How to Solve Physics Problems

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Presentation transcript:

How to Solve Physics Problems

7 Step Guide to Problem Solving Put your calculator down! Step #2 Read the problem thoroughly. Key into words like: constant, from rest, accelerating, coming to a stop

7 Step Guide to Problem Solving A. Identify Known Variables, fill in the chart Variable Value Vi (Initial Velocity) Vf (Final Velocity) a (acceleration) ∆X (Change in Distance) ∆t (time interval) ∆D

7 Step Guide to Problem Solving B. Determine what you are solving for? Variable that you are being asked to find. C. Draw a sketch of the scenario.

7 Step Guide to Problem Solving Step #4: Pick an Equation

7 Step Guide to Problem Solving Step #5: Rearrange the equation to solve for desired variable EX: We selected this equation: Rearrange to solve for a.

7 Step Guide to Problem Solving Step #6: Solve Start plugging in values for known variables. Step #7: Check your answer 1. Does the answer make sense? 2. Are the units correct?

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #2: Key terms

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #3: Table Solving for t Variable Value Vi Vf a ∆X ∆t 25 m/s ? 100 m ?

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #4: Select equation Variable Value Vi Vf 25.0 m/s a ? ∆X 100.0 m ∆t

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #5: Rearrange Equation

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #6: Solve

Example Problems A car starts from rest and accelerates to a velocity of 25.0 m/s over a distance of 100.0 meters. How long did it take the car to reach 25.0 m/s? Step #7: Check 1. Is the answer reasonable? 2. Are the units correct?

Example Problems A ball is thrown straight up in the air with an initial velocity of 10.0 m/s and then caught at the same height 2.04 seconds later. What is the acceleration of the ball after it leaves the throwers hand? How high will the ball go up before falling back down?

Example Problems A ball is thrown straight up in the air with an initial velocity of 10.0 m/s and then caught at the same height 2.04 seconds later. Step #2: Key Terms Step #3: Table Variable Value Vi Vf a ∆X ∆t 0 m/s -10.0 m/s ? ? WHAT? Why 1.02 sec? 1.02 s

Example Problems A ball is thrown straight up in the air with an initial velocity of 10.0 m/s and then caught at the same height 2.04 seconds later. What is the acceleration of the ball after it leaves the throwers hand? Step #4: Select an Equation Step #5: No need to rearrange

Example Problems Step #6: Solve Variable Value Vi 0 m/s Vf -10.0 m/s a ∆X ? ∆t 1.02 s For problems that occur in the air, the acceleration is due to gravity and is always -9.81 m/s -9.81 m/s2 What is the acceleration of the ball after it leaves the throwers hand?

Example Problems b) How high will the ball go up before falling back down? Ans: -5.10 m from the math, correct answer is 5.10 m based on the question