Example: a parallel plate capacitor has an area of 10 cm2 and plate separation 5 mm. 300 V is applied between its plates. If neoprene is inserted between.

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Example: a parallel plate capacitor has an area of 10 cm2 and plate separation 5 mm. 300 V is applied between its plates. If neoprene is inserted between its plates, how much charge does the capacitor hold. A=10 cm2 300 V =6.7 V=300 V d=5 mm

The calculation is the same, except replace 6.7 by 1. Example: how much charge would the capacitor on the previous slide hold if the dielectric were air? A=10 cm2 The calculation is the same, except replace 6.7 by 1. 300 V Or just divide the charge on the previous page by 6.7 to get… =1 V=300 V d=5 mm

Visit howstuffworks to read about capacitors and learn their advantages/disadvantages compared to batteries! V=0 Conceptual Example A capacitor connected as shown acquires a charge Q. V While the capacitor is still connected to the battery, a dielectric material is inserted. V Will Q increase, decrease, or stay the same? Why?

Back to our Example: find the energy stored in the capacitor. A=10 cm2 300 V =6.7 V=300 V d=5 mm

Example: the battery is now disconnected Example: the battery is now disconnected. What are the charge, capacitance, and energy stored in the capacitor? A=10 cm2 The charge and capacitance are unchanged, so the voltage drop and energy stored are unchanged. 300 V =6.7 V=300 V d=5 mm

Example: the dielectric is removed without changing the plate separation. What are the capacitance, charge, potential difference, and energy stored in the capacitor? A=10 cm2 =6.7 V=? d=5 mm V=300 V d=5 mm

Example: the dielectric is removed without changing the plate separation. What are the capacitance, charge, potential difference, and energy stored in the capacitor? A=10 cm2 The charge remains unchanged, because there is nowhere for it to go. V=? d=5 mm

Example: the dielectric is removed without changing the plate separation. What are the capacitance, charge, potential difference, and energy stored in the capacitor? A=10 cm2 Knowing C and Q we can calculate the new potential difference. V=? d=5 mm

Example: the dielectric is removed without changing the plate separation. What are the capacitance, charge, potential difference, and energy stored in the capacitor? A=10 cm2 V=2020 V d=5 mm

Huh?? The energy stored increases by a factor of ?? Sure. It took work to remove the dielectric. The stored energy increased by the amount of work done.

A “toy” to play with… http://phet.colorado.edu/en/simulation/capacitor-lab (You might even learn something.)