Design Procedure of Helical Compression Spring

Slides:



Advertisements
Similar presentations
ME 271 STRENGTH OF MATERIALS
Advertisements

Power Screw and Springs
Course Title: Strength of Materials (CVE 202)
2.2 STRUCTURAL ELEMENT Reinforced Concrete Column
ONE-WAY SLAB. ONE-WAY SLAB Introduction A slab is structural element whose thickness is small compared to its own length and width. Slabs are usually.
Chapter 17: Springs It must be confessed that the inventors of the mechanical arts have been much more useful to men than the inventors of syllogisms.
Torsion Torsional Deformation of a circular shaft,
Strength of Material-5 Torsion Dr. Attaullah Shah.
FEA as an aid to Design Andrei Lozzi 2014
Outline  Spring Functions & Types  Helical Springs  Compression  Extension  Torsional.
CTC / MTC 222 Strength of Materials Chapter 5 Torsional Shear Stress and Torsional Deformation.
CTC / MTC 222 Strength of Materials
Home Work #4 Due Date: 18 Mar, 2010 (Turn in your assignment at the mail box of S581 outside the ME general office) The solutions must be written on A4.
Design of Helical spring.
ENGR 220 Section 13.1~13.2.
Chapter 19 Springs. Chapter 19: Springs Springs Characterized By: Ability to deform significantly without failure Ability to store/release PE over large.
ME1001-BASIC MECHANICAL ENGINEERING. SYLLABUS UNIT I– MACHINE ELEMENTS– I(5 hours) Springs: Helical and leaf springs – Springs in series and parallel.
The George W. Woodruff School of Mechanical Engineering ME3180 ME 3180: Machine Design Mechanical Springs Lecture Notes 1.
1 Spring Design 101 Ritchy Froehlich General Manager Ace Wire Spring & Form Co., Inc.
ME 1001 – BASIC MECHANICAL ENGINEERING
1 Design and drawing of RC Structures CV61 Dr. G.S.Suresh Civil Engineering Department The National Institute of Engineering Mysore Mob:
Keys and Coupling Many Types of Keys and couplings, however understand how Torque is transferred in between each, and forms shearing stresses.
Mechanics of Materials – MAE 243 (Section 002) Spring 2008
Failure Criteria and stress concentration
UNIT-01. SIMPLE STRESSES & STRAINS
Strain Energy Due to Shear, Bending and Torsion Lecture No-6 J P Supale Mechanical Engineering Department SKN SITS LONAVALA Strength of Materials.
III Semester Staff: Mr. S.Paul Joshua Departmentof Mechanical Engineering.
Deformation of Axially Loaded Members - Single Member
Unit-5. Torsion in Shafts and Buckling of Axially Loaded Columns Lecture Number-3 Mr. M.A.Mohite Mechanical Engineering S.I.T., Lonavala.
Structural Drafting Shear stress in Bolts. Fastener Loads and Stresses Load:External force applied to a member. Stress: Internal force acting on a member.
Mechanics of Materials – MAE 243 (Section 002) Spring 2008 Dr. Konstantinos A. Sierros.
364 書名: Essentials of Mechanical Engineering Design, 1/E 作者: Shigey Mischke Budynas 書號: MX0398.
Strain Energy Lecture No-5 J P Supale Mechanical Engineering Department SKN SITS LONAVALA Strength of Materials.
TITLE A cotter is a flat wedge shaped piece of rectangular cross-section and its width is tapered (either on one side or both sides) from one end to.
An-Najah National University Faculty of Engineering Department Of Mechanical Engineering Electricity Generation Using Speed Breakers Submitted to : Dr.
1. Two rods, one of nylon and one of steel, are rigidly connected as shown in Fig. P.1.2. Determine the stresses and axial deformations when an axial load.
UNIT-1 MACHINE ELEMENTS-1 Part – A Springs
Mechanics of Solids (M2H321546)
Design of Springs.
FEA as an aid to Design Andrei Lozzi 2017
Mechanical Principles and Applications
STRENGTH OF MATERIALS(1)
SPRINGS.
MADE BY: YASH SHAH( ) SHIVANG PATEL( ) SHIVANI SISODIA( )
Muhannad Al_Waily_Machines Systems Design
STRENGTH OF MATERIALS UNIT – III Torsion.
Jasmeen Kaur Dhillon Asst.Proffesor Mechanical Department
Stress and Strain – Axial Loading
Poisson’s Ratio For a slender bar subjected to axial loading:
Stress and Strain – Axial Loading
Keys and Coupling Many Types of Keys and couplings, however understand how Torque is transferred in between each, and forms shearing stresses.
Overview of Loads ON and IN Structures / Machines
3 Torsion.
PREPARED BY R.A.ARUL RAJA ASSISTANT PROFESSOR SRM UNIVERSITY
AHMEDABAD INSTITUTE OF TECHNOLOGY
Engineering materials lecture #12
Poisson’s Ratio For a slender bar subjected to axial loading:
Revision for Mechanics of Materials
Stresses, Strains and Deflections of Steel Beams in Pure Bending
3 Torsion.
Ch. 2: Fundamental of Structure
Theory of Simple Bending
Factors in spring design Materials Torsional
Compression Test of Steel Columns
Strength of Material Torsion Dr. Attaullah Shah.
Copyright ©2014 Pearson Education, All Rights Reserved
Poisson’s Ratio For a slender bar subjected to axial loading:
Experiment 13 Spring.
Simple Stresses & Strain
Tutorial.
Presentation transcript:

Design Procedure of Helical Compression Spring

Process Step.1 For the given application, estimate the maximum spring force P and the corresponding required deflection δ of the spring. Step.2 Select a suitable spring material and find out ultimate shear strength from design data hand book (table no.11.8).Calculate the permissible shear stress for the spring wire by following relationship τ = .30 to 0.50 τult

Process…. Step.3 Assume a suitable value for spring index c from design data book (Fig.11.1). Step.4 Calculate the Wahl-factor by the following equation K = 4c-1 + 0.615………….11.2b 4c-4 c Step.5 Determine wire diameter d by equation τ = K x (8Wc)…...............11.1a πd2

Process… Step.6 Determine mean coil diameter D by the following equation D = cxd ……………………………..11.2c Step.7 Determine the number of active coils n from axial deflection of the spring by following equation δ = 8WD3n …………………………11.5a Gd4 In general modulus of rigidity G for steel wires is 81370 N/mm2

Process… Step.8 Decide the style of ends for the spring depending upon the configuration of the application. Determine the number of inactive coils. Adding active na and inactive nina coils, find out the total number of coils nt by the following equation nina = nt - na Step.9 Determine the solid length of the spring by the following equation ls = nt x d Step.10 Determine the angular deflection of the spring θ = 16WD2n…………………………….11.4 Gd4

Process…. Step.11 Assume a gap of 0.5 to 2mm between two adjacent coils, when the spring is under the action of maximum load. The total axial gap is given by, Total gap ntgap = (nt -1)x gap between two adjacent coils. In some cases, the total axial gap is taken as 15% of the maximum deflection. Step.12 Determine the free length of the spring by the following equation Free length = solid length + total gap+ max deflection lf = ls + δmax + ntgap ………………11.20

Process… Step.13 Determine the pitch of the coil by the following equation p = Free length (nt -1) Step.14 Determine the rate of spring by following equation k = Gd4 8D3 n …………………………11.5c

Process.. Step.14 Energy stored in helical springs of circular wire U= V x τ 2 …………………………….11.4 4GK2 Where V volume of the spring wire = Length of the spring wire x cross sectional area of wire