Calculating pH of a Strong Base City and Islington College

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Presentation transcript:

Calculating pH of a Strong Base City and Islington College David Martin City and Islington College To Print Students Name: …………………………………………………………………..

Topic Aims Method Equipment Duration Calculating the pH of Strong Bases Aims This worksheet provides guidance on how to calculate the pH of strong bases Level Level 3 Method PowerPoint slides (hand-out) – Slide 3 to 4 to print off, slide 5 to 6 Answers Equipment Laptop & Projector Hand-out Pens Duration >10-20 minutes Hidden

pH Water dissociates (splits up) to form H+ & OH- ions. In order to find the pH of a strong base we need to find which ion concentration?   H2O H+ + OH- Hydrogen ion concentration [H+] ____________________________________________________________________ Write a Ka expression for the equilibrium above Ka =   As water is in a much greater concentration than the ions the expression can be simplified. Ka =  The Kw for water has a value of 1 x 10-14 mol2dm-6 Problem Find the pH of a 0.1 moldm-3 NaOH solution NaOH is a strong alkali and is fully dissociated in water. NaOH Na+ + OH- [OH-] = 0.1 Kw = [H+] [OH-] [H+] = Kw/[OH-] [H+] = 1 x 10-14/0.1 [H+] = 1 x 10-13 pH = -log10[H+] = -log10 1 x 10-13 = 13 pH 13 sound right for a strong alkali To Print

pH Practise problems 1. Find the pH of a 0.2 moldm-3 KOH solution   1. Find the pH of a 0.2 moldm-3 KOH solution 2. Find the pH of a 0.005 moldm-3 NaOH solution Find the pH of a 0.001 moldm-3 LiOH solution Find the pH of a 2 moldm-3 NaOH solution To Print

ANSWERS To Print

pH Water dissociates (splits up) to form H+ & OH- ions. In order to find the pH of a strong base we need to find which ion concentration?   H2O H+ + OH- Hydrogen ion concentration [H+] Write a Ka expression for the equilibrium above Ka = [H+] [OH-] [H2O] As water is in a much greater concentration than the ions the expression can be simplified. Ka = [H+] [OH-] or Kw = [H+] [OH-]  The Kw for water has a value of 1 x 10-14 mol2dm-6 Problem Find the pH of a 0.1 moldm-3 NaOH solution NaOH is a strong alkali and is fully dissociated in water. NaOH Na+ + OH- [OH-] = 0.1 Kw = [H+] [OH-] [H+] = Kw/[OH-] [H+] = 1 x 10-14/0.1 [H+] = 1 x 10-13 pH = -log10[H+] = -log10 1 x 10-13 = 13 pH 13 sound right for a strong alkali To Print

pH Practise problems 1. Find the pH of a 0.2 moldm-3 KOH solution 13.3   1. Find the pH of a 0.2 moldm-3 KOH solution 13.3 2. Find the pH of a 0.005 moldm-3 NaOH solution 11.7 Find the pH of a 0.001 moldm-3 LiOH solution 11.0 Find the pH of a 2 moldm-3 NaOH solution 14.3 To Print

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