Introduction Polynomials are often added, subtracted, and even multiplied. Doing so results in certain sums, differences, or products of polynomials.

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Introduction Polynomials are often added, subtracted, and even multiplied. Doing so results in certain sums, differences, or products of polynomials appearing more commonly. Becoming familiar with certain polynomial identities can make the processes of expanding and factoring polynomials easier. 2.2.1: Polynomial Identities

Key Concepts Identities can be used to expand or factor polynomial expressions. A polynomial identity is a true equation that is often generalized so it can apply to more than one example. The tables that follow shows the most common polynomial identities, including the steps of how to work them out. 2.2.1: Polynomial Identities

Key Concepts, continued Common Polynomial Identities Square of Sums Identity Formula Steps With two variables: (a + b)2 = a2 + 2ab + b2 (a + b)2 = (a + b)(a + b) = a2 + ab + ab + b2 = a2 + 2ab + b2 With three variables: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac (a + b + c) 2 = (a + b + c)(a + b + c) = a2 + ab + ac + ab + b2 + bc + ac + bc + c2 = a2 + b2 + c2 + 2ab + 2bc + 2ac (continued) 2.2.1: Polynomial Identities

Key Concepts, continued Square of Differences Identity Formula Steps (a – b)2 = a2 – 2ab + b2 (a – b)2 = (a – b)(a – b) = a2 – ab – ab + b2 = a2 – 2ab + b2 Difference of Two Squares Identity Formula Steps a2 – b2 = (a + b)(a – b) a2 – b2 = a2 + ab – ab + b2 = (a + b)(a – b) (continued) 2.2.1: Polynomial Identities

Key Concepts, continued Sum of Two Cubes Identity Formula Steps a3 + b3 = (a + b)(a2 – ab + b2) a3 + b3 = a3 – a2b + ab2 + a2b – ab2 + b3 = (a + b)(a2 – ab + b2) Difference of Two Cubes Identity Formula Steps a3 – b3 = (a – b)(a2 + ab + b2) a3 – b3 = a3 + a2b + ab2 – a2b – ab2 – b3 = (a – b)(a2 + ab + b2) 2.2.1: Polynomial Identities

Key Concepts, continued Note that the square of sums, (a + b)2, is different from the sum of squares, a2 + b2. Polynomial identities are true for any values of the given variables. When dealing with large numbers, the use of identities often results in simpler calculations. 2.2.1: Polynomial Identities

Common Errors/Misconceptions confusing identities, such as applying the Square of Differences Identity instead of the Difference of Two Squares Identity incorrectly applying an identity to find an equivalent expression misplacing a negative sign in an identity, resulting in an incorrect equivalent expression 2.2.1: Polynomial Identities

Guided Practice Example 1 Use a polynomial identity to expand the expression (x – 14)2. 2.2.1: Polynomial Identities

Guided Practice: Example 1, continued Determine which identity is written in the same form as the given expression. The expression (x – 14)2 is written in the same form as the left side of the Square of Differences Identity: (a – b)2 = a2 – 2ab + b2. Therefore, we can substitute the values from the expression (x – 14)2 into the Square of Differences Identity. 2.2.1: Polynomial Identities

Guided Practice: Example 1, continued Replace a and b in the identity with the terms in the given expression. For the given expression (x – 14)2, let x = a and 14 = b in the Square of Differences Identity. 2.2.1: Polynomial Identities

Guided Practice: Example 1, continued The rewritten identity is (x – 14)2 = x2 – 2(x)(14) + 142. (x – 14)2 Original expression (a – b)2 = a2 – 2ab + b2 Square of Differences Identity [(x) – (14)]2 = (x)2 – 2(x)(14) + (14)2 Substitute x for a and 14 for b in the Square of Differences Identity. 2.2.1: Polynomial Identities

Guided Practice: Example 1, continued Simplify the expression by finding any products and evaluating any exponents. The first term, x2, cannot be simplified further, but the other terms can. 2.2.1: Polynomial Identities

✔ Guided Practice: Example 1, continued When expanded, the expression (x – 14)2 can be written as x2 – 28x + 196. (x – 14)2 = x2 – 2(x)(14) + 142 Equation from step 2 = x2 – 28x + 142 Simplify 2(x)(14). = x2 – 28x + 196 Square 14. ✔ 2.2.1: Polynomial Identities

Guided Practice: Example 1, continued http://www.walch.com/ei/00657 2.2.1: Polynomial Identities

Guided Practice Example 2 Use a polynomial identity to factor the expression x 3 + 125. 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued Determine which identity is written in the same form as the given expression. The first term in the expression, x 3, is a cube. Determine whether the second term in the expression, 125, is also a cube. 125 = 5 • 25 = 5 • 5 • 5 = 53 Since 125 can be rewritten as a cube, the expression x 3 + 125 can be rewritten as x 3 + 53. 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued The identity a3 + b3 = (a + b)(a2 – ab + b2) is in the same form as x 3 + 53. Therefore, the expression x3 + 125, rewritten as x 3 + 53, is in the same form as the left side of the Sum of Two Cubes Identity: a3 + b3 = (a + b)(a2 – ab + b2). 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued Replace a and b in the identity with the terms in the given expression. For the rewritten expression x 3 + 53, let x = a and 5 = b in the Sum of Two Cubes Identity. 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued The rewritten identity is x3 + 53 = (x + 5)[x2 – (x)(5) + 52]. x3 + 53 Rewritten expression a3 + b3 = (a + b)(a2 – ab + b2) Sum of Two Cubes Identity (x)3 + (5)3 = [(x) + (5)][(x)2 – (x)(5) + (5)2] Substitute x for a and 5 for b in the Sum of Two Cubes Identity. 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued Simplify the expression by finding any products and evaluating any exponents. The first factor, x + 5, cannot be simplified further. The second factor, x2 – (x)(5) + 52, has three terms: the first term, x2, cannot be simplified; the other terms, (x)(5) and 52, can be simplified. 2.2.1: Polynomial Identities

✔ Guided Practice: Example 2, continued When factored, the expression x3 + 125, which is equivalent to x3 + 53, can be rewritten as (x + 5)(x2 + 5x + 25). x3 + 53 = (x + 5)[x2 – (x)(5) + 52] Equation from the previous step = (x + 5)(x2 – 5x + 52) Simplify (x)(5). = (x + 5)(x2 + 5x + 25) Square 5. ✔ 2.2.1: Polynomial Identities

Guided Practice: Example 2, continued http://www.walch.com/ei/00658 2.2.1: Polynomial Identities