I. Energy and Work Energy Work Conservation of Energy

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Presentation transcript:

I. Energy and Work Energy Work Conservation of Energy Ch. 5&6 - Energy I. Energy and Work Energy Work Conservation of Energy

A. Energy ENERGY THERMAL The ability to cause change. MECHANICAL internal motion of particles ENERGY MECHANICAL NUCLEAR motion of objects changes in the nucleus ELECTRICAL joules (J) CHEMICAL motion of electric charges bonding of atoms

A. Energy Kinetic Energy (KE) energy in the form of motion depends on mass and velocity 80 km/h 50 km/h Which has the most KE? Which has the least KE? 80 km/h truck 50 km/h motorcycle

A. Energy Potential Energy (PE) stored energy depends on position or configuration of an object Which boulder has greater gravitational PE? What other ways can an object store energy?

W = Fd B. Work Work transfer of energy through motion force exerted through a distance W = Fd W: work (J) F: force (N) d: distance (m) 1 J = 1 N·m Distance must be in direction of force!

B. Work Brett’s backpack weighs 30 N. How much work is done on the backpack when he lifts it 1.5 m from the floor to his back? GIVEN: F = 30 N d = 1.5 m W = ? WORK: W = F·d W = (30 N)(1.5 m) W = 45 J F W d

d B. Work W F GIVEN: m = 40 kg d = 1.4 m - during d = 2.2 m - after A dancer lifts a 40 kg ballerina 1.4 m in the air and walks forward 2.2 m. How much work is done on the ballerina during and after the lift? GIVEN: m = 40 kg d = 1.4 m - during d = 2.2 m - after W = ? WORK: W = F·d F = m·a F =(40kg)(9.8m/s2)=392 N W = (392 N)(1.4 m) W = 549 J during lift No work after lift. “d” is not in the direction of the force. F W d

C. Conservation of Energy Law of Conservation of Energy Energy may change forms, but it cannot be created or destroyed under ordinary conditions. EX: PE  KE mechanical  thermal chemical  thermal

C. Conservation of Energy PE  KE View pendulum animation. View roller coaster animation.

C. Conservation of Energy Mechanical  Thermal View rolling ball animations. View skier animation.

II. Thermal Energy Temperature Thermal Energy Heat Transfer Ch. 5 - Energy II. Thermal Energy Temperature Thermal Energy Heat Transfer

A. Temperature Temperature measure of the average KE of the particles in a sample of matter

B. Thermal Energy Thermal Energy the total energy of the particles in a material KE - movement of particles PE - forces within or between particles due to position depends on temperature, mass, and type of substance

B. Thermal Energy A B Which beaker of water has more thermal energy? B - same temperature, more mass 200 mL 80ºC A 400 mL B

C. Heat Transfer Heat thermal energy that flows from a warmer material to a cooler material Like work, heat is... measured in joules (J) a transfer of energy

C. Heat Transfer A B Why does A feel hot and B feel cold? Heat flows from A to your hand = hot. Heat flows from your hand to B = cold. 80ºC A 10ºC B

C. Heat Transfer Specific Heat (Cp) amount of energy required to raise the temp. of 1 kg of material by 1 degree Kelvin units: J/(kg·K) or J/(kg·°C)

C. Heat Transfer Which sample will take longer to heat to 100°C? 50 g Al 50 g Cu Al - It has a higher specific heat. Al will also take longer to cool down.

Q = m  T  Cp C. Heat Transfer Q: heat (J) m: mass (kg) T: change in temperature (K or °C) Cp: specific heat (J/kg·K) – Q = heat loss + Q = heat gain T = Tf - Ti

C. Heat Transfer heat gained = heat lost Calorimeter Coffee cup Calorimeter Calorimeter device used to measure changes in thermal energy in an insulated system, heat gained = heat lost

C. Heat Transfer GIVEN: WORK: m = 32 g Q = m·T·Cp Ti = 60°C A 32-g silver spoon cools from 60°C to 20°C. How much heat is lost by the spoon? GIVEN: m = 32 g Ti = 60°C Tf = 20°C Q = ? Cp = 235 J/kg·K WORK: Q = m·T·Cp m = 32 g = 0.032 kg T = 20°C - 60°C = – 40°C Q = (0.032kg)(-40°C)(235J/kg·K) Q = – 301 J

C. Heat Transfer GIVEN: WORK: m = 230 g Q = m·T·Cp Ti = 12°C How much heat is required to warm 230 g of water from 12°C to 90°C? GIVEN: m = 230 g Ti = 12°C Tf = 90°C Q = ? Cp= 4184 J/kg·K WORK: Q = m·T·Cp m = 230 g = 0.23 kg T = 90°C - 12°C = 78°C Q = (0.23kg)(78°C)(4184 J/kg·K) Q = 75,061 J