Problem In the position shown, collar B moves A

Slides:

Advertisements

Similar presentations

Relative Motion & Constrained Motion

Advertisements

ABSOLUTE DEPENDENT MOTION ANALYSIS OF TWO PARTICLES

PLANAR KINETIC EQUATIONS OF MOTION: TRANSLATION (Sections )

Kinematics of Particles

Physics Unit 2 Constant Velocity

King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 7.

01-1 Physics I Class 01 1D Motion Definitions.

02-1 Physics I Class 02 One-Dimensional Motion Definitions.

Physics 2011 Chapter 2: Straight Line Motion. Motion: Displacement along a coordinate axis (movement from point A to B) Displacement occurs during some.

Position, Velocity and Acceleration Analysis

Write and graph a direct variation equation

Science Starter! Complete the worksheet “Science Starter!” (on teacher’s desk).

Physics 201 2: Vectors Coordinate systems Vectors and scalars Rules of combination for vectors Unit vectors Components and coordinates Displacement and.

Constrained Motion of Connected Particles

1-D Kinematics. Science of describing motion. Words Diagrams Numbers Graphs Equations Develop sophosticated mental models that describe the motion of.

ABSOLUTE DEPENDENT MOTION ANALYSIS OF TWO PARTICLES Today’s Objectives: Students will be able to: 1.Relate the positions, velocities, and accelerations.

4 - 1 Kinematics of Particles Kinematics is the study of motion without reference to the force which produced the motion. First, we will study the kinematics.

Motion in One Dimension

Differential equations. Many applications of mathematics involve two variables and a relation between them is required. This relation is often expressed.

2.1 Position, Velocity, and Speed 2.1 Displacement  x  x f - x i 2.2 Average velocity 2.3 Average speed  

Problem c 240 mm b x B A z y Collars A and B are connected by the wire AB and can slide freely on the rods shown. Knowing that the length of the.

Relationship Between Velocity and Acceleration Velocity and acceleration are in the same direction Acceleration is uniform (blue arrows maintain the same.

Physics Lecture 14 Instructor: John H. Hamilton. Last Lecture Review This week – Position – Change in position wrt time – Change in velocity wrt time.

Describing Motion.

Method of Virtual Work.

Problem Locate the centroid of the plane area shown. y x 20 mm

ABSOLUTE DEPENDENT MOTION ANALYSIS OF TWO PARTICLES

Acceleration Analysis

RELATIVE MOTION ANALYSIS: VELOCITY (Section 16.5)

2. Motion 2.1. Position and path Motion or rest is relative.

To find the solution of simultaneous equations graphically: 1)

Prepared by Dr. Hassan Fadag.

Chapter 2 Describing Motion: Kinematics In One Dimension

Vectors for Mechanics.

Motion Graphs Position-Time (also called Distance-Time or Displacement-Time) d t At rest.

Problem 5-a Locate the centroid of the plane area shown. y x 20 mm

12.10 Relative-Motion Analysis of Two Particles Using Translating Axes

RELATIVE MOTION ANALYSIS: VELOCITY

KINEMATICS OF RIGID BODY

Physics Unit 2 Constant Velocity

GENERAL & RECTANGULAR COMPONENTS

ABSOLUTE DEPENDENT MOTION ANALYSIS OF TWO PARTICLES

RELATIVE MOTION ANALYSIS: ACCELERATION

Physics 111: Mechanics Lecture 2

MOTION OF A PROJECTILE Today’s Objectives: Students will be able to:

Homework: See Handout. Turn in Lab #1Wednesday

Section Indefinite Integrals

RIGID BODY MOTION (Section 16.1)

Kinematics of Particles

MOTION IN A STRAIGHT LINE GRAPHICALLY

RELATIVE MOTION ANALYSIS: VELOCITY

ABSOLUTE DEPENDENT MOTION ANALYSIS OF TWO PARTICLES

MOTION OF A PROJECTILE Today’s Objectives: Students will be able to:

Motion in One Dimension

Systems of Particles.

Packet #7 Applications: Rates of Change

MOTION IN A STRAIGHT LINE GRAPHICALLY

One last thing about motion graphs

Physics 111: Mechanics Lecture 2

Physics Unit 2 Constant Velocity

Kinematics in one-Dimension

MOTION IN A STRAIGHT LINE GRAPHICALLY

Section Indefinite Integrals

Motion Investigate the relationships among speed, position, time, velocity, and acceleration.

Calculus I (MAT 145) Dr. Day Wednesday April 10, 2019

GENERAL & RECTANGULAR COMPONENTS

Projectile Motion and Relative Velocity

King Fahd University of Petroleum & Minerals

Presentation transcript:

Problem 11.186 In the position shown, collar B moves A to the left with a velocity of 150 mm/s. Determine (a) the velocity of collar A, (b) the velocity of portion C of the cable, (c) the relative velocity of portion C of the cable with respect to collar B. A B C

Solving Problems on Your Own In the position shown, collar B moves to the left with a velocity of 150 mm/s. Determine (a) the velocity of collar A, (b) the velocity of portion C of the cable, (c) the relative velocity of portion C of the cable with respect to collar B. A B C 1. Dependent motion of two or more particles: 1a. Draw a sketch of the system: Select a coordinate system, indicating clearly a positive sense for each of the coordinate axes. The displacements, velocities, and accelerations have positive values in the direction of the coordinate axes. 1b. Write the equation describing the constraint: When particles are connected with a cable, its length which remains constant is the constraint.

Solving Problems on Your Own In the position shown, collar B moves to the left with a velocity of 150 mm/s. Determine (a) the velocity of collar A, (b) the velocity of portion C of the cable, (c) the relative velocity of portion C of the cable with respect to collar B. A B C 1c. Differentiate the equation describing the constraint: This gives the the corresponding relations among velocities and accelerations of the various particles.

constant = 2xA + xB + (xB - xA) Draw a sketch of the system. Problem 11.186 Solution A B C xA xC xB Write the equation describing the constraint. The total length of the cable: (a) constant = 2xA + xB + (xB - xA) vB = 150 mm/s Differentiate the equation describing the constraint. 0 = vA + 2vB vB = 150 mm/s vA = - 2 vB vA = -300 mm/s vA = 300 mm/s

constant = 2xA + xC 0 = 2vA + vC vC = - 2vA vC = 600 mm/s Problem 11.186 Solution xA A (b) The length of the cable from the right end to an arbitrary point on portion C of the cable: C B xC constant = 2xA + xC xB vB = 150 mm/s 0 = 2vA + vC vC = - 2vA vC = 600 mm/s (c) Relative velocity of portion C: vC = vB + vC/B 600 = 150 + vC/B vC/B = 450 mm/s