2 DIMENSIONAL KINEMATICS MIT C.P. PHYSICS 2 DIMENSIONAL KINEMATICS

Zero Angle Projectile Motion

Zero Angle Projectile Motion

Zero Angle Projectile Motion

Zero Angle Projectile Motion

Zero Angle Projectile Motion

Zero Angle Projectile Motion Which Ball Will Hit The Ground First?

Zero Angle Projectile Motion Neither!!!!

Lab: Zero Angle Trajectory Interactive

Lab: Zero Angle Trajectory Data Chart 1 Trial # Height (m) Angle (°) Speed (m/s) Range (m) Time (s) 1 25 15 2 50 3 75 4 100

Lab: Zero Angle Trajectory Data Chart 2 Trial # Height (m) Angle (°) Speed (m/s) Range (m) Time (s) 1 100 30 2 40 3 50 4 60

Formulas Time Range Height Velocity h = 1/2gt^2 v = d/t t = √2h/g d = vt v = gt t = d/v

Sample Problem 1 A student rolls a ball with a velocity of 35 m/s off a flat table 1.6 m above the floor. How long does it take to hit the ground? How far does the ball land away from the table? t = √2h/g Step 1 t = √2(1.6)/9.81 Step 2 t = 0.57 s Step 3

Sample Problem 1 A student rolls a ball with a velocity of 35 m/s off a flat table 1.6 m above the floor. How long does it take to hit the ground? How far does the ball land away from the table? Step 1 d = vt Step 2 d = (35)(0.57) Step 3 d = 20. m

How long does it take to hit the ground? How high is the building? Sample Problem 2 A student rolls a ball with a velocity of 20.0 m/s off a roof. It lands 82.0 m away from the building. How long does it take to hit the ground? How high is the building? t = d/v Step 1 t = 82/20.0 Step 2 t = 4.10 s Step 3

How long does it take to hit the ground? How high is the building? Sample Problem 2 A student rolls a ball with a velocity of 20.0 m/s off a roof. It lands 82.0 m away from the building. How long does it take to hit the ground? How high is the building? Step 1 h = ½ gt^2 Step 2 h = ½(9.81)(4.10)^2 Step 3 h = 82.5 m

Problem Two cannons, each at a different height, aim directly at each other. What will happen if both cannons fire at the same time at each other?

Answer

Launch Angle Trajectory

Launch Angle Trajectory Demo

Velocity & Launch Angle Range & Time & Height Velocity & Launch Angle

Lab: Validating Projectile Formulas Interactive

Lab: Validating Projectile Formulas Data Chart 1 Trial # Velocity (m/s) Angle (°) Height (m) Range (m) 1 6 70 2 10 3 14 4 18 5 21

Lab: Validating Projectile Formulas Data Chart 2 Trial # Velocity (m/s) Angle (°) Height (m) Range (m) 1 15 10 2 20 3 30 4 40 5 50 6 60 7 70 8 80

Formulas Range d = v^2 sin2Θ/g

Which launch angle (30°,45°,60°)will give you the maximum range? Sample Range Problem Which launch angle (30°,45°,60°)will give you the maximum range? Step 1: d = v^2 sin2Θ/g Step 2: d = 1^2 sin2(30°) (9.81) d = 1^2 sin2(45°) (9.81) d = 1^2 sin2(60°) (9.81)

Which launch angle (30°,45°,60°)will give you the maximum range? Sample Range Problem Which launch angle (30°,45°,60°)will give you the maximum range? 0.107 m 0.159 m 0.107 m Home Run

Formulas Range Height d = v^2 sin2Θ/g h = v^2 sinΘ/2g

Sample Height Problem A ball is kicked up into the air at 35.0°. Its initial velocity was 25.0m/s. How high will the ball travel? Step 1: h = v^2(sinΘ)/2g Step 2: h = (25.0)^2(sin35.0°) 2(9.81) Step 3: 18.2m

Formulas Range Height Time d = v^2 sin2Θ/g h = v^2 sinΘ/2g T = 2v sinΘ/g

Lab: Determine the Velocity of a Marble Launcher

Lab: Determine the Velocity of a Marble Launcher Data Chart Trial # Angle (°) Distance (m) 1 2 3 4 5

Formulas Velocity Velocity Velocity v = √dg/sin2Θ v = √h2(g)/sinΘ v = Tg/sin2Θ

Sample Velocity Problem A ball is kicked up into the air at 35.0°. It lands 8.01 meters away. What was its initial velocity? Step 1: v = √dg/sin2Θ Step 2: v = √(8.01)(9.81) sin2(35°) Step 3: 9.14 m/s

Lab: Delude Challenge

Test Review Game Added Points Score(Single) Score(Double) 1 3000 1500 2 3500 1750 3 4000 2000 4 4500 2250 5 5000 2500 6 5500 2750 7 6000 8 6500 3250 9 7000 10 7500 3750

Lab: Determine the Velocity of a Potato Launcher