be taken to the post-quiz. TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz. CLICK TO CONTINUE

One mole of solid sulfur (an element) contains 6.022 x 1023 atoms. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY One mole of solid  sulfur (an element) contains 6.022 x 1023 atoms.

One mole of liquid bromine (a compound) contains 6.022 x 1023 molecules.

One mole of gaseous carbon dioxide (a compound) contains 6.022 x 1023 molecules. CLICK TO CONTINUE

One mole solid SULFUR mass 32.066 g LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY One mole solid SULFUR mass 32.066 g

One mole liquid BROMINE mass 159.808 g

One mole gaseous CARBON DIOXIDE mass 44.010 g CLICK TO CONTINUE

approximate volume at room temperature and pressure 16 cm3 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY One mole solid SULFUR approximate volume at room temperature and pressure 16 cm3

One mole liquid BROMINE approximate volume at room temperature and pressure 51 cm3

One mole gaseous CARBON DIOXIDE approximate volume at room temperature and pressure 20,000 cm3  CLICK TO CONTINUE

One mole of sulfur atoms LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY ONE SULFUR ATOM formula S atomic weight 32.066 One mole of sulfur atoms mass 32.066 g

ONE BROMINE MOLECULE formula Br2 atomic weight 79.904 molecular weight 159.808 One mole bromine molecules mass 159.808 g

MOLECULE formula CO2 atomic weights ONE CARBON DIOXIDE MOLECULE formula CO2 atomic weights carbon 12.011 oxygen 15.9994 molecular weight 44.010 One mole carbon dioxide molecules mass 44.010 g CLICK TO CONTINUE

1. Convert 30 g carbon to moles. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 1. Convert 30 g carbon to moles.

C, atomic weight 12.011 1 mole C (12.011 g) CLICK TO CONTINUE

mass (g) carbon  moles carbon LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.) mass (g) carbon  moles carbon CLICK TO CONTINUE

1 12.011 mole C g C _________ 30 g C x 30 mole C 12.011 = 2.5 mol C LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.) 1 12.011 mole C g C _________ 30 g C x 30 mole C 12.011 = 2.5 mol C CLICK TO CONTINUE

2. Convert 3.5 liters of ammonia at S.T.P. to moles.  

1 mole gaseous ammonia, NH3; volume 22.414 liters at S.T.P. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH3 at S.T.P. to mol.) 1 mole gaseous ammonia, NH3; volume 22.414 liters at S.T.P.

volume (L) ammonia  moles ammonia LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH3 at S.T.P. to mol.) volume (L) ammonia  moles ammonia CLICK TO CONTINUE

1 22.414 mol NH3 L NH3 ___________ 3.5 L NH3 x 3.5 mol NH3 22.414 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH3 at S.T.P. to mol.) 1 22.414 mol NH3 L NH3 ___________ 3.5 L NH3 x 3.5 mol NH3 22.414 = 0.16 mol NH3 CLICK TO CONTINUE

3. How many moles of glucose are in 10 mL of a 0 3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution?

0.5 moles/liter glucose in solution of (# mol glucose in 10 mL 0.5 M soln?) 0.5 moles/liter glucose in solution of 10 mL

volume (mL) solution  volume (L) solution  moles solvent LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) volume (mL) solution  volume (L) solution  moles solvent CLICK TO CONTINUE

1 1000 or 10 mL solution x 1 L 103 mL ______ L mL 10 mL solution x or LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 1 1000 or 10 mL solution x 1 L 103 mL ______ L mL 10 mL solution x or 10 mL solution x 10-3 L 1 mL CLICK TO CONTINUE

or or 10 mL solution x 1 L 1000 mL x mol glucose L solution 0.5 1 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 10 mL solution x 1 L 1000 mL x mol glucose L solution 0.5 1 or x mol glucose L solution 0.5 1 10 mL solution x 1 L 103 mL or 10 mL solution x 10-3 L 1 mL x mol glucose L solution 0.5 1 CLICK TO CONTINUE

or 10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution or 10 mL solution x 1 L x 0.5 mol glucose 103 mL 1 L solution 10 mL solution x 10-3 L x 0.5 mol glucose 1 mL 1 L solution CLICK TO CONTINUE

10 x 0.5 mol glucose 1000 or 103 10 x 10-3 x 0.5 mol glucose LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 10 x 0.5 mol glucose 1000 or 103 10 x 10-3 x 0.5 mol glucose = 0.005 or 5 x 10-3 mol glucose CLICK TO CONTINUE

4. How many atoms are present in 4.0 moles of phosphine, PH3? 

(# atoms in 4.0 mol PH3?) H P phosphine molecules

moles phosphine  molecules phosphine  atoms LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH3?) moles phosphine  molecules phosphine  atoms CLICK TO CONTINUE

_____________________ molecules PH3 mol PH3 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH3?) 4.0 mol PH3 x 6.02 x 1023 1 _____________________ molecules PH3 mol PH3 x atoms molecule PH3 4 1 CLICK TO CONTINUE

4.0 x 6.02 x 1023 x 4 atoms = 9.6 x 1024 atoms ___________________ LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH3?) 4.0 mol PH3 x 6.02 x 1023 molecules PH3 1 mol PH3 x 4 atoms 1 molecules PH3 ___________________ 4.0 x 6.02 x 1023 x 4 atoms = 9.6 x 1024 atoms CLICK TO CONTINUE

5. How many electrons are lost by ionization of 0.65 moles of calcium?

(# electrons lost by 0.65 mol Ca?) + + + e + + + e + + + e e e e + + + e e + + + e e + + + e + + + e e e e e + + + e + e + + + e + e

moles calcium  atoms calcium  electrons (# electrons lost by 0.65 mol Ca?) moles calcium  atoms calcium  electrons CLICK TO CONTINUE

6.02 x 1023 2 1 1 atoms Ca mol Ca __________________ 0.65 mol Ca x LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) 6.02 x 1023 1 atoms Ca mol Ca __________________ 0.65 mol Ca x x electrons atoms Ca 2 1 CLICK TO CONTINUE

0.65 mol Ca x 6.02 x 1023 atoms Ca 1 mol Ca x 2 electrons 1 atoms Ca LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) 0.65 mol Ca x 6.02 x 1023 atoms Ca 1 mol Ca x 2 electrons 1 atoms Ca 0.65 x 6.02 x 1023 x 2 electrons = 7.8 x 1023 electrons END OF TUTORIAL CLICK TO CONTINUE

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