Warm Up Check your understanding P. 586 (You have 5 minutes to complete) I WILL be collecting these.

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Presentation transcript:

Warm Up Check your understanding P. 586 (You have 5 minutes to complete) I WILL be collecting these.

9.3 – Day 2 Two-Sided Tests & Confidence Intervals The connection between two-sided tests and confidence intervals is even stronger for means than it was for proportions. That’s because both inference methods for means use the standard error of the sample mean in the calculations. A two-sided test at significance level α (say, α = 0.05) and a 100(1 – α)% confidence interval (a 95% confidence interval if α = 0.05) give similar information about the population parameter. When the two-sided significance test at level α rejects H0: µ = µ0, the 100(1 – α)% confidence interval for µ will not contain the hypothesized value µ0 . When the two-sided significance test at level α fails to reject the null hypothesis, the confidence interval for µ will contain µ0 .

Inference for Means: Paired Data Comparative studies are more convincing than single-sample investigations. For that reason, one-sample inference is less common than comparative inference. Study designs that involve making two observations on the same individual, or one observation on each of two similar individuals, result in paired data. When paired data result from measuring the same quantitative variable twice, as in the job satisfaction study, we can make comparisons by analyzing the differences in each pair. If the conditions for inference are met, we can use one-sample t procedures to perform inference about the mean difference µd. These methods are sometimes called paired t procedures.

Example: Paired data and one-sample t procedures Researchers designed an experiment to study the effects of caffeine withdrawal. They recruited 11 volunteers who were diagnosed as being caffeine dependent to serve as subjects. Each subject was barred from coffee, colas, and other substances with caffeine for the duration of the experiment. YIKES  During one two-day period, subjects took capsules containing their normal caffeine intake. During another two-day period, they took placebo capsules. The order in which subjects took caffeine and the placebo was randomized. At the end of each two-day period, a test for depression was given to all 11 subjects. Researchers wanted to know if being deprived of caffeine would lead to an increase in depression. Try Exercise 39

Example: Paired data and one-sample t procedures The table below contains data on the subjects’ scores on a depression test. Higher scores show more symptoms of depression. Results of a caffeine-deprivation study Subject Depression (caffeine) Depression (placebo) Difference (placebo – caffeine) 1 5 16 11 2 23 18 3 4 7 8 14 6 24 19 9 15 13 10 12 -1 Try Exercise 39

Example: Paired data and one-sample t procedures Problem: Why did researchers randomly assign the order in which subjects received placebo and caffeine? Researchers want to be able to conclude that any statistically significant change in depression score is due to the treatments themselves and not to some other variable. One obvious concern is the order of the treatments. Suppose that caffeine were given to all the subjects during the first 2-day period. What if the weather were nicer on these 2 days than during the second 2-day period when all subjects were given a placebo? Researchers wouldn’t be able to tell if a large increase in the mean depression score is due to the difference in weather or due to the treatments. Random assignment of the caffeine and placebo to the two time periods in the experiment should help ensure that no other variable (like the weather) is systematically affecting subjects’ responses. Try Exercise 39

Example: Paired data and one-sample t procedures Problem: (b) Carry out a test to investigate the researchers’ question. State: If caffeine deprivation has no effect on depression, then we would expect the actual mean difference in depression scores to be 0. We therefore want to test the hypotheses H0: µd = 0 Ha: µd > 0 where µd is the true mean difference (placebo - caffeine) in depression score for subjects like these. (We chose this order of subtraction to get mostly positive values.) Because no significance level is given, we’ll use α = 0.05. Try Exercise 39

Example: Paired data and one-sample t procedures Plan: If the conditions are met, we should do a paired t test for µd. • Random: Researchers randomly assigned the treatments —placebo then caffeine, caffeine then placebo— to the subjects. 10% Condition: We aren’t sampling, so it isn’t necessary to check the 10% condition. Try Exercise 39

Example: Paired data and one-sample t procedures • Normal/Large Sample: We don’t know whether the actual distribution of difference in depression scores (placebo - caffeine) is Normal. With such a small sample size (n = 11), we need to examine the data to see if it’s safe to use t procedures. The histogram has an irregular shape with so few values; the boxplot shows some right-skewness but not outliers; and the Normal probability plot is slightly curved, indicating some slight skewness. With no outliers or strong skewness, the t procedures should be pretty accurate. Try Exercise 39

Example: Paired data and one-sample t procedures Do: I entered the differences in L1 and then used the calculator’s t-test and got the following data: • Test statistic t = 3.53 • P-value 0.0027, which is the area to the right of t = 3.53 on the t distribution curve with df = 11 - 1 = 10. Try Exercise 39 Conclude: (a) Because the P-value is 0.0027, we reject H0: µd = 0. We have convincing evidence that the true mean difference (placebo - caffeine) in depression score is positive for subjects like these.

Using Tests Wisely Carrying out a significance test is often quite simple, especially if you use a calculator or computer. Using tests wisely is not so simple. Here are some points to keep in mind when using or interpreting significance tests. How Large a Sample Do I Need? A smaller significance level requires stronger evidence to reject the null hypothesis. Higher power gives a better chance of detecting a difference when it really exists. At any significance level and desired power, detecting a small difference between the null and alternative parameter values requires a larger sample than detecting a large difference.

Using Tests Wisely Statistical Significance and Practical Importance When a null hypothesis (“no effect” or “no difference”) can be rejected at the usual levels (α = 0.05 or α = 0.01), there is good evidence of a difference. But that difference may be very small. When large samples are available, even tiny deviations from the null hypothesis will be significant. Beware of Multiple Analyses Statistical significance ought to mean that you have found a difference that you were looking for. The reasoning behind statistical significance works well if you decide what difference you are seeking, design a study to search for it, and use a significance test to weigh the evidence you get. In other settings, significance may have little meaning.

Tests About a Population Mean STATE and CHECK the Random, 10%, and Normal/Large Sample conditions for performing a significance test about a population mean. PERFORM a significance test about a population mean. USE a confidence interval to draw a conclusion for a two-sided test about a population parameter. PERFORM a significance test about a mean difference using paired data.