Projectile Motion AP Physics B.

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Projectile Motion AP Physics B

Observe and Explain What is the Physics Behind ? How to Make it go further ? How to Make it go higher ? List Your Observation Take photos Explain what makes it go further and higher .

Focused Learning Target In analyzing projectile  motion , SWBAT Use vectors as a means to explain magnitude and direction to model the motion of macroscopic objects in 2 dimensions (Computation and mathematical thinking) Performance Expectations : I can derive mathematical equations from graphic representations of motion . Learning Targets : I can use mathematical equations to predict the behavior of moving objects

What is projectile? Projectile -Any object which projected by some means and continues to move due to its own inertia (mass).

Projectiles move in TWO dimensions Since a projectile moves in 2-dimensions, it therefore has 2 components just like a resultant vector. Horizontal and Vertical

Horizontal “Velocity” Component NEVER changes, covers equal displacements in equal time periods. This means the initial horizontal velocity equals the final horizontal velocity In other words, the horizontal velocity is CONSTANT. BUT WHY? Gravity DOES NOT work horizontally to increase or decrease the velocity.

Vertical “Velocity” Component Changes (due to gravity), does NOT cover equal displacements in equal time periods. Both the MAGNITUDE and DIRECTION change. As the projectile moves up the MAGNITUDE DECREASES and its direction is UPWARD. As it moves down the MAGNITUDE INCREASES and the direction is DOWNWARD.

Combining the Components Together, these components produce what is called a trajectory or path. This path is parabolic in nature. Component Magnitude Direction Horizontal Constant Vertical Changes

Horizontally Launched Projectiles Projectiles which have NO upward trajectory and NO initial VERTICAL velocity.

Horizontally Launched Projectiles To analyze a projectile in 2 dimensions we need 2 equations. One for the “x” direction and one for the “y” direction. And for this we use kinematic #2. Remember, the velocity is CONSTANT horizontally, so that means the acceleration is ZERO! Remember that since the projectile is launched horizontally, the INITIAL VERTICAL VELOCITY is equal to ZERO.

Horizontally Launched Projectiles Example: A plane traveling with a horizontal velocity of 100 m/s is 500 m above the ground. At some point the pilot decides to drop some supplies to designated target below. (a) How long is the drop in the air? (b) How far away from point where it was launched will it land? What do I know? What I want to know? vox=100 m/s t = ? y = 500 m x = ? voy= 0 m/s g = -9.8 m/s/s 1010 m 10.1 seconds

Horizontally Launched Projectiles Example: A plane traveling with a horizontal velocity of 100 m/s is 500 m above the ground. At some point the pilot decides to drop some supplies to designated target below. (a) How long is the drop in the air? (b) How far away from point where it was launched will it land?

P74 /p 99 P 78 /p99

Vertically Launched Projectiles NO Vertical Velocity at the top of the trajectory. Vertical Velocity decreases on the way upward Vertical Velocity increases on the way down, Horizontal Velocity is constant Component Magnitude Direction Horizontal Constant Vertical Decreases up, 0 @ top, Increases down Changes

#79/ p 99

Vertically Launched Projectiles Since the projectile was launched at a angle, the velocity MUST be broken into components!!! vo voy q vox

Vertically Launched Projectiles There are several things you must consider when doing these types of projectiles besides using components. If it begins and ends at ground level, the “y” displacement is ZERO: y = 0

Vertically Launched Projectiles You will still use kinematic #2, but YOU MUST use COMPONENTS in the equation. vo voy q vox

A place kicker kicks a football with a velocity of 20 A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (a) How long is the ball in the air? (b) How far away does it land? (c) How high does it travel?

Example A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (a) How long is the ball in the air? (b) How far away does it land? (c) How high does it travel? vo=20.0 m/s q = 53

Example What I know What I want to know vox=12.04 m/s t = ? voy=15.97 m/s x = ? y = 0 ymax=? g = - 9.8 m/s/s A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (a) How long is the ball in the air? 3.26 s

Example A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (b) How far away does it land? What I know What I want to know vox=12.04 m/s t = 3.26 s voy=15.97 m/s x = ? y = 0 ymax=? g = - 9.8 m/s/s 39.24 m

Example What I know What I want to know t = 3.26 s x = 39.24 m y = 0 vox=12.04 m/s t = 3.26 s voy=15.97 m/s x = 39.24 m y = 0 ymax=? g = - 9.8 m/s/s A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (c) How high does it travel? CUT YOUR TIME IN HALF! 13.01 m

#84 p 99, 85 / p 100- College Physics P91 How do you get the Maximum Range ?

Conceptual Physics p 28-31 Assign the 3 topics to certain individual in the group : Vector and Scalar Quantities Velocity Vectors Component of Vectors Read and write the information – 10 minutes Share Write the shared information Call people to share – Big group

Force Vectors Velocity of river and boat Velocity of the plane and tail wind Velocity of the plane and the headwind

Ex 3.9 p 87 #74, 76 p 99 #79 / p 99 #84 / p 99 #85 / p 100

Class work : Suppose a golf ball is hit off the tee with an initial velocity of 30 m/s at an angle of 35o to the horizontal. What is the maximum height reached by the ball? What is its range ?