Spatial distribution of acoustic radiation force modal excitation from focused ultrasonic transducers in air Acoustical Society of America Meeting Boston,

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Presentation transcript:

Spatial distribution of acoustic radiation force modal excitation from focused ultrasonic transducers in air Acoustical Society of America Meeting Boston, MA June 26, 2017 Thomas Huber, Ian McKeag, William Riihiluoma Physics Department, Gustavus Adolphus College Christopher Niezrecki, Songmao Chen, Peter Avitabile Mechanical Engineering, University of Massachusetts, Lowell

Introduction Overview Acoustic Radiation Force for Modal Excitation in Air Excitation using two transducers in X-Focal arrangement Excitation using single transducer with amplitude modulation Utilization to Determine Ultrasound Distribution from Transducer Excitation using confocal transducer Conclusions

Acoustic/Ultrasound Radiation Force First derived by Rayleigh in early 1900’s Extended by Brillouin and Langevin Westervelt, JASA, 23, 312 (1951) Acoustic wave carries momentum Details of magnitude of force depends on whether there is net flow of fluid in direction of wave propagation Different authors write radiation pressure in different forms <E> is mean energy density, I is intensity, P is acoustic pressure Key Result: Radiation Force Proportional to Square of Acoustic Pressure

Difference Frequency = P1P2cos[(ω1 - ω2)t] fd = (f1 - f2) Acoustic Radiation Force At 500 kHz to Produce 2kHz Excitation f1 – Lower Sideband (For this case 499 kHz ) f2 – Upper Sideband (For this case 501 kHz) fc - Carrier or Central Frequency (500 kHz) fd - Difference (Excitation) Frequency (501 – 499 kHz = 2 kHz) 85 90 95 100 105 110 115 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Frequency [Hz] Amplitude Dual Pair Frequencies fd 499 kHz fc= 500 kHz 501 kHz f1 f2 P = P1cos(ω1t) + P2cos(ω2t) ; ω1=2πf1 & ω2=2πf2 Radiation force proportional to P2 Radiation force Components DC Component = ½(P12+P22) High Frequency =P1P2cos[(ω1+ω2)t]+ ½P12cos(2ω1t)+½P22cos(2ω2t) Difference Frequency = P1P2cos[(ω1 - ω2)t] fd = (f1 - f2)

Questions to be addressed: Best method for applying ultrasound? Benefits of using Acoustic Radiation Force for Modal Excitation Non-Contact and Non Electrical Actuation Essentially no driver resonances, mass loading, and excitation of fixture modes Can have focused ultrasound; focal spot of about 2 mm diameter Questions to be addressed: Best method for applying ultrasound? What is Force Distribution?

Microphone Cantilever X-Focal: Using Two Separate Ultrasound Transducers Two transducers driven with separate function generators and amps For example: One transducer at 501 kHz and other at 499 kHz Each transducer has focal spot size ~ 2mm in diameter Frequencies combined only in overlap area of the transducers Transducers Mounted on Translation Stage Monitor excitation using Microphone and Clamped/Free Cantilever Microphone Cantilever

X-Focal: Results obtained from Microphone Microphone width of about 6mm (dotted yellow lines), Ultrasound focal diameter of about 2mm Narrow excitation region with amplitude nearly independent of frequency (Note that y-axis is log scale) Frequency response is flat to within about a factor of 2 from 0.4 kHz to 80 kHz (many additional frequencies tested) Similar results from different transducers: Microacoustic Instruments (Capacitive Micromachined), Ultran (Piezoelectrc) X-Focal: Results obtained from Microphone

Cantilever with 447 Hz fundamental frequency Cantilever with 447 Hz fundamental frequency. Width of about 6mm, Ultrasound about 2mm Emit ultrasound difference frequency at cantilever resonances: Narrow excitation region Amplitude and distribution variations at high frequency because of modal shapes for high-frequency resonances Similar results from different pairs of ultrasound transducers X-Focal: Results obtained from Cantilever (Monitored using a Laser Vibrometer) Conclusion: Using a pair of ultrasound transducers in X-Focal arrangement is effective for highly focused, non-contact modal excitation over wide range of frequencies Downside: Requires pair of transducers and amplifiers, and careful beam alignment

fd Single Transducer: Amplitude Modulated Signal 85 90 95 100 105 110 115 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Frequency [Hz] Amplitude Dual Pair Frequencies fd 499 kHz fc= 500 kHz 501 kHz Dual sideband, suppressed carrier AM modulated signal Requires only one power amplifier and transducer Does not require alignment of two overlapping transducers Single Transducer: Amplitude Modulated Signal Message Cycle Carrier Cycle Excitation Signal

AM Excitation: Results obtained for 447 Hz Fundamental Resonance of Cantilever Cantilever (6 mm across) vibration monitored at one point with laser Doppler vibrometer As ultrasound focal spot moves onto the edge, the response acts as a 2D integral of the ultrasound distribution on the cantilever To obtain the ultrasound distribution from this data, must take the derivative

Low-noise Lanczos differentiation (N=9) AM Excitation: Determination of line-spread function by moving transducer Low-noise Lanczos differentiation (N=9) Each point in the derivative represents the relative sum of a slice of the ultrasound spot distribution.

Each point is integral of slice of ultrasound distribution Using Manufacturer’s Pressure Distribution to obtain line-spread function Radial pressure distribution (slice through middle) from manufacturer rotated to create surface plot of distribution. Each point is integral of slice of ultrasound distribution Integrated pressure distribution Integrate slices through the 2-d distribution

Results: Good agreement between measured and manufacturer’s line-spread function Red is Measured Line Spread (Vibration as transducer moves across edge) Magenta is Integrated Pressure Distribution (from manufacturer data) Blue is Integrated Squared Pressure Distribution (because radiation force proportional to pressure squared) Agreement between blue and red curves shows that transducer’s ultrasound distribution can be measured with vibrometer as transducer is moved through cantilever edge at 447 Hz

Amplitude Modulation: Results obtained from Microphone Microphone width of about 6mm (dotted yellow lines), Ultrasound focal diameter of about 2mm Below ~ 3kHz, narrow excitation region Higher frequency: Very unexpected, broad frequency distribution! Amplitude Modulation: Results obtained from Microphone

“Normal” Sound from Circular Aperture of Diameter D (Ultrasound Transducer) First Diffraction Minima at angle Sin-1 (1.22λ/D) = Sin-1 (1.22 c / f D) Higher Frequency : Smaller angle for first diffraction minima For difference frequency above ~4kHz, “normal sound” dominates acoustic radiation force What is the origin of this “normal sound” production (Generator, Amplifier, Transducer, air?)

Amplitude Modulation: Results for different transducers Microphone width of about 6mm (dotted yellow lines), Ultrasound focal diameter of about 2mm Compare different piezo transducers (1” and 2” Ultran), capacitive micromachined transducer with X-Focal This “normal sound” production effect appears to be real, and is not just a defective transducer!

X Amplitude Modulation: Mixing in amplifier or function generator Could there be mixing within the amplifier? Remove power amplifier: output from function generator directly into transducer Microphone signal two orders of magnitude smaller; unfortunately similar broad distribution. Occurs with different transducers and function generators Message Cycle Carrier Cycle Excitation Signal X

Excitation using 600 kHz Dual-Element Confocal Transducer Separate function generators and amplifiers for confocal disk and ring Common method used for ultrasound excitation in water-based experiments at different labs Observe same pattern: narrow distribution at low difference frequency and broad distribution at high frequency Not amplifier crosstalk: switching same generator/amplifiers to X-Focal pair gives narrow distribution Something to do with airborne excitation instead of water?

For More Info Conclusions Acknowledgements Acoustic radiation force can be used for Non-Contact Modal Excitation X-Focal pair can produce localized excitation with wide bandwidth and flat response Single AM transducer and confocal transducer seem to produce “Normal Sound” with a broad distribution when difference frequency exceeds about 4 kHz No clear answers on origin of this effect: further studies needed Acknowledgements Gustavus Acoustics Lab Students including: Will Doebler, Mikaela Algren, and Cole Raisbeck This material is based upon work supported by the National Science Foundation under Grant Nos. 1300591 and 1635456 Any opinions, findings, and conclusions or recommendations expressed in this material are those of the authors and do not necessarily reflect the views of the National Science Foundation. For More Info