Hypothesis Testing and Estimation

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Presentation transcript:

Hypothesis Testing and Estimation Chapter 5 : Hypothesis Testing and Estimation

There are two main purposes in statistics; (Chapter 1 & 2)  Organization & ummarization of the data [Descriptive Statistics] (Chapter 5)  Answering research questions about some population parameters [Statistical Inference]   Statistical Inference (1) Hypothesis Testing: Answering questions about the population parameters            (2) Estimation: Approximating the actual values of Parameters; Ø    Point Estimation Ø    Interval Estimation (or Confidence Interval)

We will consider two types of population parameters:  (1) Population means (for quantitative variables): μ =The average (expected) value of some quantitative variable.   Example: The mean life span of some bacteria. The income mean of government employees in Saudi Arabia. (2) Population proportions (for qualitative variables)

Example: The proportion of Saudi people who have some disease. The proportion of smokers in Riyadh The proportion of females in Saudi Arabia Estimation of Population Mean :-  Population (distribution)  Population mean =μ Population Variance Random of size Sample n Sample mean Sample Variance

We are interested in estimating the mean of a population (I)Point Estimation:  A point estimate is a single number used to estimate (approximate) the true value of . Draw a random sample of size n from the population: is used as a point estimator of .

(II)Interval Estimation:  An interval estimate of μ is an interval (L,U) containing the true value of μ “ with probability “   is called the confidence coefficient L = lower limit of the confidence interval U= upper limit of the confidence interval Draw a random sample of size n from the population .

Result:   If is a random sample of size n from a distribution with mean μ and variance , then: A 100% confidence interval for is :  (i) if is known: OR (ii) if is unknown. OR

Example: [point estimate of is ] Variable = blood glucose level (quantitative variable) Population = diabetic ketoacidosis patients in Saudi Arabia of age 15 or more parameter = μ= the average blood glucose level (large) ( is unknown) (i) Point Estimation: We need to find a point estimate for μ . is a point estimate for μ . (ii) Interval Estimation (Confidince Interval): We need to find 90% confidence interval for μ .

90% = 100% 90% confidence interval for μ is: or or

we are 90% confident that the mean μ lies in (25.71,26.69) or 25.72 < μ < 26.69 5.4.Estimation for a population proportion:- The population proportion is  (π is a parameter) where number of elements in the population with a specified characteristic “A” N = total number of element in the population (population size) The sample proportion is

number of elements in the sample with the same characteristic “A” (p is a statistic) where number of elements in the sample with the same characteristic “A” n = sample size Result: For large sample sizes , we have Estimation for π :  (1) Point Estimation: A good point estimate for π is p.   (2) Interval Estimation (confidence interval):   A confidence interval for π is

or

Example 5.6 (p.156) variable = whether or not a women is obese (qualitative variable) population = all adult Saudi women in the western region seeking care at primary health centers parameter = π = The proportion of women who are obese  n = 950 women in the sample n (A) = 611 women in the sample who are obese

is the proportion of women who are obese in the sample.  (1) A point estimate for π is p = 0.643   (2) We need to construct 95% C.I. about π . 95% C.I. about π is

or or or We can 95% confident that the proportion of obese women, π , lies in the interval (0.61,0.67) or 0.61 < π < 0.67