Memory Management I: Dynamic Storage Allocation Oct 7, 1999

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Presentation transcript:

Memory Management I: Dynamic Storage Allocation Oct 7, 1999 15-213 “The course that gives CMU its Zip!” Memory Management I: Dynamic Storage Allocation Oct 7, 1999 Topics Explicit memory allocation Data structures Mechanisms Notes for next time: Need a separate slide with the simplifying caveats: 1. word-addressed blocks 2. words big enough to hold pointers 3. sometimes our code assumes that the pointer to an allocated block points to the header rather than the body of the block. class14.ppt

Harsh Reality #3 Memory Matters Memory is not unbounded It must be allocated and managed Many applications are memory dominated Especially those based on complex, graph algorithms Memory referencing bugs especially pernicious Effects are distant in both time and space Memory performance is not uniform Cache and virtual memory effects can greatly affect program performance Adapting program to characteristics of memory system can lead to major speed improvements

Dynamic Storage Allocation Application Dynamic Storage Allocator Heap Memory Explicit vs. Implicit Storage Allocator Explicit: application allocates and frees space E.g., malloc and free in C Implicit: application allocates, but does not free space E.g. garbage collection in Java, ML or Lisp Allocation In both cases the storage allocator provides an abstraction of memory as a set of blocks Doles out free memory blocks to application Will discuss explicit storage allocation today

Process memory image memory invisible to kernel virtual memory user code stack %esp Memory mapped region for shared libraries the “brk” ptr run-time heap (via malloc) uninitialized data (.bss) initialized data (.data) program text (.text)

Malloc package void *malloc(int size) void free(void *p) if successful: returns 8-byte aligned pointer to memory block of at least size bytes is size=0, returns NULL if unsuccessful: returns NULL void free(void *p) returns block pointed at by p to pool of available memory p must come from a previous call to malloc(). Assumptions made in this lecture memory is word addressed (each word can hold a pointer) Free word Allocated block (4 words) Free block (3 words) Allocated word

Allocation example p1 = malloc(4) p2 = malloc(5) p3 = malloc(6) free(p2) p4 = malloc(2)

Constraints Applications: Allocators Can issue arbitrary sequence of allocation and free requests Free requests must correspond to an allocated block Allocators Can’t control number or size of allocated blocks Must respond immediately to all allocation requests i.e., can’t reorder or buffer requests Must allocate blocks from free memory i.e., can only place allocated blocks in free memory Must align blocks so they satisfy all alignment requirements usually 8 byte alignment Can only manipulate and modify free memory Can’t move the allocated blocks once they are allocated i.e., compaction is not allowed

Goals of good malloc/free Primary goals Good time performance for malloc and free Ideally should take constant time (not always possible) Should certainly not take linear time in the number of blocks Good space usage User allocated structures should be large fraction of operating-system allocated pages Need to avoid fragmentation Some other goals Good locality properties structures allocated close in time should be close in space “similar” objects should be allocated close in space Robust can check that free(p1) is on a valid allocated object p1 can check that memory references are to allocated space

Fragmentation Tendency for free blocks to become smaller over time leading to wasted space p1 = malloc(4) p2 = malloc(5) p3 = malloc(6) free(p2) p4 = malloc(6) oops! No general solution assuming we cannot move blocks We will consider several heuristics

Implementation Issues How do we know how much memory to free just given a pointer? How do we keep track of the free blocks? What do we do with the extra space when allocating a structure that is smaller than the free block it is placed in? How do we pick a block to use for allocation -- many might fit? How do we reinsert freed block? p0 free(p0) p1 = malloc(1)

Knowing how much to free Most standard method keep length of structure in word before the structure This is often called the header field requires an extra word for every allocated structure p0 = malloc(4) p0 5 free(p0) Block size data

Keeping track of free blocks Method 1: implicit list using lengths -- links all blocks Method 2: explicit list among the free blocks using pointers within the free blocks Method 3: segregated free lists Different free lists for different size classes Method 4: blocks sorted by size Can use a balanced tree (e.g. Red-Black tree) with pointers within each free block, and the length used as a key 5 4 6 2 5 4 6 2

Method 1: implicit list Need to identify whether each block is free or allocated Can use extra bit Bit can be put in the same word as the size if block sizes are always multiples of two (mask out low order bit when reading size). 1 word a = 1: allocated block a = 0: free block size: block size data: application data (allocated blocks only) size a data Format of allocated and free blocks

Implicit list: finding a free block First fit: Search list from beginning, choose first free block that fits Can take linear time in total number of blocks (allocated and free) In practice it can cause “splinters” at beginning of list Next fit: Like first-fit, but search list from location of end of previous search Does a better job of spreading out the free blocks Best fit: Search the list, choose the free block with the closest size that fits Keeps fragments small --- usually helps fragmentation Will typically run slower than first-fit P = start; while ((p < end) || \\ not passed end (*p & 1) || \\ already allocated (*p <= len)); \\ too small

Implicit list: allocating in a free block Allocating in a free block - splitting Since allocated space might be smaller than free space, we need to split the block 4 4 6 2 p void addblock(ptr p, int l) { int newsize = ((l + 1) >> 1) << 1; // add 1 and round up int oldsize = *p & -2; // mask out low bit *p = newsize | 1; // set new length if (newsize < oldsize) *(p+newsize) = oldsize - newsize; // set length in remaining } // part of block addblock(p,2); 4 4 4 2 2

Implicit list: freeing a block Simplest implementation: Only need to clear allocated flag void free(ptr p) { *p = *p & -2} But can lead to “false fragmentation” There is enough free space, but the allocator won’t be able to find it 4 4 4 2 2 p free(p) 4 4 4 2 2 malloc(5) Oops!

Implicit list: coalescing Join with next and/or previous block if they are free Coalescing with next block void free(ptr p) { *p = *p & -2; // clear allocated flag next = p + *p; // find next block if ((*next & 1) == 0) *p = *p + *next; // add to this block if } // not allocated But how do we coalesce with previous block? 4 4 4 2 2 p free(p) 4 4 6 2

Implicit list: bidirectional Boundary tags [Knuth73] replicate size/allocated word at bottom of free blocks Allows us to traverse the “list” backwards, but requires extra space 1 word header size a a = 1: allocated block a = 0: free block size: block size data: application data (allocated blocks only) data Format of allocated and free blocks boundary tag (footer) size a 4 4 4 4 6 6 4 4

Constant time coalescing Case 1 Case 2 Case 3 Case 4 allocated allocated free free block being freed allocated free allocated free

Constant time coalescing (case 1) n 1 n m2 1 m2 1 m2 1 m2 1

Constant time coalescing (case 2) 1 m1 1 m1 1 m1 1 n 1 n+m2 n 1 m2 m2 n+m2

Constant time coalescing (case 3) n+m1 m1 n 1 n 1 n+m1 m2 1 m2 1 m2 1 m2 1

Constant time coalescing (case 4) n+m1+m2 m1 n 1 n 1 m2 m2 n+m1+m2

Implicit lists: Summary Implementation: very simple Allocate: linear time worst case Free: constant time worst case -- even with coalescing Memory usage: will depend on placement policy First fit, next fit or best fit Not used in practice for malloc/free because of linear time allocate. Used in many special purpose applications.

Keeping track of free blocks Method 1: implicit list using lengths -- links all blocks Method 2: explicit list among the free blocks using pointers within the free blocks Method 3: segregated free lists Different free lists for different size classes Method 4: blocks sorted by size Can use a balanced tree (e.g. Red-Black tree) with pointers within each free block, and the length used as a key 5 4 6 2 5 4 6 2

Linked list of free blocks Use data space for link pointers Typically doubly linked Still need header and footer for coalescing It is important to realize that links are not necessarily in the same order as the blocks A B C Forward links A B 4 4 4 4 6 6 4 4 4 4 C Back links

Linked list of free blocks Allocation Splice block out of the free list Split the block If remaining space, put space back onto the free list Free Determine if coalescing with neighboring block If not coalescing, add block to free list If coalescing with next block, need to splice next block out of the free list, and add self into it If coalescing with previous block, only need to modify lengths of previous block If coalescing with both previous and next, then need to splice the next block out of the free list (but not add self)

Linked list of free blocks Comparison to implicit list: Allocate is linear time in number of free blocks instead of total blocks -- much faster allocates when most of the memory is full Slightly more complicated allocate and free since needs to splice blocks in and out of the list Some extra space for the links (4 words needed for each block) Main use of linked lists is in conjunction with segregated free lists Keep multiple linked lists of different size classes, or possibly for different types of objects

For more information D. Knuth, “The Art of Computer Programming, Second Edition”, Addison Wesley, 1973 the classic reference on dynamic storage allocation Wilson et al, “Dynamic Storage Allocation: A Survey and Critical Review”, Proc. 1995 Int’l Workshop on Memory Management, Kinross, Scotland, Sept, 1995. comprehensive survey $classdir/doc/dsa.ps