Buoyant Force Contents: How to calculate Whiteboards.

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Presentation transcript:

Buoyant Force Contents: How to calculate Whiteboards

Buoyant force is the weight of displaced water: ρf = Density of fluid in kg m-3 Vf = Volume of displace fluid in m3 g = 9.81 N kg-1 Derive Demo: Float not float/Cartesian Diver/hot air balloons/hydrometer

Buoyant force is the weight of displaced water: ρf = Density of fluid in kg m-3 Vf = Volume of displace fluid in m3 g = 9.81 N kg-1 What is the buoyant force on a 3.0 cm diameter air bubble under water? ρH2O = 1.0E3 kg m-3 0.14 N

ρf = Density of fluid in kg m-3 Vf = Volume of displace fluid in m3 g = 9.81 N kg-1 What is the buoyant force on a 5.45 kg iron shot submerged in water? What is the weight of the shot in air, and what is its apparent weight submerged? ρFe = 7.8E3 kg m-3, ρH2O = 1.0E3 kg m-3, ρ = m/V so V = m/ρ 6.85 N, 53.5 N, 46.6 N

ρAu = 19.3E3 kg m-3, ρH2O = 1.0E3 kg m-3, ρ = m/V so V = m/ρ ρf = Density of fluid in kg m-3 Vf = Volume of displace fluid in m3 g = 9.81 N kg-1 The King’s crown has a mass of 14.7 kg, but appears to have a mass of only 13.4 kg when weighed when it is submerged in water. What is the density of the crown? Is it gold? ρAu = 19.3E3 kg m-3, ρH2O = 1.0E3 kg m-3, ρ = m/V so V = m/ρ 11.3x103 kg m-3, so no

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Buoyant Forces 1 | 2 | 3

What is the buoyant force on a rectangular block of wood that measures 12x23x15 cm if it is submerged in the Dead Sea where the density of the water is 1240 kg m-3? (convert cm to m first) 50. N

A 15x15x5. 0 cm piece of wood floats in water (1000 A 15x15x5.0 cm piece of wood floats in water (1000. kg m-3) face down in the water with the waterline 3.1 cm up the 5.0 cm side: What is its mass? What is its density? 620 kg m-3

A 5.0x4.0x4.0 cm piece of wood with a density of 530 kg m-3 is tied to the bottom of a pail of water (1000. kg m-3) with a string and held completely submerged. What is the tension on the string? 0.37 N

A 25x25x10 cm block of iron (7. 80x103 kg m-3) floats on mercury (13 A 25x25x10 cm block of iron (7.80x103 kg m-3) floats on mercury (13.6x103 kg m-3) If one of the 25x25 cm faces is down into the mercury, how far into the mercury does the block sink before coming to equilibrium? 5.7 cm