Warm – up #2 1. y< 3 2

Slides:



Advertisements
Similar presentations
3.2 Solving Systems Algebraically 2. Solving Systems by Elimination.
Advertisements

4.3 Systems of Equations - Elimination Objective: The student will be able to: Solve systems of equations using elimination with addition and subtraction.
TODAY IN ALGEBRA…  Learning Goal: 7.3 You will solve systems of linear equations by Elimination  Independent Practice  MID CH.7 TEST-MONDAY/TUESDAY!
Warm Up #4 1. Evaluate –3x – 5y for x = –3 and y = 4. –11 ANSWER
The student will be able to:
5.1 Solving Systems of Linear Equations by Graphing
3x – 5y = 11 x = 3y + 1 Do Now. Homework Solutions 2)2x – 2y = – 6 y = – 2x 2x – 2(– 2x) = – 6 2x + 4x = – 6 6x = – 6 x = – 1y = – 2x y = – 2(– 1) y =
Fri 10/16 Lesson 3 – 2 Learning Objective: To solve systems algebraically Hw: Pg. 146 #10, 16, 17, odd.
Warm Up 12/5 1) Is (-2, 3) a solution? 3x + y = -3 3x + y = -3 2x – 4y = 6 2x – 4y = 6 2) Find the solution by graphing y = -4 + x x + y = 6 3) Solve:
Warm Up:  1) Name the three parent functions and graph them.  2) What is a system of equations? Give an example.  3) What is the solution to a system.
Objective The student will be able to: solve systems of equations using substitution. SOL: A.9.
Warm up 12/6 or 7 1) Write the equation of a line that is parallel to y = -3x –5 and goes through the point (6,10). 2) Write the equation of a line that.
Solving Systems Using Elimination
You sell tickets for admission to your school play and collect a total of $104. Admission prices are $6 for adults and $4 for children. You sold 21 tickets.
 What is the slope of the line that passes through the following points. 1.(-2, 5) (1, 4)  Identify the slope and y -intercept of each equation. 2.y.
WARM – UP #2 10/16/15 Fri HW: Pg. 146 #10, 16, 17, odd.
Solving by Substitution Method or Elimination (Addition) Method
Essential Questions: When and how do you solve a system of equations using the substitution method? When and how do you solve a system of equations using.
Homework Log Wed 10/14 Lesson 3 – 1 Learning Objective: To solve systems by graphing Hw: Pg. 138 #7-13, 29, 31, 34.
Solving System of Equations that have 0, 1, and Infinite Solutions
Warm – up #1 Hw:pg 301 # 12-15, 21, 23, ODD (skip 45)
Section 4.1 Systems of Linear Equations in Two Variables.
Solve by Graphing Solve: 3x + 4y = - 4 x + 2y = 2
1.. Wed 10/21 Lesson 3 – 5 Learning Objective: To solve systems with three variables Hw: Pg. 171 # 21 – 29 odd.
Solving Systems of Equations by Elimination Name: Pd Algebra 3/03/09.
3-2 Solving Systems Algebraically. In addition to graphing, which we looked at earlier, we will explore two other methods of solving systems of equations.
Solving Systems by Elimination 5.4 NOTES, DATE ____________.
TODAY IN ALGEBRA…  Warm Up: Review solving Multi-step equations  15 minutes: Finish Mid-Ch.3 Test  Learning Goal: 3.4 You will solve equations with.
Homework Log Wed 10/21 Lesson 3 – 5 Learning Objective: To solve systems with three variables Hw: Pg. 172 # odd Attention!! Pass up yesterday’s HW.
3.2 Solve Linear Systems Algebraically Algebra II.
Solving Systems of Linear Equations in 2 Variables Section 4.1.
Algebra 1 Review Systems of Linear Equations Using Substitution
Homework.
Objective I can solve systems of equations using elimination with addition and subtraction.
Solve by Graphing Solve: 3x + 4y = - 4 x + 2y = 2
10.1 SYSTEMS OF LINEAR EQUATIONS: SUBTRACTION, ELIMINATION.
Do Now  .
ALGEBRA 1 CHAPTER 7 LESSON 5 SOLVE SPECIAL TYPES OF LINEAR SYSTEMS.
Do Now  .
Warm Up x = y – 3 9 – 3x 12 9 Simplify each expression.
Elimination Method Day 1
5.3 Elimination Using Addition and Subtraction
Warm-Up Graph Solve for y: Graph line #2.
Warm – up #2 1.
Solving Systems of Two Equations
Honors Algebra II 3.5 Solving Systems with Three Variables.
3-2 Solving Systems Algebraically: Substitution Method
Solving Systems of Equations with Substitution
The student will be able to:
Warm-Up 2-1.
The student will be able to:
The student will be able to:
The student will be able to:
Equations with Variables on Both Sides
infinitely many solutions
The student will be able to:
Lesson Objectives: I will be able to …
SYSTEMS OF LINEAR EQUATIONS
Section Solving Linear Systems Algebraically
Solving Systems of Equations
Assignment Questions? Pg #13- (-2, 1) #14- (3, -4) #16- (-4, 6) # T-Shirts #50- (3, 3) #53- No Solution #54- (-5, -3) #58- Infinite Solutions.
Solving Systems Using Elimination
Solving Systems of Two Equations
7.1 Solving Systems of Equations
The student will be able to:
3.2 Solving Linear Systems Algebraically
Lesson 0 – 8 Systems of Linear Equations
The student will be able to:
Warm – up #4 1. Evaluate
Warm – up #6 1. 3
Presentation transcript:

Warm – up #2 1. y< 3 2 𝑥−6 x≤4

Homework Log Fri 10/16 Lesson 3 – 2 Learning Objective: To solve systems algebraically Hw: Pg. 146 #10, 16, 17, 23-39 odd

10/10&11/17 Lesson 3 – 2 Solving Systems Algebraically Algebra II

Learning Objective To solve systems by substitution To solve systems by elimination

Solve by Substitution Get a variable by itself in one equation Plug into other equation to solve Plug solved variable back into one eq’n to solve for other variable Solution is where the two lines will intersect

Solutions of Systems 0 = 5  Never True!! No Solution Parallel Lines 5 = 5  Always True!! Infinite Solutions Same Line

Solve by Substitution x – 7y = 11 1. 𝑥−7𝑦=11 5𝑥+4𝑦=−23 +7y +7y 1. 𝑥−7𝑦=11 5𝑥+4𝑦=−23 5(7y + 11) + 4y = - 23 35y + 55 + 4y = - 23 39y = - 78 y = -2 x – 7(-2) = 11 x + 14 = 11 x = -3 Now plug y = -2 into either equation to solve for x. (-3, -2)

Solve by Substitution -2x + y = 3 2. 2𝑥−𝑦=−6 −2𝑥+𝑦=3 +2x +2x 2. 2𝑥−𝑦=−6 −2𝑥+𝑦=3 2x – (2x + 3) = - 6 2x – 2x – 3 = -6 -3 = -6 No Solution! Lines are parallel & will never intersect!

Solve by Substitution 5x + y = -5 3. 6𝑥+2𝑦=−10 5𝑥+𝑦=−5 -5x -5x 3. 6𝑥+2𝑦=−10 5𝑥+𝑦=−5 6x + 2(-5x – 5) = -10 6x – 10x – 10 = -10 -4x = 0 x = 0 6(0) + 2y = -10 2y = -10 y = - 5 (0, -5)

Solve by Elimination Pick one variable and get opposite coefficients Add straight down & solve Plug solved variable back into one eq’n to solve for other variable Solution is where the two lines will intersect

Solve by Elimination 4. 4𝑥+2𝑦=9 −4𝑥+3𝑦=16 5y = 25 y = 5 4x + 2(5) = 9 4. 4𝑥+2𝑦=9 −4𝑥+3𝑦=16 Since “x” already have opposite coefficients of 4 and -4, just add straight down 5y = 25 y = 5 4x + 2(5) = 9 4x + 10 = 9 4x = -1 x=− 1 4 (− 1 4 , 5)

Solve by Elimination −6𝑥−𝑦=27 6𝑥+16𝑦=18 5. −6𝑥−𝑦=27 3𝑥+8𝑦=9 (2)( ) (2) 5. −6𝑥−𝑦=27 3𝑥+8𝑦=9 −6𝑥−𝑦=27 6𝑥+16𝑦=18 (2)( ) (2) 15y = 45 y = 3 3x + 8(3) = 9 3x + 24 = 9 3x = -15 x = -5 (-5, 3)

Solve by Elimination 6𝑥−5𝑦=−8 −4𝑥+5𝑦=12 6. 6𝑥−5𝑦=−8 4𝑥−5𝑦=−12 6. 6𝑥−5𝑦=−8 4𝑥−5𝑦=−12 6𝑥−5𝑦=−8 −4𝑥+5𝑦=12 (-1)( ) (-1) 2x = 4 x = 2 6(2) – 5y = -8 12 – 5y = -8 -5y = -20 y = 4 (2, 4)

Solve by Elimination (-3)( ) (-3) 7. 5𝑥+3𝑦=52 15𝑥+9𝑦=54 0 = -102 (-3)( ) (-3) 7. 5𝑥+3𝑦=52 15𝑥+9𝑦=54 −15𝑥−9𝑦=−156 15𝑥+9𝑦=54 0 = -102 Parallel Lines! No Solution

Solve by Elimination (-3)( ) (-3) −6𝑥−9𝑦=−15 6𝑥+9𝑦=15 (-3)( ) (-3) 8. 2𝑥+3𝑦=5 6𝑥+9𝑦=15 −6𝑥−9𝑦=−15 6𝑥+9𝑦=15 0 = 0 Same Line! Infinite Solutions

Solve by Elimination (-4)( ) (-4) 9. 4𝑥+3𝑦=12 −6𝑥+4𝑦=−1 (3)( ) (3) (-4)( ) (-4) 9. 4𝑥+3𝑦=12 −6𝑥+4𝑦=−1 −16𝑥−12𝑦=−48 −18𝑥+12𝑦=−3 (3)( ) (3) -34x = -51 x = 3 2 4( 3 2 ) + 3y = 12 6 + 3y = 12 3y = 6 y = 2 ( 3 2 , 2)

Solve by Elimination (-3)( ) (-3) 10. 2𝑥+7𝑦=4 3𝑥+5𝑦=−5 (-3)( ) (-3) 10. 2𝑥+7𝑦=4 3𝑥+5𝑦=−5 −6𝑥−21𝑦=−12 6𝑥+10𝑦=−10 (2)( ) (2) -11y = -22 y = 2 2x + 7(2) = 4 2x + 14 = 4 2x = -10 x = -5 (-5, 2)

Word Problem 11. An online photo store charges $0.15/photo plus $2.70 shipping. A local store charges $0.25 with no shipping. a) Write a cost eq’n for each store b) When would it cost the same? c) When do you use online vs. local?

Word Problem Solve by substitution 𝑦=0.15𝑥+2.70 𝑦=0.25𝑥 0.25x = 0.15x + 2.70 0.10x = 2.70 x = 27 photos would cost both $6.75 Use online store if more than 27 photos. Use local store if less than 27 photos.

Ticket Out the Door You work for Alg Comp delivering packages. Alg Comp pays you a flat rate of $9.50 per hour. Geo Comp pays employees $2 per hour plus $3 per delivery. How many deliveries would Geo Comp’s employees have to make in four hours to earn the same pay you earn in a four-hour shift?

Assignment: Pg. 146 #10, 16, 17, 23-39 odd