HW #4 /Tutorial # 4 WRF Chapter 18; WWWR Chapter 19 ID Chapter 6 To be discussed on Feb. 7, 2017. By either volunteer or class list. Correction Question WWWR # 19.19

Convective Heat Transfer

Fundamental Considerations In Convective Heat Transfer Two main classifications of convective heat transfer These have to do with the driving force causing fluid to flow Natural or free convection Fluid motion results from heat transfer Fluid heated/ cooled -> density change/ buoyancy effect -> natural circulation in which affected fluid moves of its own accord past the solid surface - fluid it replaces is similarly affected by the energy transfer - process is repeated

Forced convection Fluid circulation is produced by external agency (fan or pump) Analytical Methods Dimensional Analysis Analogy between Energy and Momentum Exchange

Significant Parameters In Convective Heat Transfer Both have same dimensions L2/t; thus their ratio must be dimensionless This ratio, that of molecular diffusivity of momentum to the molecular diffusivity of heat, is designed the Prandtl number Pr º = n a mcp k

Prandtl number observed to be a combination of fluid properties; thus Pr itself may be thought of as a property. Primarily a function of temperature s

A ratio of conductive thermal resistance to the convective thermal resistance of the fluid Nusselt number Nu º hL k Where the thermal conductivity of the fluid as opposed to that of the solid, which was the case in the evaluation of the Biot modulus.

Dimensional Analysis of Convective Energy Transfer Forced Convection

Dimensional Analysis for Forced Convection

Natural Convection

Courtesy Contribution by ChBE Year Representative, 2004. Dimensional Analysis for Natural Convection

Energy and Momentum Transfer Analogies

er 8) 9) s on The Colburn analogy expression is Cf St Pr 2/3 = 2 (19-37) 8) 9) s on er

Example 1 Water at 50oF enters a heat-exchanger tube having an inside diameter of 1 in and a length of 10 ft. The water flows at 20 gal/min. For a constant wall temperature of 210oF estimate the

= (50+130)/2 =(90+210)/2 = 150 Film temperature = (water mean bulk temperature + pipe wall temperature)/2 Mean bulk temperature of water = (inlet + outlet)/2

Second iteration is required since if |TL – 130| > 3oF?