CS 3630 Database Design and Implementation

Joins Retrieve data from two or more tables Join Conditions PK and FK (Natural Join) Other attributes (Theta Join) Based on Cartesian Product Implementation Nested loops Optimization

Tables Schemas Assignment 7

Joins List all guests who have at least one booking. (We keep all guests even they don’t have any bookings.) -- Which table(s)? -- Guest (Guest_no, Guest_Name, Address) -- PK: Guest_no -- Booking (HoteL_no, Guest_no, ...) -- PK: Hotel_no, Guest_No, Date_From -- FK: Guest_no references Guest Select Guest.* From Guest, Booking Where Guest.Guest_no = Booking.Guest_no;

Joins: New Style Select Guest.* From Guest, Booking Where Guest.Guest_no = Booking.Guest_no; From Guest Join Booking on Guest.Guest_no = Booking.Guest_no; We use the new style! -- Run in Oracle -- Duplicate records

Joins List all guests who have at least one booking. Select Guest.* From Guest Join Booking on Guest.Guest_no = Booking.Guest_no; Why duplicate records? For every g in Guest For every b in Booking If g.Guest_no = b.Guest_no Then Select g.*

Always remove duplicate records! Joins Always remove duplicate records! Select Distinct Guest.* From Guest Join Booking on Guest.Guest_no = Booking.Guest_no; Select Unique Guest.*

Using Short Table Names List all guests who have at least one booking. Select Distinct G.* From Guest G Join Booking B on G.Guest_no = B.Guest_no; Pause -- Cannot use the original table name any more Select Distinct Guest.* on Guest.Guest_no = B.Guest_no; ERROR at line 1: ORA-00904: "GUEST"."GUEST_NO": invalid identifier

Joins List all guests who have at least one booking with the details of each booking. -- No need for Distinct -- All columns from both tables Select * From Guest G Join Booking B on G.Guest_no = B.Guest_no; Set linesize 100 Col Guest_name Format a14 Heading “Guest Name” Col address format a21

Joins What if no common attribute is specified? Select G.* From Guest G, Booking B; -- Where G.Guest_no = B.Guest_no; -- Cartesian product! Select Distinct G.* From Guest G Join Booking B; -- on G.Guest_no = B.Guest_no; ERROR at line 3: ORA-00905: missing keyword

Join not on PK/FK List all guests who are in a city where there is also a hotel. Assuming Address is City. Select Distinct G.* From Guest G Join Hotel H on G.Address = H.Address;

Joins: Three Tables List Hotel name, guest name and date_from for all bookings, sorted by hotel_no in ascending order and then by guest_no in descending order. Which tables? Hotel Name: Hotel Guest Name: Guest Date_From : Booking Select H.name, G.Guest_name, Date_from From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Join Guest G on G.Guest_no = B.Guest_no Order By H.Hotel_No, G.Guest_no desc; -- H.Hotel_No, G.Guest_no not selected

Joins: Three Tables -- List Hotel name, guest name and date_from -- for all bookings. -- Sort the result Select H.name, G.Guest_name, Date_from From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Join Guest G on G.Guest_no = B.Guest_no Order By H.name, G.Guest_name, Date_from; -- Sort by name, Guest_name, Date_from; Order By H.Hotel_No, G.Guest_no; -- Sort by Hotel_No, Guest_no;

Joins with Group By -- For each hotel, display Hotel name and number of -- bookings of the hotel. -- Tables: -- Hotel, Booking Select name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Group by H.Hotel_No; -- Will it work?

Joins with Group By -- For each hotel, display Hotel name and number of -- bookings of the hotel. -- Tables: -- Hotel, Booking -- Must also Group by name Select name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Group by H.Hotel_No, name; -- What if group by name only?

Joins with Group By -- For each hotel, display Hotel name and -- number of bookings of the hotel. Select name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Group by H.Hotel_No, name; -- Missing hotels without bookings -- How to display a zero for such hotels? Select * From hotel;

Current Year with Assumption -- For each hotel, display Hotel number with hotel name -- and number of bookings of the hotel for this year. -- Assume no booking is longer than 1 year. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no and ((to_char(Date_From, 'yyyy') = to_char(SysDate, 'yyyy')) or (to_char(Date_To, 'yyyy') = to_char(SysDate, 'yyyy'))) Group by H.Hotel_No, name;

Be Careful about And/Or -- For each hotel, display Hotel number with hotel name -- and number of bookings of the hotel for this year. -- Assume no booking is longer than 1 year. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no and to_char(Date_From, 'yyyy') = to_char(SysDate, 'yyyy') or to_char(Date_To, 'yyyy') = to_char(SysDate, 'yyyy') Group by H.Hotel_No, name; -- and ((to_char(Date_From, 'yyyy') = to_char(SysDate, 'yyyy')) -- or -- (to_char(Date_To, 'yyyy') = to_char(SysDate, 'yyyy')))

Join and Where -- For each hotel, display Hotel number with hotel name -- and number of bookings of the hotel for this year. -- Assume no booking is longer than 1 year. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Where to_char(Date_From, 'yyyy') = to_char(SysDate, 'yyyy') or to_char(Date_To, 'yyyy') = to_char(SysDate, 'yyyy') Group by H.Hotel_No, name; -- could use where after join condition -- Same result for the query -- But one is Join condition -- the other is selection condition -- We should do it this way!

Current Year without Assumption -- For each hotel, display Hotel number with hotel name -- and number of bookings of the hotel for this year. -- No assumptions: booking could be longer than one year. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Where to_char(Date_From, 'yyyy') = to_char(SysDate, 'yyyy') or to_char(Date_To, 'yyyy') = to_char(SysDate, 'yyyy') (to_char(Date_From, 'yyyy') < to_char(SysDate, 'yyyy') and to_char(Date_To, 'yyyy') > to_char(SysDate, 'yyyy')) Group by H.Hotel_No, name;

Current Year without Assumption -- For each hotel, display Hotel number with hotel name -- and number of bookings of the hotel for this year. -- No assumptions. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Where to_char(Date_From, 'yyyy') <= to_char(SysDate, 'yyyy') and to_char(Date_To, 'yyyy') >= to_char(SysDate, 'yyyy') Group by H.Hotel_No, name; -- How to make it work for the current month? -- Use ‘yyyy mm’ -- Not ‘yyyy’ -- Not ‘mm yyyy’

Group By and Having -- For each hotel with at least 3 bookings this -- year, display Hotel number with the name and the number -- of bookings of the hotel this year. -- With assumption Select H.Hotel_no, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Where to_char(sysDate, 'yyyy') = to_char(date_to, 'yyyy') or to_char(sysDate, 'yyyy') = to_char(date_from,'yyyy') Group by H.Hotel_No, name Having Count(*) >= 3;

Group By and Having -- For each hotel with more than 5 bookings, -- display Hotel number with name and the number -- of bookings of the hotel. Select H.Hotel_No, name, count(*) From Hotel H Join Booking B on H.Hotel_no = B.Hotel_no Group by H.Hotel_No, name Having Count(*) > 5;

Joins Due Tuesday, April 25 Assignment 9 Joins Due Tuesday, April 25

Friday, April 14? Based on Assignment 8 Quiz 3 Friday, April 14? Based on Assignment 8