Lesson 4-8 Objective The student will be able to:

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Lesson 4-8 Objective The student will be able to: use the zero product property to solve equations

Zero Product Property If a • b = 0 then a=0, b=0, or both a and b equal 0.

1. Solve (x + 3)(x - 5) = 0 Using the Zero Product Property, you know that either x + 3 = 0 or x - 5 = 0 Solve each equation. x = -3 or x = 5 {-3, 5}

2. Solve (2a + 4)(a + 7) = 0 2a + 4 = 0 or a + 7 = 0 2a = -4 or a = -7 {-2, -7}

3t + 5 = 0 or t - 3 = 0 3t = -5 or t = 3 t = -5/3 or t = 3 {-5/3, 3} 3. Solve (3t + 5)(t - 3) = 0 3t + 5 = 0 or t - 3 = 0 3t = -5 or t = 3 t = -5/3 or t = 3 {-5/3, 3}

Solve (y – 3)(2y + 6) = 0 {-3, 3} {-3, 6} {3, 6} {3, -6}

4 steps for solving a quadratic equation- Lesson 4-8 Set the equation equal to 0. Factor the equation. Set each part equal to 0 and solve. Check your answer on the calculator. Set = 0 Factor Split/Solve Check

4. Solve x2 - 11x = 0 GCF = x x(x - 11) = 0 x = 0 or x - 11 = 0 {0, 11} Set = 0 Factor Split/Solve Check

Put it in descending order. 5. Solve. -24a +144 = -a2 Put it in descending order. a2 - 24a + 144 = 0 (a - 12)2 = 0 a - 12 = 0 a = 12 {12} Set = 0 Factor Split/Solve Check

6. Solve 4m2 + 25 = 20m 4m2 - 20m + 25 = 0 (2m - 5)2 = 0 2m - 5 = 0 Set = 0 Factor Split/Solve Check

7. Solve x3 + 2x2 = 15x x3 + 2x2 - 15x = 0 x(x2 + 2x - 15) = 0 x = 0 or x + 5 = 0 or x - 3 = 0 {0, -5, 3} Set = 0 Factor Split/Solve Check

Solve a2 – 3a = 40 {-8, 5} {-5, 8} {-8, -5} {5, 8}

The degree will tell you how many answers you have! Solve 4r3 – 16r = 0 {-16, 4} {-4, 16} {0, 2} {0, 4} {-2, 0, 2} The degree will tell you how many answers you have!

0 is not reasonable so Maria is 15 years old!! Maria told this puzzle to her friends. “The product of four times my age and 45 less than three times my age is zero. How old am I?” Find Maria’s age. Let m = Maria’s age. 4m(3m - 45) = 0 4m = 0 or 3m - 45 = 0 m = 0 or 3m = 45 m = 0 or m = 15 0 is not reasonable so Maria is 15 years old!!