Announcements Please read Chapters 4 and 5 Quiz today on HW 2

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ECE 476 Power System Analysis Lecture 6: Transmission Line Parameters Prof. Tom Overbye Dept. of Electrical and Computer Engineering University of Illinois at Urbana-Champaign overbye@illinois.edu Special Guest Lecturer: TA Iyke Idehen

Announcements Please read Chapters 4 and 5 Quiz today on HW 2 HW 3 is 4.9 (use lecture results for 4.8 comparison), 4.12, 4.19 (just compare 4.19a to 4.19b), 4.25 It does not need to be turned in, but will be covered by an in-class quiz on Thursday Sept 15 Positive sequence is same as per phase; it will be covered in Chapter 8 Use Table A.4 values to determine the Geometric Mean Radius of the wires (i.e., the ninth column).

Many-Conductor Case, cont’d

Many-Conductor Case, cont’d

Symmetric Line Spacing – 69 kV

Birds Do Not Sit on the Conductors

Line Inductance Example Calculate the reactance for a balanced 3f, 60Hz transmission line with a conductor geometry of an equilateral triangle with D = 5m, r = 1.24cm (Rook conductor) and a length of 5 miles.

Line Inductance Example, cont’d

Conductor Bundling To increase the capacity of high voltage transmission lines it is very common to use a number of conductors per phase. This is known as conductor bundling. Typical values are two conductors for 345 kV lines, three for 500 kV and four for 765 kV.

Bundled Conductor Pictures The AEP Wyoming-Jackson Ferry 765 kV line uses 6-bundle conductors. Conductors in a bundle are at the same voltage! Photo Source: BPA and American Electric Power

Bundled Conductor Flux Linkages For the line shown on the left, define dij as the distance bet- ween conductors i and j. We can then determine l for each

Bundled Conductors, cont’d

Bundled Conductors, cont’d

Inductance of Bundle

Inductance of Bundle, cont’d

Bundle Inductance Example Consider the previous example of the three phases symmetrically spaced 5 meters apart using wire with a radius of r = 1.24 cm. Except now assume each phase has 4 conductors in a square bundle, spaced 0.25 meters apart. What is the new inductance per meter? 0.25 M

Transmission Tower Configurations The problem with the line analysis we’ve done so far is we have assumed a symmetrical tower configuration. Such a tower figuration is seldom practical. Therefore in general Dab  Dac  Dbc Unless something was done this would result in unbalanced phases Typical Transmission Tower Configuration

Transposition To keep system balanced, over the length of a transmission line the conductors are rotated so each phase occupies each position on tower for an equal distance. This is known as transposition. Aerial or side view of conductor positions over the length of the transmission line.

Line Transposition Example

Line Transposition Example

Transposition Impact on Flux Linkages “a” phase in position “1” “a” phase in position “3” “a” phase in position “2”

Transposition Impact, cont’d

Inductance of Transposed Line

Inductance with Bundling

Inductance Example Calculate the per phase inductance and reactance of a balanced 3, 60 Hz, line with horizontal phase spacing of 10m using three conductor bundling with a spacing between conductors in the bundle of 0.3m. Assume the line is uniformly transposed and the conductors have a 1cm radius. Answer: Dm = 12.6 m, Rb= 0.0889 m Inductance = 9.9 x 10-7 H/m, Reactance = 0.6 /Mile

Line Conductors Typical transmission lines use multi-strand conductors ACSR (aluminum conductor steel reinforced) conductors are most common. A typical Al. to St. ratio is about 4 to 1.

Line Conductors, cont’d Total conductor area is given in circular mils. One circular mil is the area of a circle with a diameter of 0.001 =   0.00052 square inches Example: what is the the area of a solid, 1” diameter circular wire? Answer: 1000 kcmil (kilo circular mils) Because conductors are stranded, the equivalent radius must be provided by the manufacturer. In tables this value is known as the GMR and is usually expressed in feet.

Line Resistance

Line Resistance, cont’d Because ac current tends to flow towards the surface of a conductor, the resistance of a line at 60 Hz is slightly higher than at dc. Resistivity and hence line resistance increase as conductor temperature increases (changes is about 8% between 25C and 50C) Because ACSR conductors are stranded, actual resistance, inductance and capacitance needs to be determined from tables.

Review of Electric Fields

Gauss’s Law Example Similar to Ampere’s Circuital law, Gauss’s Law is most useful for cases with symmetry. Example: Calculate D about an infinitely long wire that has a charge density of q coulombs/meter. Since D comes radially out inte- grate over the cylinder bounding the wire

Electric Fields The electric field, E, is related to the electric flux density, D, by D =  E where E = electric field (volts/m)  = permittivity in farads/m (F/m)  = o r o = permittivity of free space (8.85410-12 F/m) r = relative permittivity or the dielectric constant (1 for dry air, 2 to 6 for most dielectrics)

Voltage Difference