Linear Algebra Lecture 34.

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Presentation transcript:

Linear Algebra Lecture 34

Linear Algebra Lecture 34

Eigenvalues and Eigenvectors

Applications to Differential Equations

System of Differential Equations

Differential Equation System as a Matrix Differential Equation

If u and v are solutions of Then cu + dv is also a solution because Superposition of Solutions If u and v are solutions of Then cu + dv is also a solution because

If A is n x n, then there are n linearly independent functions in a Fundamental Set, and each solution of is a unique linear combination of these n functions.

That is, a Fundamental Set of solutions is a basis for the set of all solutions of

Initial Value Problem

Example …

continued The given system is said to be decoupled because each derivative of a function depends only on the function itself, not on some combination or “coupling” of both x1(t) and x2(t). …

continued The solutions of the equations are x1(t) = c1e3t and x2(t) = c2e-5t, for any constants c1 and c2.

Each solution of given system can be written in the form continued Each solution of given system can be written in the form

Observe …

The circuit in figure 1 can be described by Example 1 The circuit in figure 1 can be described by where v1(t) and v2(t) are the voltages across the two capacitors at time t. …

continued Figure 1 …

continued Suppose that resistor R1 is 2 ohms, R2 is 1 ohms, capacitor C1 is 2 farads, and capacitor C2 is 1 farad, and suppose that there is an initial charge of 5 volts on capacitor C1 and 4 volts on capacitor C2. …

continued Find formulas for v1(t) and v2(t) that describe how the voltages change over time.

Example 2 Suppose a particle is moving in a planar force field and its position vector x satisfies and x(0) = x0, where

continued Solve this initial value problem and sketch the trajectory of the particle, for

Decoupling a Dynamical System

Complex Eigenvalues

The circuit in figure 2 can be described by Example 3 The circuit in figure 2 can be described by …

continued Figure 2 …

continued where iL is the current passing through the inductor L and vc is the voltage drop across the capacitor C. Suppose R1 is 5 ohms, R2 is .8 ohm, C is .1 farad, and L is .4 henry. …

continued Find formulas for iL and vc, if the initial current through the inductor is 3 amperes and the initial voltage across the capacitor is 3 volts.

Example 4

Linear Algebra Lecture 34

Linear Algebra Lecture 34