Chapter 6 Confidence Intervals.

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Presentation transcript:

Chapter 6 Confidence Intervals

Chapter Outline 6.1 Confidence Intervals for the Mean ( Known) 6.2 Confidence Intervals for the Mean ( Unknown) 6.3 Confidence Intervals for Population Proportions 6.4 Confidence Intervals for Variance and Standard Deviation .

Confidence Intervals for the Mean ( Unknown) Section 6.2 Confidence Intervals for the Mean ( Unknown) .

Section 6.2 Objectives How to interpret the t-distribution and use a t-distribution table How to construct and interpret confidence intervals for a population mean when  is not known .

The t-Distribution When the population standard deviation is unknown, the sample size is less than 30, and the random variable x is approximately normally distributed, it follows a t-distribution. Critical values of t are denoted by tc. .

Properties of the t-Distribution The mean, median, and mode of the t-distribution are equal to zero. The t-distribution is bell shaped and symmetric about the mean. The total area under a t-curve is 1 or 100%. The tails in the t-distribution are “thicker” than those in the standard normal distribution. The standard deviation of the t-distribution varies with the sample size, but it is greater than 1. .

Properties of the t-Distribution The t-distribution is a family of curves, each determined by a parameter called the degrees of freedom. The degrees of freedom are the number of free choices left after a sample statistic such as a point estimate. When you use a t-distribution to estimate a population mean, the degrees of freedom are equal to one less than the sample size. d.f. = n – 1 Degrees of freedom .

Properties of the t-Distribution As the degrees of freedom increase, the t-distribution approaches the normal distribution. After 30 d.f., the t-distribution is very close to the standard normal z-distribution. d.f. = 5 d.f. = 2 t Standard normal curve .

Example: Finding Critical Values of t Find the critical value tc for a 95% confidence when the sample size is 15. Solution: d.f. = n – 1 = 15 – 1 = 14 Table 5: t-Distribution tc = 2.145 .

Solution: Critical Values of t 95% of the area under the t-distribution curve with 14 degrees of freedom lies between t = +2.145. t -tc = -2.145 tc = 2.145 c = 0.95 .

Confidence Intervals for the Population Mean A c-confidence interval for the population mean μ The probability that the confidence interval contains μ is c. .

Confidence Intervals and t-Distributions In Words In Symbols Verify that  is not known, the sample is random, and the population is normally distributed or n  30. Identify the sample statistics n, , and s. .

Confidence Intervals and t-Distributions In Words In Symbols Identify the degrees of freedom, the level of confidence c, and the critical value tc. d.f. = n – 1; Use Table 5. Find the margin of error E. Find the left and right endpoints and form the confidence interval. Left endpoint: Right endpoint: Interval: .

Example: Constructing a Confidence Interval You randomly select 16 coffee shops and measure the temperature of the coffee sold at each. The sample mean temperature is 162.0ºF with a sample standard deviation of 10.0ºF. Find the 95% confidence interval for the mean temperature. Assume the temperatures are approximately normally distributed. Solution: Use the t-distribution (n < 30, σ is unknown, temperatures are approximately distributed.) .

Solution: Constructing a Confidence Interval n =16, x = 162.0 s = 10.0 c = 0.95 df = n – 1 = 16 – 1 = 15 Critical Value Table 5: t-Distribution tc = 2.131 .

Solution: Constructing a Confidence Interval Margin of error: Confidence interval: Left Endpoint: Right Endpoint: 156.7 < μ < 167.3 .

Solution: Constructing a Confidence Interval 156.7 < μ < 167.3 Point estimate 156.7 162.0 167.3 ( ) • With 95% confidence, you can say that the mean temperature of coffee sold is between 156.7ºF and 167.3ºF. .

Normal or t-Distribution? .

Example: Normal or t-Distribution? You randomly select 25 newly constructed houses. The sample mean construction cost is $181,000 and the population standard deviation is $28,000. Assuming construction costs are normally distributed, should you use the normal distribution, the t-distribution, or neither to construct a 95% confidence interval for the population mean construction cost? Solution: Use the normal distribution (the population is normally distributed and the population standard deviation is known) .

Section 6.2 Summary Interpreted the t-distribution and used a t-distribution table Constructed and interpreted confidence intervals for a population mean when  is not known .