Lesson 5: Power In Balanced Three-Phase Systems

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Presentation transcript:

Lesson 5: Power In Balanced Three-Phase Systems ET 332a Ac Motors, Generators and Power Systems Lesson 5_et332b.pptx

Learning Objectives After this presentation you will be able to: Compute the active power absorbed by a three-phase load. Compute the reactive power absorbed by a three-phase load. Compute total three-phase apparent power. Compute the total power several loads absorb. Compute reactive power necessary to correct power factor in a three-phase system. Lesson 5_et332b.pptx

Three Phase Power Load can be either wye or delta connected. Assume wye connected load and compute power on per phase basis Phase Power Total Three-phase Power Using line quantities…for wye connected loads Lesson 5_et332b.pptx

Three Phase Power Total three-phase power using line quantities Where q is the angle between line voltage and line current Active Power Apparent Power Three-phase reactive power formulas Where qp is the angle between phase voltage and phase current Phase Reactive Total Reactive 3f power factor and Also Lesson 5_et332b.pptx

Three Phase Power Calculations Example 5-1: A balanced delta connected three-phase load draws 200 A per phase with a leading power factor of 0.85 from a 12.47 kV line to line system. Determine the following : a) The line current magnitude of the load b) the phase voltage magnitude of the load c) the total apparent power of the load d) the total real power drawn by the load e) the total reactive power drawn by the load f) the total complex power of the load Lesson 5_et332b.pptx

Example 5-1 Solution (1) a) Delta connected load so |VL|=|Vp| and |IL|=3|Ip| Ans b) Line voltage Ans c) Find the total apparent power, ST Using line quantities Using phase quantities Ans Ans Lesson 5_et332b.pptx

Example 5-1 Solution (2) d) Active or real power e) Reactive power Ans e) Reactive power Find q Ans Lesson 5_et332b.pptx

Example 5-1 Solution (3) f) Complex power. Assume VL angle is zero degrees Polar form Rectangular form P Q Lesson 5_et332b.pptx

Solving Three-phase Systems Example 5-2: For the system below find the ammeter reading, IA. Eab = 4600o V Ebc = 460  -120o V Eca = 460  120º V Z1 = 10 30o W Z2 = 15  10o W Z3 = 20+j20 W Ia1 Ia2 Ia3 Z3 Z1 Z2 Lesson 5_et332b.pptx

Example 5-2 Solution (1) Meter reading is sum of load currents Z1 is a balanced wye connected load Lesson 5_et332b.pptx

Example 5-2 Solution (2) Z2 balanced delta load. Find Ip then compute IL. Eab=Vab Lesson 5_et332b.pptx

Example 5-2 Solution (3) Find the single phase current Ia3 Eca Lesson 5_et332b.pptx

Example 5-2 Solution (4) Sum currents to find meter reading Ans Lesson 5_et332b.pptx

Solving Three-Phase Systems by Power Calculations Example 5-3: A 440 V 60 Hz 3-phase source supplies three loads: 1) Delta connected 3-phase 60 hp induction motor operating at 3/4 of rated output with an efficiency of 90% and a power factor of 94% 2) A wye connected 3-phase 75 hp induction motor operating at half of its rated output with an efficiency of 88% and a power factor of 74% 3) A delta connect resistive heater drawing 20 kW. Find: a) total active, reactive, and apparent power supplied by the source b) the power factor of the combined loads c) the magnitude of the line current d) the capacitance and voltage rating for a wye connected capacitor bank that will correct the system power factor to 0.95 lagging Lesson 5_et332b.pptx

Solution Method Find the total active and reactive power absorbed by each load, using the power factor and the efficiency, then construct power triangle for total load. Use the following formulas Where: Po = machine mechanical shaft output (W) Pi = machine electrical input (W) Prated = machine rated shaft power (W) PT = total 3-phase active power (W) ST = total 3-phase apparent power (VA) QT = total 3-phase reactive power (VARs) h = machine efficiency LF = load factor Lesson 5_et332b.pptx

Example 5-3 Solution (1) a) Load 1: 60 Hp induction motor Find power factor angle Induction motor-Fp lagging QT positive Lesson 5_et332b.pptx

Example 5-3 Solution (2) Load 2: 75 hp induction motor Find QT1 Lesson 5_et332b.pptx

Example 5-3 Solution (3) Find the power factor angle then find QT2 Load 3; Resistance heater Only absorbs watts Sum the total active and reactive power of each load to find the total system power absorbed. Lesson 5_et332b.pptx

Example 5-3 Solution (4) Ans Ans Ans Lesson 5_et332b.pptx

Example 5-3 Solution (5) b) Find the power factor of the combined load Ans c) Find the load current magnitude Ans Lesson 5_et332b.pptx

Example 5-3 Solution (6) d) Find the capacitance and voltage rating of a capacitor that corrects the system power factor to 0.95 lagging. PT=89,090 W QT=42,434 VAR ST=98,680 VA STnew Where q is system power factor angle Construct new triangle Lesson 5_et332b.pptx

Example 5-3 Solution (7) This is the value of the total 3-phase VARs required to correct Fp to 0.95 lagging The capacitor bank power, Qc, is the difference between Qsys and QTnew Psys=89,090 W Qsys=42,434 VAR Ssys=98,680 VA Qc STnew QTnew Lesson 5_et332b.pptx

Example 5-3 Solution (8) Use the one-step formula to check result Compares to previous Lesson 5_et332b.pptx

Example 5-3 Solution (9) Qc is the total bank power required, find the phase power Bank is wye connected so capacitors see Vpn not VL Ans Find the capacitor value Ans Lesson 5_et332b.pptx

End Lesson 5: Power In Balanced Three-Phase Systems ET 332a Ac Motors, Generators and Power Systems Lesson 5_et332b.pptx