AP Chemistry Exam Review

Slides:



Advertisements
Similar presentations
Unit 11 Stoichiometry CP Chemistry.
Advertisements

College Placement Chemistry: Year In Review * Denotes concepts that occur repeatedly throughout the course.
Chapter 12 “Stoichiometry”
Chapter 12 “Stoichiometry” Chemistry Tutorial Stoichiometry Mr. Mole.
III. Stoichiometry Stoy – kee – ahm –eh - tree
Chapter Three: Stoichiometry Nick Tang 2 nd Period Ms. Ricks.
Chapter 12 Stoichiometry
Chapter 9 Stoichiometry
Stoichiometry Chapter 9 Stoichiometry  Greek for “measuring elements”  The calculations of quantities in chemical reactions based on a balanced equation.
Chapter 8 Stoichiometry.
“Stoichiometry” Original slides by Stephen L. Cotton Mr. Mole.
Chemical Reactions. Balancing Chemical Equations- Problem Sodium metal reacts with water to produce aqueous sodium hydroxide and hydrogen. Sodium metal.
Chemical Reactions. Balancing Chemical Equations- Problem Sodium metal reacts with water to produce aqueous sodium hydroxide and hydrogen. Sodium metal.
Chapter 3 - Stoichiometry It is important to be able to quantify the amount of reagent(s) that will be needed to produce a given amount of product(s).
Chapter 12 “Stoichiometry” Chemistry Chemistry Pioneer High School Mr. David Norton.
Honors Chapter 12 Stoichiometry u Greek for “measuring elements” u The calculations of quantities in chemical reactions based on a balanced equation.
Stoichiometry u Greek for “measuring elements” u The calculations of quantities in chemical reactions based on a balanced equation. u We can interpret.
Stoichiometry! The heart of chemistry. The Mole The mole is the SI unit chemists use to represent an amount of substance. 1 mole of any substance = 6.02.
Chapter 12 “Stoichiometry” Mr. Mole. Stoichiometry is… u Greek for “measuring elements” Pronounced “stoy kee ahm uh tree” u Defined as: calculations of.
Chapter 12 “Stoichiometry” Pre-AP Chemistry Charles Page High School Stephen L. Cotton Mr. Mole.
Stoichiometry is… Greek for “measuring elements” Defined as: calculations of the quantities in chemical reactions, based on a balanced equation. There.
 I can define stoichiometry.  I can identify the number of moles required in a reaction based on the coefficients.  I can determine how many moles.
“Stoichiometry” Original slides by Stephen L. Cotton and modified by Roth, Prasad and Coglon Mr. Mole.
Chapter 3 Chemical Reactions and Reaction Stoichiometry
AP Chemistry Exam Review
Chemistry Final Exam review
Lesson 1 Electrons and Energy Levels
1. Substitute the word “average kinetic energy” for “___________” to make questions easier. Temperature.
Chapter 3: Stiochiometry
Properties of Molecular Substances
Chapter 12 Stoichiometry.
Warm-up: Atomic size is one of the many trends of the Periodic Table.
Start Up (Copy in NB left side) The stronger the intermolecular forces, the higher the boiling point. Weak Intermolecular forces are found in.
Chapter 12 “Stoichiometry”
Chemistry is the study of matter.
Chapter 4.4: Intermolecular forces
Big Idea #1 Properties of Matter.
AP Chemistry Exam Review
Big Idea #1 Properties of Matter.
AP Chemistry Exam Review
1st 9 weeks Study Guide.
Intermolecular Forces
Electronic Structure of the Atom: Photoelectron Spectroscopy (PES)
Bonding and Properties
“Stoichiometry” Mr. Mole.
Bonding.
Chapter 3 Stoichiometry.
Describing Chemical Reactions.
AP Chemistry Exam Review
Periodic Trends Notes.
Chemistry Review sheet
Chapter 12 “Stoichiometry”
Unit 11: Chemical Reactions
Stoichiometry – Mr. Mole.
Chapter 11 “Stoichiometry”
Physical & Chemical Changes
Chapter 12.
The Mole through Percent Yield
Chemical Reactions, Chemical Equations, and Stoichiometry
Chapter 10.
Chapter 12 “Stoichiometry”
Unit 5 “Stoichiometry” Mr. Mole.
Atoms and Bonding Table of Contents
Review Reaction Rates and Equilibrium / Final Review
Chemical Quantities For example – let’s say you want to buy some Bazooka Gum You could buy it by the piece from the deli You could buy it by the box from.
ELECTRON CONFIGURATION
Kinetic Molecular Theory
Chapter 12 Stoichiometry
Chapter 9 “Stoichiometry”
Presentation transcript:

AP Chemistry Exam Review Histidine! AP Chemistry Exam Review

2016 Review Schedule Doc K Day 1: Overview of process and exam format; how to get your scores; AP chemistry review Day 2: MC test Day 3 through 5: identify what you don’t know based on MC test outcome; FRQs – grade yourself Throughout: Build connections between Big Ideas! Examples: Dead batteries are at equilibrium; vibration states increase specific heat; Coulomb’s law applies to attractions within atoms and between molecules See https://sites.google.com/site/drksapchemistry/review Talk about average scores and grading process – that’s why using the grading rubric is important – sometimes picky, sometimes generous Can talk about test strategies – eliminate some choices to improve your guess percentage; don’t dwell on a problem too long Answer the question asked! If we ask for an intermolecular force, tell us which one! Show work!

Big Idea #1 Properties of Matter

Source Chemical Reactivity Using Trends Nonmetals have higher electronegativities than metals --> causes the formation of ionic solids Compounds formed between nonmetals are molecular Usually gases, liquids, or volatile solids at room temperature Elements in the 3rd period and below can accommodate a larger number of bonds The first element in a group (upper most element of a group) forms pi bonds more easily (most significant in 2nd row, non- metals) Accounts for stronger bonds in molecules containing these elements Major factor in determining the structures of compounds formed from these elements Elements in periods 3-6 tend to form only single bonds Reactivity tends to increase as you go down a group for metals and up a group for non-metals. 46) Of the elements below, __________ is the most chemically reactive. A) sodium B) barium C) calcium D) cesium E) magnesium Video L.O. 1.10: Students can justify with evidence the arrangement of the periodic table and can apply periodic properties to chemical reactivity

Common problems and misconceptions Going from mass to empirical formula – often switch the coefficients Transition metals lose the s electrons first s electrons are further on average from nucleus than p for same energy level Units: kJ vs J, °C vs K, per mole or per gram; don’t lose track of which unit you’re using; not always at STP for a gas Explaining is more than just an observation: a lone pair on a central atom is not sufficient for shape, the pair must act (repel the other electrons) What occurs in the process of dissolving? The solute is not disappearing; it is mixing Show combustion analysis slide for Big Idea #1 Van der Waal’s is not LDF; mass is not an explanation for LDF, # electrons, polarizability, size, volume have been accepted Students get mixed up in limiting reactant problems – amounts of whatever is left over Don’t make H+ from a strong base, don’t make OH- from a strong acid

Big Idea #3 Chemical Reactions

Limiting Reactants – D.A. Source Limiting Reactants – D.A. Al2S3 + 6 H2O ---> 2Al(OH)3 + 3 H2S 15.00 g aluminum sulfide and 10.00 g water react  Identify the Limiting Reactant Video Sim pHet Click reveals answer and explanation. 15.00g Al2S3 x (1mol/ 150.158 g) x (6mol H2O/1mol Al2S3) x (18g/mol H20 ) = 10.782 g H20 needed 10g H20 x (1mol/ 18.015 g) x (1 mol Al2S3 / 6mol H2O) x (150.158 g/mol) = 13.892g Al2S3 needed H20 is limiting, because we need more than we were given b) What is the maximum mass of H2S which can be formed from these reagents? Theoretical Yield 10.00 g H20 x (1mol/ 18.015 g) x (3/6) x (34.0809 g/mol ) = 9.459 g H2S produced Click reveals answer and explanation. c) How much excess reactant is left in the container? Click reveals answer and explanation. 15.00 g – 13.892 g = 1.11g Al2S3 **Dimensional Analysis is not the only way to solve these problems. You can also use BCA tables (modified ICE charts), which may save time on the exam  LO 3.4: The student is able to relate quantities (measured mass of substances, volumes of solutions, or volumes and pressures of gases) to identify stoichiometric relationships for a reaction, including situations involving limiting reactants and situations in which the reaction has not gone to completion.

Common problems and misconceptions Don’t make H+ from the addition of a strong base; don’t make OH- from the addition of a strong acid Van der Waal’s is not LDF; do not use mass as an explanation for LDF. You may use polarizability, # of electrons, size, and volume. Limiting reactant problems are confusing – which is limiting, how much of the other is used up, how much of the other remains, etc Combustion analysis to get empirical formula can be confusing, particularly if not using oxygen as the oxidizer