The focusing of a parallel beam of light to a focus

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Presentation transcript:

The focusing of a parallel beam of light to a focus is reversible:

3 easy to trace lines can help locate the image formed by a lens q q M= p With the magnification,

1 2 3 4 5 f The ray entering this diverging lens, parallel to its axis, exits the other side following which ray? 5

The divergence by a concave lens should be reversible as well!

1 2 3 f 4 Which ray entering 5 the diverging lens exits the other side parallel to its axis? 5

3 easy to trace lines can help locate the image formed by a lens q f q M= p With the magnification still,

= + 1 f 1 p 1 q When viewing objects by eye, which variable(s) = + When viewing objects by eye, which variable(s) of the lens equation must always remain fixed? the focal length, f the object distance, p the image distance, q (4)both f and p (5)both f and q (6)both p and q

For everyone there is a NEAR POINT, the closest position you can focus on f Any closer, the lens cannot accommodate. The eye strains to hold f this small.

must be proportional to 1 f 1 p 1 q = + ho q p The retinal image size must be proportional to the focal length, f of the lens the object distance, p the image distance, q (4)the object size, ho (5)both p and q (6)both p and ho

ho   q

A jeweler whose near point is 40 cm, examines a diamond with a small magnifying glass. The lens has a focal length of 5 cm and the image is -185 cm from the lens. Determine the angular magnification. Where should the image be located for viewing without eyestrain? What is the magnification then? c)What maximum magnification is possible?

Determine the angular magnification. A jeweler whose near point is 40 cm, examines a diamond with a small magnifying glass. The lens has a focal length of 5 cm and the image is -185 cm from the lens. Determine the angular magnification. b)Where should the image be located for viewing without eyestrain? What is the magnification then? c)What maximum magnification is possible? Want q=- , so 1/q = 0  When q=-N 

2 2 Directed away from the focus on far side. Some answers: 2 Directed away from the focus on far side. 2 Directed toward the focus on near side. (3) the image distance, q