Proton Form Factor Ratio GE/GM from Double Spin Asymmetry with

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Presentation transcript:

Proton Form Factor Ratio GE/GM from Double Spin Asymmetry with Polarized Beam and Target Spin Asymmetries of the Nucleon Experiment ( E07-003) Anusha Liyanage

Outline Physics Motivation Experiment Setup Elastic Kinematics Data Analysis • Electrons in HMS • Protons in HMS Future Work/Conclusion Polarized Target

Physics Motivation RSS (Jlab) Q2 = 1.50 (GeV/c)2 Dramatic discrepancy between Rosenbluth and recoil polarization technique. Multi-photon exchange considered the best candidate for the explanation RSS (Jlab) Q2 = 1.50 (GeV/c)2 M. Jones et al., PRC74 (2006) 035201 GeP-III (Jlab) Q2 = 5.2 (GeV/c)2 , 6.7 (GeV/c)2 and 8.5 (GeV/c)2 A.J.R. Puckett et al., Phys. Rev. Lett. 104 (2010) 242301 Dramatic discrepancy ! Dramatic discrepancy ! 5.17 6.25 SANE 2.20

Experiment SANE e- p e- p e- p/e- Central scattering angle :40 ° Elastic (e , e’p) scattering from the polarized NH3 target using a longitudinally polarized electron beam (Data collected from Jan – March ,2009) HMS for the scattered proton detection Single arm electron detection Central angles are 22.3° and 22.0° Solid angle ~10 msr e- p e- p Hall C at Jefferson Lab BETA for coincidence electron Central scattering angle :40 ° Over 200 msr solid angle coverage e- p/e-

Polarized Target field configuration Average target polarization is • C ,CH2 and NH3 • Dynamic Nuclear Polarization (DNP) polarized the protons in the NH3 target up to 90% • Used microwaves to excite spin flip transitions • Polarization measured using NMR coils ΘB = 180° ΘB = 80° ( 80 and 180 deg ) Used perpendicular Magnetic field configuration Average target polarization is ~ 70 % Beam polarization is ~ 73 % • Refrigerator - 1 K • Magnetic Field - 5 T • NMR system • Microwaves - 55 GHz - 165 GHz

Elastic Kinematics Spectrometer mode Coincidence Single Arm Run Dates Beam Energy Magnet Orientation Run Hours/ Proposed PAC hours Average Beam Polarization Elastic Kinematics Spectrometer mode Coincidence Single Arm HMS Detects Proton Electron E Beam GeV 4.72 5.89 P GeV/C 3.58 4.17 4.40 Θ (Deg) 22.30 22.00 15.40 Q2 (GeV/C)2 5.17 6.26 2.20 Total Hours (h) ~40 (~44 runs) ~155 (~135 runs) ~12 (~15 runs) e-p Events ~113 ~824 -

PART I : Electrons in HMS Data Analysis PART I : Electrons in HMS By knowing the beam energy, E and the scattered electron angle, • Used only the Electron selection cuts. The Invariant mass abs(W)<4 0.9<(W)<1 e- Θ Invariant Mass, W The Raw Asymmetries The Raw Asymmetry, Ar Further analysis requires a study of the dilution factor and backgrounds in order to determine the physics asymmetry and GE/GM. (at Q2=2.2 (GeV/C)2 )

Extracting the elastic events PART II: Protons in HMS Extracting the elastic events ΘP Xclust Yclust e e’ P Definitions : X/Yclust - Measured X/Y positions on BigCal X = horizontal /in-plane coordinate Y = vertical / out – of – plane coordinate Eclust - Measured electron energy at BigCal By knowing the energy of the polarized electron beam, EB and the scattered proton angle, ΘP We can predict the X/Y coordinates - X_HMS, Y_HMS and ( Target Magnetic Field Corrected) The Energy - E_HMS of the coincidence electron on BigCal

Extracting the Elastic Events… abs(X_HMS-Xclust+1.6)<7 X_HMS-Xclust (cm) X position difference abs(Y_HMS-Yclust+5.7)<12 Y_HMS-Yclust (cm) Y position difference Y position diff. Vs X position diff. X_HMS-Xclust (cm) Y_HMS-Yclust (cm) The Elliptic cut, Y_HMS-Yclust (cm) Suppresses background most effectively Here, ∆X = X_HMS – xclust ∆Y = Y_HMS – yclust X(Y)max = The effective area cut X_HMS-Xclust (cm) y position difference abs(Y_HMS-yclust) < 10 Y_HMS-yclust (cm)

Momentum difference The Momentum Difference , dPel_hms PHMS – Measured Proton momentum by HMS Pcal – Calculated Proton momentum by knowing the beam energy, E and the Proton scattered angle, Pcent – HMS central momentum Here , M is the Proton mass. dpel_hms abs(dpel_hms+0.01)<0.04 The Momentum Difference , dPel_hms The final elastic events are selected by using, • The Elliptic cut and • The ‘dpel_hms’ cut

From The Experiment ≈ 102° and = 0 The raw asymmetry, Ar N+ = Counts for the + helicity N- = Counts for the – helicity ∆Ar = Error on the raw asymmetry The elastic asymmetry, Ap f = Dilution Factor PB,PT = Beam and Target polarization ∆Ap = Error on the elastic asymmetry Nc= A correction term to eliminates the contribution from quasi-elastic 15N scattering under the elastic peak The beam - target asymmetry, Ap The calculated asymmetry vs μGE/GM At Q2=6.26 (GeV/C)2 and ≈ 102° and = 0 μ GE/GM Ratio 0.0 0.6 1.0 1.2 0.4 0.2 0.8 -0.05 0.05 0.10 0.15 0.20 0.00 Rosenbluth Tech. Pol. Tran. Tech Asymmetry r = GE /GM a, b, c = kinematic factors , = pol. and azi. Angles between q and S Here, ≈ 102° and = 0 From the HMS kinematics, r2 << c 0.0

Future Work .. Extract the physics asymmetry and the GE/GM ratio Improve the MC/SIMC simulation and estimate the background Conclusion .. Measurement of the beam-target asymmetry in elastic electron- proton scattering offers an independent technique of determining GE/GM ratio. This is an ‘explorative’ measurement, as a by-product of the SANE experiment. Plan to submit a proposal to PAC for *dedicated* experiment with higher statistics after the 12 GeV upgrade.

Thank You SANE Collaborators: Argonne National Laboratory, Christopher Newport U., Florida International U., Hampton U., Thomas Jefferson National Accelerator Facility, Mississippi State U., North Carolina A&M, Norfolk S. U., Ohio U., Institute for High Energy Physics, U. of Regina, Rensselaer Polytechnic I., Rutgers U., Seoul National U., State University at New Orleans , Temple U., Tohoku U., U. of New Hampshire, U. of Virginia, College of William and Mary, Xavier University, Yerevan Physics Inst. Spokespersons: S. Choi (Seoul), M. Jones (TJNAF), Z-E. Meziani (Temple), O. A. Rondon (UVA) Thank You

Backup Slide

Error Propagation From The Experiment….. Using the experiment data at Q2=6.26 (GeV/C)2 , with total ep events ~824, ∆Ap=0.11 ∆r = 0.22 μ ∆r = 2.79 x 0.22 μ ∆r = 0.6 Q2=5.19 (GeV/C)2 , with total ep events ~113, ∆Ap=0.26 ∆r = 0.46 μ ∆r = 2.79 x 0.46 μ ∆r = 1.29 Where , μ – Magnetic Moment of the Proton