Signs and Tightropes Answers

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Presentation transcript:

Signs and Tightropes Answers 1. A sign is suspended as seen at right. The tension in the chain is 550 N and sign weighs 360 N. Find the angle the makes with the horizontal. x EAT 360 N The tension vector can be broken into components; the vertical component must match the weight 550 N 360 N x Then the angle can be found from opp 360 sin x = = = 0.655 hyp 550 x = sin -1 ( 0.655 ) = 40.9o

Signs and Tightropes Answers 2. A sign is suspended as seen at right. The sign weighs 400 N and the chain makes an angle of 35o with the horizontal. Find the tension in the chain. 35o 400 N JOE’S T The tension vector can be broken into components; the vertical component must match the weight 400 N 35o From SOH-CAH-TOA: opp 400 T 400 T sin 35 = = T = hyp T sin 35 T sin 35 = 400 T = 697 N sin 35 sin 35

4. A tightrope walker of mass 60 kg is standing in the middle of a tightrope 20.0 m long. The angle that the rope makes with the horizontal is 5.0o. Determine the tension in the rope. T = ? 5o Wt. Wt. = m g = ( 60 kg )( 9.8 m/s2 ) = 588 N

4. A tightrope walker of mass 60 kg is standing in the middle of a tightrope 20.0 m long. The angle that the rope makes with the horizontal is 5.0o. Determine the tension in the rope. T = ? 294 N 5o 588 N opp 294 T 294 T sin 5 = = T = hyp T sin 5 T sin 5 = 294 T = 3400 N sin 5 sin 5

5. A sign is hung from a chain that can withstand a tension of 1000 N before it breaks. The chain will make a 40o with the horizontal. What is the maximum weight the sign can have without the chain breaking? 1000 N 40o opp Wt. 1000 1000 sin 40 = = hyp 1000 EAT Wt. = ? Wt. = 643 N 1000 N Wt. 40o