Type II Projectiles

Type II Projectile Motion Projectile motion in which launch angle is above the horizon and the projectile lands at the same altitude as it was launched. Example: A golf ball driven from the tee box without the use of a tee lands on the green; the green has the same elevation as the tee box.

Type II Projectile Motion For a given initial speed, what angle gives maximum range?

Type II Projectile Motion For a given initial speed, what angle gives maximum range?

Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown

Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0!

Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0! The magnitude of vimpact = the magnitude of vinitial angles are opposite sign

Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0! The magnitude of vimpact = the magnitude of vinitial; angles are opposite sign (below vs. above horizontal) Maximum range is achieved with a 45° angle.

Type II Projectile Motion How do Type II problems differ from Type I problems?

Solving Type II Draw a VELOCITY vector triangle to find the components of the launch velocity Set up x and y lists Solve

Type II Projectile Motion – Sample Problem A golf ball is driven from level ground with an initial velocity of 40 m/s at an angle of 30° above the horizon. Find: Max height of ball’s path b) hangtime c) range d) impact velocity