Problems 2.2 2.4 2.6 2.9 2.15 2.18 2.43 Previous Exams and quizzes.

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Presentation transcript:

Problems 2.2 2.4 2.6 2.9 2.15 2.18 2.43 Previous Exams and quizzes

Measuring Information-Example1.1 Find the information content of message that consists of a digital word 12 digits long in which each digit may take on one of four possible levels. The probability of sending any of the four levels is assumed to be equal, and the level in any digit does not depend on the values taken on by pervious digits. Answer: Possible combinations of 12 digits ( # of possible messages) = 412 Because each level is equally likely, all different words are equally likely.

Problems

Problems

Evaluation of DC Value DC Value of this waveform is: p(t) = v(t)i(t) A 120V , 60 Hz fluorescent lamp wired in a high power factor configuration. Assume the voltage and current are both sinusoids and in phase ( unity power factor) Voltage DC Value of this waveform is: Current Instantenous Power p(t) = v(t)i(t)

Spectrum of an Exponential Pulse

Spectrum of an Exponential Pulse

Example 2-3: Spectrum of a Damped Sinusoid Spectral Peaks of the Magnitude spectrum has moved to f = fo and f = -fo due to multiplication with the sinusoidal.

Example 2-3: Spectrum of a Damped Sinusoid Variation of W(f) with f

Spectrum of a Sine Wave

Spectrum of a Sine Wave

Spectrum of a Triangular Pulse The spectrum of a triangular pulse can be obtained by direct evaluation of the FT integral. An easier approach is to evaluate the FT using the second derivative of the triangular pulse. First derivative is composed of two rectangular pulses as shown. The second derivative consists of the three impulses. We can find the FT of the second derivative easily and then calculate the FT of the triangular pulse.

Spectrum of a Triangular Pulse

PSD of a Sinusoid

PSD of a Sinusoid The average normalized power may be obtained by using:

Evaluation of Power The instantaneous power is: The Average power is: Maximum Power Average Power The Maximum power is: Pmax=VI

Problem 2

Solution Problem 2 The signal is periodic signal. You can take averages for one period only.

Problem 4

Solution Problem 4

Solution Problem 4

Problem 6

Solution Problem 6

Solution Problem 6

Problem 9

Problem 15 f

Problem 18

Solution Problem 18

Solution Problem 18

Solution Problem 43

Solution Problem 43 f

Quiz I Spring 02-03

Quiz I Spring 02-03 Solution

Quiz I Spring 02-03 Solution

Mid Term I Spring 03-04

Mid Term I Spring 03-04 Solution

Mid Term I Spring 03-04 Solution

Mid Term I Fall 03-04 Solution