Welcome to Precalculus! Get notes out. Get homework out Write “I Can” statements I can: Evaluate trigonometric functions of acute angles, and use a calculator to evaluate trigonometric functions. Use the fundamental trigonometric identities. Use trigonometric functions to model and solve real-life problems.

Focus and Review Attendance Questions from yesterday’s work

Right Triangle Trigonometry 4.3 Copyright © Cengage Learning. All rights reserved.

Objectives Evaluate trigonometric functions of acute angles, and use a calculator to evaluate trigonometric functions. Use the fundamental trigonometric identities. Use trigonometric functions to model and solve real-life problems.

The Six Trigonometric Functions

The Six Trigonometric Functions This section introduces the trigonometric functions from a right triangle perspective. Consider a right triangle with one acute angle labeled  , as shown below. Relative to the angle , the three sides of the triangle are the hypotenuse, the opposite side (the side opposite the angle  ), and the adjacent side (the side adjacent to the angle  ).

The Six Trigonometric Functions Using the lengths of these three sides, you can form six ratios that define the six trigonometric functions of the acute angle . sine cosecant cosine secant tangent cotangent

The Six Trigonometric Functions In the following definitions, it is important to see that 0 <  < 90 ( lies in the first quadrant) and that for such angles the value of each trigonometric function is positive.

Memory Aid  

The Six Trigonometric Functions In the following definitions, it is important to see that 0 <  < 90 ( lies in the first quadrant) and that for such angles the value of each trigonometric function is positive.

Example 1 – Evaluating Trigonometric Functions Use the triangle in Figure 4.20 to find the values of the six trigonometric functions of . Solution: By the Pythagorean Theorem, (hyp)2 = (opp)2 + (adj)2, it follows that Figure 4.20

Example 1 – Solution So, the six trigonometric functions of  are cont’d So, the six trigonometric functions of  are

Example 1 – Solution cont’d

Practice Problems 7, 8, 13, 18

The 45-45-90 Triangle and the 30-60-90 Triangle

The Six Trigonometric Functions In Example 1, you were given the lengths of two sides of the right triangle, but not the angle . Often, you will be asked to find the trigonometric functions of a given acute angle . To do this, construct a right triangle having  as one of its angles.

The 45-45-90 Triangle  

The 45-45-90 Triangle  

The 45-45-90 Triangle      

The 45-45-90 Triangle  

The 45-45-90 Triangle      

The 45-45-90 Triangle        

The 45-45-90 Triangle  

The 30-60-90 Triangle  

The 30-60-90 Triangle  

The 30-60-90 Triangle     2 2       1 1

The 30-60-90 Triangle   2   1

The 30-60-90 Triangle  

The Six Trigonometric Functions

The Six Trigonometric Functions  

The Six Trigonometric Functions  

Applications Involving Right Triangles

Applications Involving Right Triangles Many applications of trigonometry involve a process called solving right triangles. In this type of application, you are usually given one side of a right triangle and one of the acute angles and are asked to find one of the other sides, or you are given two sides and are asked to find one of the acute angles. In Example 8, the angle you are given is the angle of elevation, which represents the angle from the horizontal upward to an object.

Applications Involving Right Triangles Find the measure of each side indicated. Round to the nearest tenth. A B     A C 13   B   C

Applications Involving Right Triangles Find the measure of each angle indicated. Round to the nearest tenth.     3 200 yd 400 yd 3

Applications Involving Right Triangles In the following example, the angle you are given is the angle of elevation, which represents the angle from the horizontal upward to an object. In other applications you may be given the angle of depression, which represents the angle from the horizontal downward to an object. (See next slide.)

Applications Involving Right Triangles

Example 8 – Using Trigonometry to Solve a Right Triangle A surveyor is standing 115 feet from the base of the Washington Monument, as shown in figure below. The surveyor measures the angle of elevation to the top of the monument as 78.3. How tall is the Washington Monument?

Example 8 – Solution From the figure, you can see that where x = 115 and y is the height of the monument. So, the height of the Washington Monument is y = x tan 78.3  115(4.82882)  555 feet.

Applications Involving Right Triangles  

Cofunctions of Complimentary Angles In the box, note that sin 30 = = cos 60. This occurs because 30 and 60 are complementary angles. In general, it can be shown from the right triangle definitions that cofunctions of complementary angles are equal. That is, if  is an acute angle, then the following relationships are true. sin(90 –  ) = cos  cos(90 –  ) = sin  tan(90 –  ) = cot  cot(90 –  ) = tan  sec(90 –  ) = csc  csc(90 –  ) = sec 

Cofunctions of Complimentary Angles  

Cofunctions of Complimentary Angles          

Cofunctions of Complimentary Angles  

Cofunctions of Complimentary Angles Equivalent statements can be derived relating cosine, cotangent, and cosecant to sine, tangent, and secant, respectively. Therefore, the following cofunction relationships hold: sin(90 –  ) = cos  cos(90 –  ) = sin  tan(90 –  ) = cot  cot(90 –  ) = tan  sec(90 –  ) = csc  csc(90 –  ) = sec 

Trigonometric Identities

Trigonometric Identities  

Cofunctions of Complimentary Angles        

Trigonometric Identities In trigonometry, a great deal of time is spent studying relationships between trigonometric functions (identities).

Important Note You need to memorize all of the Fundamental Trigonometric Identities found on page 282 verbatim. Stating these identities will be included on all of the quizzes and tests for the remainder of Chapter 4.

Example 5 – Applying Trigonometric Identities Let  be an acute angle such that sin  = 0.6. Find the values of (a) cos  and (b) tan  using trigonometric identities. Solution: a. To find the value of cos , use the Pythagorean identity sin2  + cos2  = 1. So, you have (0.6)2 + cos2  = 1 cos2  = 1 – (0.6)2 cos2  = 0.64 Substitute 0.6 for sin . Subtract (0.6)2 from each side. Simplify.

Example 5 – Solution cont’d cos  = cos  = 0.8. b. Now, knowing the sine and cosine of , you can find the tangent of  to be Use the definitions of cos  and tan , and the triangle shown in Figure 4.23, to check these results. Extract positive square root. Simplify. = 0.75. Figure 4.23

Example 6 – Applying Trigonometric Identities  

Independent Practice Section 4.3 (page 286) # 1 – 4 (vocabulary), 5, 6, 10, 13, 14, 15, 16, 17, 19, 31 – 34, 41, 42, 45, 46, 47, 49, 51, 53, 55, 57, 59, 61, 63, 66, 69, 71, 73 Extra Credit: # 76 (5 points on next quiz) IMPORTANT NOTE: Problem 65 has been changed to Problem 66.