Chapter 10 Whiteboard Review Questions

Slides:



Advertisements
Similar presentations
Chapter 11 Empirical and Molecular Formulas
Advertisements

The Mole Chapter 10.
Section 5: Empirical and Molecular Formulas
The formula for oxalic acid is (COOH)2
Percent Composition and Empirical Formulas
Empirical and Molecular Formulas. Formaldehyde CH 2 O Acetic acid C 2 H 4 O 2 Gylceradehyde C 3 H 6 O 3 40% C; 6.7% H; 53.3% O.
Percent Composition Empirical Formulas and Molecular Formulas Quantification in Chemistry.
Molecular Formulas 1.Find empirical formula 2.Calculate molar mass of empirical formula 3.Molar mass of compound / molar mass of empirical formula (we’ll.
APPLICATIONS OF THE MOLE
Mathematics of Chemical Formulas. Formula Weights.
Molar Mass & Percent Composition
PERCENT COMPOSITION. 2 3 Steps for Determining Chemical Formulas 1. Determine the percent composition of all elements. 2. Convert this information into.
What is a Mole How many socks come in a pair? 2 How many eggs are in a dozen? 12 How many eggs come in a gross? 144 How many pencils come in a ream? 500.
The Mole: A measurement of Matter
The Mole Chapter 11.
Sec. 10.4: Empirical & Molecular Formulas
Percent Composition (Section 11.4) Helps determine identity of unknown compound –Think CSI—they use a mass spectrometer Percent by mass of each element.
Percent Composition and Chemical Formulas Chapter 10.3.
Percent Composition Empirical & Molecular Formulas.
3.10 Determining a Chemical Formula from Experimental Data
Empirical and Molecular Formulas Chapter 10: Section 4.
Molar Mass & Percent Composition. The mass of 1 mole of an element or compound – The mass in grams from the Periodic Table Unit = grams per mole (g/mol)
Percent Composition, Empirical and Molecular Formulas.
11.4 – Empirical and Molecular Formulas Objectives: Explain what is meant by the percent composition of a compound. Determine the empirical and.
Chemistry Handbook Review
Empirical & Molecular Formulas. Percent Composition Def – the percent by mass of each element in a compound Percent by mass = mass of element x 100 mass.
PERCENT COMPOSITION X 100= % mass of element mass of element mass of compound.
Empirical & Molecular Formulas. Percent Composition Determine the elements present in a compound and their percent by mass. A 100g sample of a new compound.
Calculating Empirical and Molecular Formulas. Calculating empirical formula A compound contains 79.80% carbon and 20.20% hydrogen. What is the empirical.
Empirical and Molecular Formulas. CH 2 O CH 3 OOCH = C 2 H 4 O 2 CH 3 O Empirical Formula A formula that gives the simplest whole-number ratio of the.
Mass % and % Composition Mass % = grams of element grams of compound X 100 % 8.20 g of Mg combines with 5.40 g of O to form a compound. What is the mass.
Percentage composition Indicates the relative amount of each element present in a compound.
 Shows the percent by mass of each element in a compound.
Calculating Empirical Formulas
Percent Composition Molar Mass Molar Conversions Empirical Formulas Random
Students type their answers here
Empirical Formulae The empirical formula of a compound is the simplest ratio of the different atoms in it. For example, for ethane (C2H6)it is CH3. You.
Percent Composition - The percent composition of a component in a compound is the percent of the total mass of the compound that is due to that component.
Percent Composition - The percent composition of a component in a compound is the percent of the total mass of the compound that is due to that component.
WHITEBOARD PRACTICE TEST REVIEW. How many molecules of ethane, C 2 H 6 are present in g C 2 H 6 ?
Percent Composition, Empirical and Molecular Formulas.
Percent Composition: Is the percentage of the total mass due to each element within a compound.
Percent Mass, Empirical and Molecular Formulas. Calculating Formula (Molar) Mass Calculate the formula mass of magnesium carbonate, MgCO g +
11.4 – Empirical and Molecular Formulas. Percent Composition Every chemical compound has a definite composition. What law is this referring to? The composition.
UNIT 5B PERCENT COMPOSITION X 100= % mass of element mass of element mass of compound part whole X 100.
Percent Composition. – Compounds are ALWAYS composed of elements in fixed ratios. This is often referred to as the Law of Definite Proportions. – This.
Chapter 10 Chemical Quantities
Determine the empirical formula of the compound containing:
EMPIRICAL FORMULA VS. MOLECULAR FORMULA .
10.3 Percent Composition Def: Relative amounts of the different elements in a compound What percent of water is hydrogen? oxygen?
EMPIRICAL FORMULA AND MOLECULAR FORMULA
Empirical and Molecular Formulas
The Molecular and Empirical Formula Game
Empirical and Molecular Formulas
Empirical and molecular formulas
Molecular Formula Percent Composition.
Empirical and Molecular Formulas
Molecular Formula Percent Composition.
% Formula Mass and % Composition
7.5 – NOTES Molecular Formulas
Empirical and Molecular Formulas
Empirical and Molecular Formulas
Empirical & Molecular Formulas
Mole Calculations Converting number of particles to moles
Empirical and Molecular Formulas
Chapter 11: More on the Mole
7.3 – NOTES Molecular Formulas
Molecular Formula Acetic Acid Glucose Formaldehyde.
Determining a Molecular Formulas:
Presentation transcript:

Chapter 10 Whiteboard Review Questions

What is the percent composition of phosphoric acid (H3PO4) What is the percent composition of phosphoric acid (H3PO4)? (for all 3 elements individually)

What is the percent composition of phosphoric acid (H3PO4) What is the percent composition of phosphoric acid (H3PO4)? (for all 3 elements individually) H = 3.08% P = 31.61% O = 65.31%

Which has the larger percent by mass of sulfur. H2SO3 or H2S2O8?

Which has the larger percent by mass of sulfur. H2SO3 or H2S2O8?

Calcium chloride (CaCl2) is sometimes used as a de-icer Calcium chloride (CaCl2) is sometimes used as a de-icer. Calculate the percent by mass of each element in CaCl2.

Calcium chloride (CaCl2) is sometimes used as a de-icer Calcium chloride (CaCl2) is sometimes used as a de-icer. Calculate the percent by mass of each element in CaCl2. Ca = 36.11% Cl = 63.89%

Determine the empirical formula for a compound that contains 63 Determine the empirical formula for a compound that contains 63.16% O and 36.84% N.

Determine the empirical formula for a compound that contains 63 Determine the empirical formula for a compound that contains 63.16% O and 36.84% N. N2O3

Determine the empirical formula for a compound that contains 35 Determine the empirical formula for a compound that contains 35.98% aluminum (Al) and 64.02% sulfur (S).

Determine the empirical formula for a compound that contains 35 Determine the empirical formula for a compound that contains 35.98% aluminum (Al) and 64.02% sulfur (S). Al2S3

Propane is a hydrocarbon, a compound composed only of carbon and hydrogen. It is 81.82% carbon and 18.18% hydrogen. What is the empirical formula?

Propane is a hydrocarbon, a compound composed only of carbon and hydrogen. It is 81.82% carbon and 18.18% hydrogen. What is the empirical formula? C3H8

A compound was found to contain 49. 98 g of carbon and 10 A compound was found to contain 49.98 g of carbon and 10.47 g of hydrogen. The molar mass of the compound is 58.12 g/mol. Determine the molecular formula.

A compound was found to contain 49. 98 g of carbon and 10 A compound was found to contain 49.98 g of carbon and 10.47 g of hydrogen. The molar mass of the compound is 58.12 g/mol. Determine the molecular formula. C4H10

A colorless liquid composed of 46. 68% nitrogen and 53 A colorless liquid composed of 46.68% nitrogen and 53.32% oxygen has a molar mass of 60.01 g/mol. What is the molecular formula?

A colorless liquid composed of 46. 68% nitrogen and 53 A colorless liquid composed of 46.68% nitrogen and 53.32% oxygen has a molar mass of 60.01 g/mol. What is the molecular formula? N2O2

When an oxide of potassium is decomposed, 19. 55 g of K and 4 When an oxide of potassium is decomposed, 19.55 g of K and 4.00 g of O are obtained. What is the empirical formula for the compound?

When an oxide of potassium is decomposed, 19. 55 g of K and 4 When an oxide of potassium is decomposed, 19.55 g of K and 4.00 g of O are obtained. What is the empirical formula for the compound? K2O

The pain reliever, morphine, has 17. 900 g carbon, 1. 680 hydrogen, 4 The pain reliever, morphine, has 17.900 g carbon, 1.680 hydrogen, 4.225 oxygen, 1.228 nitrogen. Determine the empirical formula of morphine.

The pain reliever, morphine, has 17. 900 g carbon, 1. 680 hydrogen, 4 The pain reliever, morphine, has 17.900 g carbon, 1.680 hydrogen, 4.225 oxygen, 1.228 nitrogen. Determine the empirical formula of morphine. C17H19O3N

Ricinine is one of the poisonous compounds found in the castor plant Ricinine is one of the poisonous compounds found in the castor plant. It is 58.54% carbon, 4.91% hydrogen, 17.06% nitrogen, and 19.49% oxygen. Its molar mass is 164.16 g/mol. Determine molecular formula.

Ricinine is one of the poisonous compounds found in the castor plant Ricinine is one of the poisonous compounds found in the castor plant. It is 58.54% carbon, 4.91% hydrogen, 17.06% nitrogen, and 19.49% oxygen. Its molar mass is 164.16 g/mol. Determine molecular formula. C8H8N2O2

The compound borazine consists of 40. 29% boron, 7 The compound borazine consists of 40.29% boron, 7.51% hydrogen, and 52.20% nitrogen, and its molar mass is 80.50 g/mol. Calculate the molecular formula for borazine.

The compound borazine consists of 40. 29% boron, 7 The compound borazine consists of 40.29% boron, 7.51% hydrogen, and 52.20% nitrogen, and its molar mass is 80.50 g/mol. Calculate the molecular formula for borazine. B3H6N3

The composition of silver oxalate is 71. 02% silver, 7 The composition of silver oxalate is 71.02% silver, 7.91% carbon, and 21.07% oxygen. If the molar mass of silver oxalate is 303.8 g/mol, what is its molecular formula?

The composition of silver oxalate is 71. 02% silver, 7 The composition of silver oxalate is 71.02% silver, 7.91% carbon, and 21.07% oxygen. If the molar mass of silver oxalate is 303.8 g/mol, what is its molecular formula? Ag2C2O4

Triethylenemelamine is used in the plastics industry and as an anticancer drug. Its analysis is 52.93% carbon, 5.92% hydrogen, and 41.15% nitrogen. The molar mass of triethylenemelamine is 204.2 g/mol. Determine its molecular formula.

Triethylenemelamine is used in the plastics industry and as an anticancer drug. Its analysis is 52.93% carbon, 5.92% hydrogen, and 41.15% nitrogen. The molar mass of triethylenemelamine is 204.2 g/mol. Determine its molecular formula. C9H12N6