Which of the following is a conjugate pair? A.H+ and OH−

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Presentation transcript:

Which of the following is a conjugate pair? A.H+ and OH− Acids and Bases Bellringer MULTIPLE CHOICE Which of the following is a conjugate pair? A.H+ and OH− B. NH2− and NH4+ C. HCl and Cl− D.H2SO4 and SO42−

Topic XII Acids and Bases Lewis theory of acids and bases 2 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 2

Lewis Acids and Bases According to Gilbert Lewis, an acid accepts a pair of electrons and a base donates a pair of electrons during a reaction. This definition is more general than those offered by Arrhenius or by Brønsted and Lowry. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 3

Consider the reaction of H+ and OH–. Lewis Acids and Bases Consider the reaction of H+ and OH–. H+ accepts the pair of electrons from OH-. The hydroxide ion can bond to the hydrogen ion because it has an unshared pair of electrons. OH− is a Lewis base, and H+, which accepts the pair of electrons, is a Lewis acid. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 4

Lewis Acids and Bases A second example of a reaction between a Lewis acid and a Lewis base is what happens when ammonia dissolves in water. Hydrogen ions from the dissociation of water are the electron-pair acceptor and the Lewis acid. Ammonia is the electron-pair donor and the Lewis base. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 5

Acid-Base Definitions Interpret Data This table compares the definitions of acids and bases. Acid-Base Definitions Type Acid Base Arrhenius H+ producer OH– producer Brønsted-Lowry H+ donor H+ acceptor Lewis electron-pair acceptor electron-pair donor The Lewis definition is the broadest. It extends to compounds that the Brønsted-Lowry theory does not classify as acids and bases. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 6

Identifying Lewis Acids and Bases Sample Problem Identifying Lewis Acids and Bases Identify the Lewis acid and the Lewis base in this reaction between ammonia and boron trifluoride. NH3 + BF3 → NH3BF3 Analyze Identify the relevant concepts. 1 When a Lewis acid reacts with a Lewis base, the base donates a pair of electrons and the acid accepts the donated pair. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 7

Solve Apply concepts to this problem. Sample Problem Solve Apply concepts to this problem. 2 Identify the reactant with the unshared pair of electrons and the reactant that can accept the pair of electrons. Draw electron dot structures to identify which reactant has an unshared pair of electrons. Ammonia has an unshared pair of electrons to donate. The boron atom can accept the donated electrons. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 8

Solve Apply concepts to this problem. Sample Problem Solve Apply concepts to this problem. 2 Classify the reactants based on their behavior. Lewis bases donate a pair of electrons, so ammonia is the Lewis base. Lewis acids accept a pair of electrons, so boron trifluoride is the Lewis acid. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 9

Are hydrogen-ion donors also electron-pair acceptors? Yes. All substances defined as acids by the Brønsted- Lowry definition (an acid is a hydrogen-ion donor) are also defined as acids by the Lewis definition (an acid is an electron-pair acceptor). That means that these substances are both hydrogen- ion donors and electron-pair acceptors. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 10

Key Concepts Summary According to Arrhenius, acids are hydrogen-containing compounds that ionize to yield hydrogen ions in aqueous solution. Bases are compounds that ionize to yield hydroxide ions in aqueous solution. According to Brønsted-Lowry theory, an acid is a hydrogen-ion donor and a base is a hydrogen-ion acceptor. According to Lewis, an acid accepts a pair of electrons and a base donates a pair of electrons. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11