Problem Explication Amber Gipson Erin Key Kelly Lee Amy Ozley

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Presentation transcript:

Problem Explication Amber Gipson Erin Key Kelly Lee Amy Ozley

#64 Calculate ∆H° for each of the following reactions using the data in Appendix 4: 4Na(s) + O2(g)  2Na2O(s) 2Na(s) +2H2O(l)  2NaOH(aq) + H2(g) 2Na(s) + CO2(g)  NA2O(s) + CO(g) Explain why a water or carbon dioxide fire extinguisher might not be effective in putting out a sodium fire.

Equation: *Product - Reactant = ΔH* 4Na(s) + O2(g)  2Na2O(s) 4 (0) + 0 2(-416) -832 – 0 ΔH= -832 EXOTHERMIC!

Equation: *Product - Reactant = ΔH* 2Na(s) +2H2O(l)  2NaOH(aq) + H2(g) 0 + 2(-286) 2(-470) + 0 -940 - (-572) ΔH= -368 EXOTHERMIC!

Equation: *Product - Reactant = ΔH* 2Na(s) + CO2(g)  NA2O(s) + CO(g) 2 (0) + -395.5 -416 + -110.5 -526.5 - -393.5 ΔH= -133.0 EXOTHERMIC!

Answer: The reaction of water and sodium release heat Answer: The reaction of water and sodium release heat. The reaction of carbon dioxide and sodium release heat also. They are both exothermic reactions.