CRAZY CORE SKITTLES By Rachel Collins

The Purpose It is stated that the Crazy Cores Skittles Company have 56.7 grams of Skittles in each bag. Is this accurate? The population of interest is a sample size of 15 regular sized Crazy Core Skittles bags from a private supplier.

Sneaky Lurking Variables The Skittles weighed in the experiment all came from one supplier, so there is a possibility that the skittles all came from the same batch from manufacturer. The supplier from which produced the skittles does not have a license to sell, so there can be some doubt if the goods he/she were selling are standard.

More Luring Variables The efficiency of the scale is questioned due to the fact that I carried it around in my purse. My sample size is only 15, while it is large enough to perform a one sample T test, if there was a larger sample it would be able to speak for a larger amount of skittles.

Procedure Contact the skittles dealer. Weigh each bag of skittles and record the weight.

Numbers, Graphs, and Data Skittles Weight 60.1, 59.01, 59.3, 58.4 ,58.4, 59.5 ,58.6 ,62.1 ,61.9 ,57.8, 59.4 ,60.9 ,58.24 ,57.6 ,56.2

More Numbers Five number Summary Mean= 59.16 grams Minimum= 56.2 grams Maximum= 62.1 grams Q1 = 58.24 grams Q3 =60.1 grams Sx= 1.59 Medium=59.01 since the mean is greater than the medium, the graph is slightly skewed to the right.

Hypothesis Ho: In a sample size of 15 bags of Crazy Core Skittles, the mean weight is 56.7 grams. X= 56.7grams Ha: In a sample size of 15 bags of Crazy Core Skittles, the mean weight is more than 56.7 grams X>56.7 grams

Inference Procedure The significance level that the data will be tested is at .05%. The sample size is fifteen 56.7 gram Crazy Core Skittle bags. A one sample T test will be used since the population mean is unknown.

Conditions Not an SRS: PROCEED With Caution Sample size shows little to no skewness and no extreme outliers.

Box Plot

Formulas T test T= x-µ s/n df= n-1 X=59.13 µ=56.7 S=1.59 n=15 59.13-56.7 =5.979 T=5.979 P value= 1.63e-5 1.59/15

What Does The Numbers Mean? Conclusion The P- Value was 1.63e-5 at an Alpha level of .05%. This is significant evidence to reject the null Hypothesis. Therefore, In a sample size of 15 bags of Crazy Core Skittles, the mean weight is more than 56.7 grams. X>56.7 grams

Confidence Interval Test Confidence Interval for : X=59.133 T*=5.979 n=15 S=1.59 59.133+/-5.979 15-1 (1.59/√15= 58.28, 60.047

Confidence Conclusion According to the Confidence Interval test, I am 95% confident that the mean weight of Crazy Core Skittles bags lays between 58.28 grams and 60.047 grams. This supports my rejection of my null hypothesis.

Reflection My project shows me that in a population of 15 Crazy Core Skittles bags, the mean weight is more than what is stated on the bag. Some of the weakness of the project were that the data did not come from an SRS.