A b c. Choose either or And E constant over surface is just the area of the Gaussian surface over which we are integrating. Gauss’ Law This equation can.
Magnetic Field of a Solenoid
Physics 212 Lecture 15 Ampere’s Law.
Physics 212 Lecture 29, Slide 1 Physics 212 Lecture 29 Course Review The Topics For Today – –Electric Fields/Gauss’ Law/Potential – –Faraday’s Law – –RC/RL.
Applications of Ampere’s Law
Sources of Magnetic Fields
Physics 212 Lecture 4, Slide 1 Physics 212 Lecture 4 Today's Concepts: Conductors + Using Gauss’ Law Applied to Determine E field in cases of high symmetry.
Magnetic Fields due to Currents Chapter 29. The magnitude of the field dB produced at point P at distance r by a current-length element ds turns out to.
Last Time Magnetic Force Motors and Generators Gauss' Law 1.
Chapter 28 Sources of Magnetic Field Ampère’s Law Example 28-6: Field inside and outside a wire. A long straight cylindrical wire conductor of radius.
Copyright © 2012 Pearson Education Inc. PowerPoint ® Lectures for University Physics, Thirteenth Edition – Hugh D. Young and Roger A. Freedman Lectures.
BABARIA INSTITUTE OF TECHNOLOGY ELECTRONICS & COMMUNICATION DEPARTMENT
Two questions: (1) How to find the force, F on the electric charge, q excreted by the field E and/or B? (2) How fields E and/or B can be created?
24.2 Gauss’s Law.
Ampère’s Law Figure Arbitrary path enclosing a current, for Ampère’s law. The path is broken down into segments of equal length Δl.
Physics 212 Lecture 6 Electric Potential.
Physics 212 Lecture 14 Biot-Savart Law :05.
Physics 212 Lecture 4 Gauss’ Law.
Gauss’s Law ENROLL NO Basic Concepts Electric Flux
Chapter 3 Magnetostatics
Electricity and Magnetism
Magnetic Fields due to Currents
Ampère’s Law Figure Arbitrary path enclosing a current, for Ampère’s law. The path is broken down into segments of equal length Δl.
Physics 2102 Lecture 16 Ampere’s law Physics 2102 Jonathan Dowling
Magnetic Sources AP Physics C.
LECTURE 15 Ampere’s Law Gauss’ Law for Magnetism
Announcements Tutoring available
Dr. Cherdsak Bootjomchai (Dr.Per)
Today: fundamentals of how currents generate magnetic fields
Cross-section of the wire:
Electricity and Magnetism
E. not enough information given to decide Gaussian surface #1
C. less, but not zero. D. zero.
Magnetic Sources AP Physics C.
Lesson 8 Ampère’s Law and Differential Operators
Applications of Ampere’s Law
Quiz 1 (lecture 4) Ea
Magnetic Sources AP Physics C.
Gauss’s law This lecture was given mostly on the board so these slides are only a guide to what was done.
Magnetic Field Due To A Current Loop.
Magnetic Field Due To A Current Loop.
Magnetic Sources AP Physics C.
Sources of Magnetic Fields
Chapter 28 Sources of Magnetic Field
Electricity and Magnetism
Chapter 30 Examples 4,8.
Electricity and Magnetism
Presentation transcript:

Physics 212 Lecture 15 Ampere’s Law

Infinite current-carrying wire LHS: RHS: General Case :05

Practice on Enclosed Currents Checkpoint 1a Checkpoint 1b Checkpoint 1c Ienclosed = 0 Ienclosed = I Ienclosed = I Ienclosed = 0 For which loop is B·dl the greatest? A. Case 1 B. Case 2 C. Same For which loop is B·dl the greatest? A. Case 1 B. Case 2 C. Same For which loop is B·dl the greatest? A. Case 1 B. Case 2 C. Same :08

Cylindrical Symmetry Checkpoint 2a Enclosed Current = 0 An infinitely long hollow conducting tube carries current I in the direction shown. Cylindrical Symmetry Checkpoint 2a X Enclosed Current = 0 X X X Check cancellations What is the direction of the magnetic field inside the tube? A. clockwise B. counterclockwise C. radially inward to the center D. radially outward from the center E. the magnetic field is zero :22

Line Integrals I into screen :12

Ampere’s Law dl B dl B dl B :14

Ampere’s Law dl B dl B dl B :16

Ampere’s Law dl B dl B dl B :16

Which of the following current distributions would give rise to the B Which of the following current distributions would give rise to the B.dL distribution at the right? A C B :18

:19

:19

:19

Match the other two: B A :21

Checkpoint 2b :22

Simulation :23

Solenoid Several loops packed tightly together form a uniform magnetic field inside, and nearly zero magnetic field outside. 1 2 4 3 Assume a constant field inside the solenoid and zero field outside the solenoid. Apply Ampere’s law to find the magnitude of the field. n = # turns/length :28

Example Problem I Conceptual Analysis An infinitely long cylindrical shell with inner radius a and outer radius b carries a uniformly distributed current I out of the screen. Sketch |B| as a function of r. I a x Conceptual Analysis Complete cylindrical symmetry (can only depend on r)  can use Ampere’s law to calculate B B field can only be clockwise, counterclockwise or zero! b For circular path concentric w/ shell The purpose of this Check is to jog the students minds back to when they studied work and potential energy in their intro mechanics class. Calculate B for the three regions separately: 1) r < a 2) a < r < b 3) r > b :31

Example Problem I so (A) (B) (C) r y I r a b x What does |B| look like for r < a ? so (A) (B) (C) :33

Example Problem I I (A) (B) (C) r y I r What does |B| look like for r > b ? a b x I (A) (B) (C) :35

Example Problem dl I LHS: B RHS: (A) (B) (C) y What does |B| look like for r > b ? dl I r LHS: B a b x RHS: (A) (B) (C) :36

Example Problem j = I / area I (A) (B) (C) y I What is the current density j (Amp/m2) in the conductor? a b x (A) (B) (C) j = I / area :40

Example Problem I (A) (B) (C) r y I r What does |B| look like for a < r < b ? a b x (A) (B) (C) :43

Example Problem I (A) (B) (C) y What does |B| look like for a < r < b ? I r a b x Starts at 0 and increases almost linearly (A) (B) (C) :45

Example Problem y An infinitely long cylindrical shell with inner radius a and outer radius b carries a uniformly distributed current I out of the screen. Sketch |B| as a function of r. I a x b :48

Follow-Up B will be zero if total current enclosed = 0 I I0 X y Add an infinite wire along the z axis carrying current I0. What must be true about I0 such that there is some value of r, a < r < b, such that B(r) = 0 ? X I a I0 x A) |I0| > |I| AND I0 into screen b B) |I0| > |I| AND I0 out of screen C) |I0| < |I| AND I0 into screen D) |I0| < |I| AND I0 out of screen E) There is no current I0 that can produce B = 0 there B will be zero if total current enclosed = 0 :48