DO NOW Pick up notes Gas Pressure lab is due Thursday

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Presentation transcript:

DO NOW Pick up notes Gas Pressure lab is due Thursday Big Chill project is due Friday.

GAS LAWS

VIDEO Chapter 2 – Racing Hot Air Balloons

GASES (Chapter 12) Physical Properties of Gases: Gases have mass. Gases have no definite volume, no definite shape, are easily compressed, and behave independently of each other. Gas particles do not attract or repel each other – the spaces between the particles is too great.

GASES (Chapter 12) The fact that gas molecules are in constant, random motion allows gases to fill their containers completely. Different gases can move through each other quite rapidly. This movement is called DIFFUSION. EFFUSION is when diffusion occurs through a small opening. Gases exert pressure and the pressure of a gas depends on its temperature and volume.

GASES Remember that gases consist of very small particles, the particles have large distances between them, they are in constant, rapid, random motion and have elastic collisions. Actual gases (in real life) do not obey all the suppositions stated in the kinetic-molecular theory. In order to accurately measure a gas sample, you must know the quantity of particles (moles), pressure, temperature, and volume of a gas.

THE GAS LAWS Boyle’s Law: between VOLUME and PRESSURE; inversely proportional. Charles’ Law: betweenVOLUME TEMPERATURE ; directly proportional. Gay-Lussac’s Law: between PRESSURE and TEMPERATURE; directly proportional. Avogadro’ Principle: between numbers of particles – moles - and PRESSURE or VOLUME; directly proportional.

BOYLE’S LAW DEMOS – Boyle’s Law Chapter 7 – Breathing and Boyle’s Law 1. Why does the balloon expand? 2. What does this demo have to do with breathing? 3. Have you ever heard the phrase “nature abhors a vacuum?” What do you think it means? Cartesian Diver Artificial lung

BOYLE’S LAW

BOYLE’S LAW THE LAW: For a given mass of gas, at a constant temperature, the volume varies inversely with the pressure: P1V1 = P2V2 PRACTICE: The pressure in a 9.0 L balloon is 2.1 atm. If the volume is reduced to 5.0 L, what will the resulting pressure be? (Temperature does not change.) V1 = P1V1 = P2V2 P1 = V2 = P2 =

Points will be given for this information. REMINDER EVERY TIME you do a gas laws problem: Write what you know and what you are trying to find. Write the formula. Plug in the numbers with units and solve with the correct number of sig figs. Points will be given for this information.

CHARLES’ LAW DEMO Balloon and temperature change

CHARLES’ LAW

CHARLES LAW THE LAW: The volume of a fixed mass of a gas is directly proportional to its KELVIN temperature if the pressure is constant. If pressure is kept constant, then volume must change to keep temperature the same. V1T2 = V2 T1 You must use the Kelvin temperature scale!

You must use the Kelvin temperature scale! CHARLES LAW You must use the Kelvin temperature scale! PRACTICE: The temperature of a sample of gas is 300.0 K. The gas’ volume is 25.0 L. What will be the new volume of the gas if the temperature is dropped to 125.0 K? V1 = V2T1 = T2V1 T1 = V2 = T2 =

Points will be given for this information. REMINDER EVERY TIME you do a gas laws problem: Write what you know and what you are trying to find. Write the formula. Plug in the numbers with units and solve with the correct number of sig figs. Points will be given for this information.

GAY-LUSSAC’S LAW Videodisc – Chapter 5 - Imploding Can 1. Why did the can implode? 2. How does the demonstration you just saw relate to a barometer? 3. How is a vacuum seal created on a jar of homemade preserves? Egg in a bottle

GAY-LUSSAC’S LAW

You must use Kelvin temperature scale! GAY-LUSSAC’S LAW THE LAW: An increase in temperature increases the frequency of collisions between gas particles. In a given volume, raising the KELVIN temperature also raises the pressure. P1 T2= P2 T1  You must use Kelvin temperature scale!

GAY-LUSSAC’S LAW You must use Kelvin temperature scale! PRACTICE: The temperature of a sample of gas is 300.0 K. The gas’ pressure is 1.4 atm. What will be the new pressure of the gas be if the temperature is dropped to 125.0 K? P1 = P2T1 = T2P1 T1 = P2 = T2 =

Points will be given for this information. REMINDER EVERY TIME you do a gas laws problem: Write what you know and what you are trying to find. Write the formula. Plug in the numbers with units and solve with the correct number of sig figs. Points will be given for this information.

HINT PTV

PUTTING IT ALL TOGETHER Simulation on gas laws: Structure and Properties of Matter

TO DO Handout on Boyle’s, Charles, and Gay- Lussac’s problems due Thursday.