2: Intermolecular forces

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Intermolecular forces and solubility
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Presentation transcript:

2: Intermolecular forces Date Lesson Outcomes Task 1: I can carry out experiments to study the solubility of simple molecules in different solvents (GRADE C) Task 2: I can interpret given information about solvents and solubility to explain the choice of solvents in given contexts, discussing the factors that determine the solubility including: i the solubility of ionic compounds in water in terms of the hydration of the ions ii the water solubility of simple alcohols in terms of hydrogen bonding iii the insolubility of compounds that cannot form hydrogen bonds with water molecules, eg polar molecules such as halogenoalkanes iv the solubility in non-aqueous solvents of compounds which have similar intermolecular forces to those in the solvent (GRADE B) Task 3: (GRADE A)

BIG picture What skills will you be developing this lesson? Numeracy Literacy Team work Self management Creative thinking Independent enquiry Participation Reflection How is this lesson relevant to every day life? (WRL/CIT)

Connector What is solubility? Give examples. Which of the following will make a solution? Salt in water Salt in alcohol Salt in acid Oil in water Oil in pentane Water is a very good solvent (aqueous solvent). Other solvents are called Non-aqueous solvents. Hexane, paraffin etc. are called Organic solvents.

Experiment 1: Solubility of iodine in different solvents (Task 1) Put a small crystal of iodine into a test tube. Add 5 cm3 of distilled water and put a bung on the tube and shake. Try to decide roughly how soluble iodine is in water. Repeat steps A–C but using the solvents ethanol and then (cyclo)hexane Record your observations. Experiment 2: Solubility of sucrose in different solvents Repeat steps A–E of experiment 1 but this time using sucrose instead.

From the amount of silver chloride precipitated, judge the solubility. Experiment 3: Solubility of calcium chloride in different solvents Task 1 (Grade C) Repeat experiment 1, steps A–C using calcium chloride instead of iodine, But to estimate the relative solubility in each solvent silver nitrate solution will be used to roughly determine the amount of Cl– ions a released. After shaking the test tube, decant the liquid into another test tube, leaving any excess calcium chloride behind. Add around 1 cm3 of silver nitrate solution. From the amount of silver chloride precipitated, judge the solubility.

Questions For each of the three substances answer the following questions. What sort of intramolecular forces, if any are within the particles? What sort of intermolecular forces exist between the particles? Explain the relative solubility in each of the three solvents.

Patterns in solubility Like dissolves like. True or False? Justify your answer.

How can I improve on task 1? Task 1: Review Go back to your lesson outcome grid and fill out the ‘How I did’ and the ‘Targets’ column. Lesson Outcomes How I did Targets Task 1: Grade C Met? Partly met? Not met? How can I improve on task 1?

Ions in ionic solids - Cl- Some other ionic solids have different lattice structures Cl- Na+ Opposite charged anions and cations are held together by electrostatic forces. In a lattice, Each ion is surrounded by six oppositely charged ions. Energy is required to break down the ionic lattice and this is called Lattice energy. + - Sodium chloride crystals are made up of ions in an ionic lattice. Electrostatic attractions hold the ions together. Each Na+ ion is closely surrounded by 6 Cl- ions and each Cl- ion is closely surrounded by 6 Na+ ions. The nearest neighbours for each ion have an opposite charge and so attractions are stronger than repulsions in an ionic lattice.The lattice has a cubic shape and this accounts for the cubic shapes of salt crystals. Try Q6 in CI 5.2.

Dissolving an ionic solid in water http://programs.northlandcollege.edu/biology/Biology1111/animations/dissolve.html

= - Ions in solution O Hydrated ions Oδ- δ+ δ- δ+ δ- Hydrated ions - δ+ δ- δ+ δ- δ+ δ- δ+ δ- Water molecules form bonds with ions and energy is released called Hydration energy. + δ+ δ- δ+ δ- More electronegative Polar molecules δ+ δ- Oxygen is more electronegative than hydrogen, the bonds are polar. Because of the bent shape of the water molecule, the water molecules themselves are polar. The polar water molecules are attracted to the now separated ions. The ions are said to be hydrated. O Oδ- = H Hδ+ H Hδ+

- - - - - Some bonds made Some bonds broken + + + + δ+ δ- δ+ δ- δ+ δ- Water molecules are attracted to the ions in the lattice. Bonds between water molecules are broken but bonds between water molecules and the ions are made. - - δ+ δ- δ+ δ- + δ+ δ- δ+ δ- δ+ δ- δ+ δ-

- - - - - Some bonds broken Some bonds made + + + + Ionic bonds between ions in the lattice break and more water molecules are attracted to the separated ions. - - +

- - - - - Some bonds made Some bonds broken Dissolving Ion – ion bonds are broken. (Lattice energy) Ion – water bonds are made. (Hydration energy) + - + - + Some bonds broken Eventually, all the ionic lattice will have been broken apart. The energy required for bond breaking is provide by exothermic bond making. - - +

Dissolving ionic solid in water

New Information for Task 2

Solubility of alcohols in water

Solubility of alcohols in water Alcohols are soluble in water because they have polar hydroxyl group (-OH group) that can make hydrogen bond to the –OH group in water molecules. What will happen to the solubility of alcohols in water as the size of alcohols increases? Solubility of alcohols decreases because a smaller proportion of the molecule is polar. What will be the trend of carboxylic acids solubility in water?

Solubility of hexane in water Why are non-polar substances insoluble in water?

Solubility of halogenoalkane in water

Mixing two organic liquids

Questions

Answers

Temperature and Solubility 12/10/99 Temperature and Solubility The factors that determine solubility are the strength of IMFs and speed of molecules. Solubility is influenced by temperature. In warmer water, more solid will dissolve. This is because a high temperature means H2O molecules are moving faster (keeping more solid molecules suspended). Conversely a gas will be less soluble at a higher temperature. This is because when gas molecules are moving faster they are able to escape from the liquid surface. Think of cold soda vs. warm soda. Warm soda goes flat faster.

How can I improve on task 2? Task 2: Review Go back to your lesson outcome grid and fill out the ‘How I did’ and the ‘Targets’ column. Lesson Outcomes How I did Targets Task 2: Grade B Met? Partly met? Not met? How can I improve on task 2?

Homework Homework task: Due date: Criteria for Grade C: Criteria for Grade B: Criteria for Grade A:

Review of lesson