Chapter 18 Mirrors/lenses.

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Presentation transcript:

Chapter 18 Mirrors/lenses

Concave mirrors

Uses?

Convex mirrors

Uses?

Formulas and problems Lens/Mirror equation 1/f = 1/di + 1/do Magnification Focal length m = hi/ho f = r/2 m = -di/do Image height hi = -ho (di/do)

A 4 cm high candle is placed 10 cm from a concave mirror having a focal length of 16 cm. Find the location and height of the image.

A 4 cm high candle is placed 10 cm from a concave mirror having a focal length of 16 cm. Find the location and height of the image. What we know: ho = 4 cm di = ? do = 10 cm hi = ? f = 16 cm

Solving for di Use the lens/mirror equation to find di when possible 1/16 = 1/di + 1/10 1/16 - 1/10 = 1/di 1/di = -0.0375 di = 1/-.0375 di = -26.6 cm So, the image is 26.6 cm away from the mirror, and it is inverted (that’s what the negative sign means)

Solving for hi Use hi = -ho (di/do) hi = -4 (-26.6/10) hi = 10.64 cm

Work: Page 425 #’s 2-3 (do not draw ray diagrams, just solve)