Calculate the percent by mass composition of C2H4O2..

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Calculate the percent by mass composition of C2H4O2.. Calculate the molar mass of the compound Express the mass of each element within the compound as a percentage of the molar mass of the compound. Make sure to account for multiple atoms. Multiply by 100% to convert to a percentage.

Calculate the percent by mass composition of C2H4O2.

Mass of pure chemical Total mass of sample % purity = x 100

Consider the reaction of magnesium hydroxide with phosphoric acid. 3Mg(OH)2 + 2H3PO4  Mg3(PO4)2 + 6H2O Calculate the mass of Mg3(PO4)2 that will be formed (assuming a 100% yield) from the reaction of 15.0 g of 92.5% Mg(OH)2 with an excess of H3PO4. Mass of sample This would be percentage purity

Consider the reaction of magnesium hydroxide with phosphoric acid. 3Mg(OH)2 + 2H3PO4  Mg3(PO4)2 + 6H2O Calculate the mass of Mg3(PO4)2 that will be formed (assuming a 100% yield) from the reaction of 15.0 g of 92.5% Mg(OH)2 with an excess of H3PO4. x 100 Mass of pure chemical = % purity X Total mass of sample mass Mg(OH)2 = 15.0 x 0.925 = 13.875 g Mass of pure chemical Total mass of sample % purity = 100

Consider the reaction of magnesium hydroxide with phosphoric acid. 3Mg(OH)2 + 2H3PO4  Mg3(PO4)2 + 6H2O (b) Calculate the mass of 88.5% Mg(OH)2 needed to make 127 g of Mg3(PO4)2, assuming a 100% yield. This would be percentage purity You would need to you this to calculate the mass of pure chemical required

Consider the reaction of magnesium hydroxide with phosphoric acid. 3Mg(OH)2 + 2H3PO4  Mg3(PO4)2 + 6H2O (b) Calculate the mass of 88.5% Mg(OH)2 needed to make 127 g of Mg3(PO4)2, assuming a 100% yield. 127g Mg3(PO4)2 1 mole Mg3(PO4)2 3 mole Mg(OH)2 58.3g Mg3(OH)2 84.5g Mg3(OH)2 262.9g Mg3(PO4)2 1 mole Mg3(PO4) 1 mole Mg(OH)2

Consider the reaction of magnesium hydroxide with phosphoric acid. 3Mg(OH)2 + 2H3PO4  Mg3(PO4)2 + 6H2O (b) Calculate the mass of 88.5% Mg(OH)2 needed to make 127 g of Mg3(PO4)2, assuming a 100% yield. 84.5g Mass of pure chemical Total mass of sample % purity = x 100 88.5 Total mass of sample = 84.5g X 100 88.5 Total mass of sample = 95.5 grams