2.3 Geometrical Application of Calculus

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Presentation transcript:

2.3 Geometrical Application of Calculus Higher Derivatives Just Differentiate again and again and again.

2.3 Geometrical Application of Calculus 1. Find the first 4 derivatives of f(x) = x3 - 4x2 + 3x -2 f’(x) = 3x2 - 8x +3 f’’(x) = 6x - 8 f’’’(x) = 6 f’’’’(x) = 0

2.3 Geometrical Application of Calculus Rules for Differentiation If f(x) = xn then … f’(x) = nxn-1 and If f(x) = axn then … f’(x) = anxn-1

Function of a Function Rule 2.3 Geometrical Application of Calculus Rules for Differentiation Function of a Function Rule If y = (u)n then … or

2.3 Geometrical Application of Calculus Rules for Differentiation Product Rule If y = uv then …

2.3 Geometrical Application of Calculus Rules for Differentiation Quotient Rule If y = u then … v