Session 3 Welcome: To session 3-the fourth learning sequence

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Presentation transcript:

Session 3 Welcome: To session 3-the fourth learning sequence “Relational algebra “ Recap : In the previous learning sequences, we discussed the four operators of relational algebra. Present learning: We shall explore the following topic: - Example Queries

Relational Algebra

Relational Algebra A basic expression in the relational algebra consists of either one of the following: A relation in the database A constant relation

Relational Algebra Let E1 and E2 be relational-algebra expressions; the following are relational-algebra expressions: E1  E2 E1  E2 E1 - E2 E1 x E2 p (E1), P is a predicate on attributes in E1 s(E1), S is a list consisting of some of the attributes in E1  x (E1), x is the new name for the result of E1 The assignment operation ()

Relational Schema for the Banking Enterprise branch (branch-name, branch-city, assets) customer (customer-name, customer-street, customer-only) account (account-number, branch-name, balance) loan (loan-number, branch-name, amount) depositor (customer-name, account-number) borrower (customer-name, loan-number)

loan-number (amount > 1200 (loan)) Example Queries Find all loans of over $1200. amount > 1200 (loan) Find the loan number for each loan of an amount greater than $1200. loan-number (amount > 1200 (loan))

Example Queries Find the names of all customers who have a loan, an account, or both, from the bank. customer-name (borrower)  customer-name (depositor) Find the names of all customers who have a loan and an account at bank. customer-name (borrower)  customer-name (depositor)

Example Queries Find the names of all customers who have a loan at the Perryridge branch. customer-name (branch-name=“Perryridge” (borrower.loan-number = loan.loan-number(borrower x loan))) Find the names of all customers who have a loan at the Perryridge branch but do not have an account at any branch of the bank. customer-name (branch-name = “Perryridge” (borrower.loan-number = loan.loan-number(borrower x loan))) – customer-name(depositor)

Example Queries Find the names of all customers who have a loan at the Perryridge branch. Query 1 customer-name(branch-name = “Perryridge” ( borrower.loan-number = loan.loan-number(borrower x loan)))  Query 2 customer-name(loan.loan-number = borrower.loan-number( (branch-name = “Perryridge”(loan)) x borrower))

Example Queries Find the largest account balance Rename account relation as d The query is: balance(account) - account.balance (account.balance < d.balance (account x rd (account)))

Relational Algebra Summary: In this learning sequence, we discussed some example queries.

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