Using the COSINE Rule
Quick starter … answer these cos(x) = 6 ÷ 9 = 2/3 x = cos-1(2/3) x = 48.19° 62 + b2 = 92 b2 = 81 - 36 b = √45 b = 6.71cm H 9cm 9cm O b Q 1 Q 2 x° 6cm 6cm A cos(33°) = 11.3 ÷ y y = 11.3 ÷ cos(33°) y = 13.47cm A O 11.3 cm Q 3 33° y H
From the formula sheet on exams … Seems to combine Pythagoras and cosine formula
The Cosine Rule DOESN’T HAVE TO BE RIGHT-ANGLED TRIANGLE
Eg 1 B y (a) 7.9 cm (c) 116° C A 6.5 cm (b) y2 = 6.52 + 7.92 – 2 x 6.5 x 7.9 x cos(116°) y2 = 42.25 + 62.41 – 102.7 x (-0.438371146…) y = √149.6807168… = 12.23 cm (2dp)
Eg 2 B 12 cm (a) 6 cm (c) y° C A 8 cm (b) 122 = 82 + 62 – 2 x 8 x 6 x cos(y°) 144 = 100 – 96 x cos(y°) (-100) 44 = (– 96) x cos(y°) 44 = cos(y°) 96 ÷(-96) - y = cos-1( 44 ) = 117.28° (2dp) 96 -
cos (90°) = 0 Remember … y = cos (θ) y 1 0.5 -0.5 -1 θ -360 -270 -180 -90 0 90 180 270 360 y 1 0.5 -0.5 -1 cos (90°) = 0 Remember … y = cos (θ)
62 + b2 = 92 b2 = 81 - 36 b = √45 b = 6.71cm 9cm b Q 1 6cm C 92 = b2 + 62 – 2 x b x 6 x cos(90°) 9cm (a) b 81 = b2 + 36 – 12 x b x 0 (b) 81 = b2 + 36 B A 6cm b2 = 81 - 36 b = √45 b = 6.71cm (c)