Gradient and Area Under Curve Grade 9 Gradient and Area Under Curve Calculate or estimate gradients of graphs and areas under graphs (including quadratic and other non- linear) interpreting results in cases such as distance- time, velocity-time and financial contexts If you have any questions regarding these resources or come across any errors, please contact helpful-report@pixl.org.uk

Lesson Plan Lesson Overview Progression of Learning Objective(s) Calculate or estimate gradients of graphs and areas under graphs (including quadratic and other non-linear) interpreting results in cases such as distance-time, velocity-time and financial contexts Grade 9 Prior Knowledge Rearranging equations y = mx + c Duration Related to lesson on ‘Gradients and Rates of Change’ – plan to teach together. Content covered here approximate time = 50 minutes Resources Print slides: 20 - 28 Equipment Progression of Learning What are the students learning? How are the students learning? (Activities & Differentiation) Gradient from a linear graph Give students slide 20. Using slide 4 show how gradient is calculated graphically (this should be familiar). Look at the different wordings - but all the same. Students to practice finding the gradients of the lines on slide 5. 10 Gradient from a linear equation Give students slide 21. Demonstrate 2 examples of rearranging into the form y = mx + c. 4 further questions for students to practice. Answers on slide 7. Gradient of a quadratic graph – at a particular point Give students slide 22. Show the initial method of considering points just below and just above the point given. Extend this to drawing a tangent and then finding the gradient of the tangent using the method for linear graphs. Students to complete a further question on slide 10. Then give students slide 23 – contextualised problem. Interpreting gradient and gradients of zero Give students slide 24. Students to complete notes for this section using slides 12 and 13. 5 Velocity time graphs – draw and interpreting Give students slide 25 – students to make notes on this sheet. Teacher can pose additional questions related to the give graph. Give students slide 26 – practice question. Solution on slide 15. Extension questions on slide 16. Gradients and area under curve in exam questions (from specimen papers) Give students slide 27 and 28. This includes 3 exam questions related to objective. Students to use notes from lesson. Ensure that all steps are shown. Relate to mark scheme to show how the marks are allocated. Next Steps Rates of change Assessment PLC/Reformed Specification/Target 9/Algebra/Gradients and area under curve

Key Vocabulary Gradient Estimate Linear Non-linear Quadratic Velocity

Gradient from a linear graph A linear graph is a straight line graph with an equation which can be written in the form y = mx + c The gradient is ‘m’ and can be found from the graph Change in y Change in x Rise Step y2 – y1 x2 – x1

Find the gradients of these lines: b = 1/3 c = -3 d = 1 e = -2 f = -1/3 g = 5 h = -5 i = 1/5 j = -3/4

Gradient from a linear equation Rearrange this equation to make y the subject and identify the gradient of this linear graph. 2y - 5x + 8 = 0 2y = 5x - 8 y = x - 4 Gradient =

Gradient from a linear equation Rearrange this equation to make y the subject and identify the gradient of this linear graph. PRACTICE 4x – 2y = 12 y – 4x = 8 y – 8 = -1/2(x + 4) 3x – 4y = 8 3y + 4x - 9 = 0 y = 2x - 6 3y = -4x + 9 y = x + 3 y = 4x + 8 y = -1/2x + 6 Gradient = y = 3/4x -2

Gradient of a quadratic graph This is a quadratic graph with equation y = x2 y We can estimate the gradient of this graph at the point (2,4) by considering points just above and just below x= 2 ie x = 2.1 and x = 1.9 Between x = 2.1 and x = 1.9 Gradient = 4.41 – 3.61 2.1 – 1.9 x = 4 We can do this more efficiently and accurately by drawing a tangent at the point (2,4) and then finding the gradient of this line.

Gradient of a quadratic graph y 4 1 = 4 x We can do this more efficiently and accurately by drawing a tangent at the point (2,4) and then finding the gradient of this line.

Gradient of a quadratic graph This is a quadratic graph with equation y = x2- 3x + 1 x y Estimate the gradient of this graph at the point (0,1) -3 1 = -3

Gradient of a quadratic graph - Contextualised 2 A container is filled with water in 5 seconds. The graph shows the depth of the water, d cm, at the time, t seconds. Use the graph to estimate the rate at which the depth of water is increasing at 3 seconds. 8 8 2 = 4 Note that exam mark schemes will allow for some degree of error (3.5 – 4.5 in this case) 4

Interpreting gradient In this conversion graph the gradient is 2. This means for every 1 unit of x, you need 2 units of y or the value of y is double the value of x. Y axis X axis

Gradients of zero x = -8/3 y At these points on the graph the gradient is zero (flat) x x = 0

Velocity time graphs The gradient of a velocity-time graph represents acceleration or deceleration at that point. The units are m/s-2 The area under a velocity-time graph represents the distance travelled. The units here are metres. This can be estimated by splitting the area under the graph into sections, calculating each one and then adding them together. 0 1 2 3 4 5 6 7 8 9

Velocity time graphs - Practice A toy car is placed on the floor of a sports hall. It moves in a straight line starting from rest. It travels with constant acceleration for 4 seconds reaching a velocity of 5m/s. It then slows down with constant deceleration of 1m/s2 for 2 seconds. It then hits a wall and stops. Draw the velocity – time graph Work out the total distance travelled by the toy car 0.5 (4 x 5) + 0.5 (5 + 3) x 2 = 18

Problem Solving and Reasoning Show how points on a line all have the same gradient between them. Convince me that parallel lines have the same gradient. Demonstrate that if a gradient is m then a perpendicular to that line will have a gradient of -1/m.

Exam Question – Specimen Papers

Exam Question – Specimen Papers

Exam Question – Specimen Papers

Gradient from a linear graph Student Sheet 1

Gradient from a linear equation DEMO PRACTICE 2y - 5x + 8 = 0 4x – 2y = 12 y – 4x = 8 y – 8 = -1/2(x + 4) 3x – 4y = 8 3y + 4x - 9 = 0 Student Sheet 2

Gradient of a quadratic graph This is a quadratic graph with equation y = x2 x y Student Sheet 3

Gradient of a quadratic graph - Contextualised A container is filled with water in 5 seconds. The graph shows the depth of the water, d cm, at the time, t seconds. Use the graph to estimate the rate at which the depth of water is increasing at 3 seconds. Student Sheet 4

Interpreting gradient Gradients of zero Y axis X axis Student Sheet 5

Velocity time graphs 0 1 2 3 4 5 6 7 8 9 Student Sheet 6

Velocity time graphs - Practice A toy car is placed on the floor of a sports hall. It moves in a straight line starting from rest. It travels with constant acceleration for 4 seconds reaching a velocity of 5m/s. It then slows down with constant deceleration of 1m/s2 for 2 seconds. It then hits a wall and stops. Draw the velocity – time graph Work out the total distance travelled by the toy car Student Sheet 7

Exam Question – Specimen Papers Student Sheet 8

Exam Question – Specimen Papers Student Sheet 9