AMPLIFIERS Presenter :王智偉 Advisor : Chih-Kuo Liang.

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Presentation transcript:

AMPLIFIERS Presenter :王智偉 Advisor : Chih-Kuo Liang

Outline NONINVERTING SUMMING AMPLIFIER AC-COUPLED AMPLIFIER CURRENT AMPLIFIER HIGH-CURRENT AMPLIFIER

NONINVERTING SUMMING AMPLIFIER Numerical Analysis Voltage Gain RI RF Rin Rout AOL VI VO 2.7kΩ 3.9kΩ (2.28) =3.9k/2.7k +1 3.25v =2.44

NONINVERTING SUMMING AMPLIFIER Output Voltage (2.1) =2.44*3.25 V =7.93 V

AC-COUPLED AMPLIFIER Voltage Gain - + (2.37) Rf 68k CI RI VI Co 27k 0.02uF + 0.02uF 39kΩ RL

AC-COUPLED AMPLIFIER Xc=1/(62.8*800 Hz*0.02uF) =9.95kΩ =28.8kΩ

AC-COUPLED AMPLIFIER Bandwidth =(1 MHz*27 kΩ)/(68 kΩ+27 kΩ) (2.37) (2.40) =(1 MHz*27 kΩ)/(68 kΩ+27 kΩ) =-(68 kΩ/28.80kΩ) =-2.4 =284 kHz

AC-COUPLED AMPLIFIER =295 Hz/204 Hz =1/(6.28*27 kΩ*0.02 uF) =295 Hz (2.41) (2.42) =295 Hz/204 Hz =1/(6.28*27 kΩ*0.02 uF) =295 Hz =1.45

AC-COUPLED AMPLIFIER =295 Hz*1.32 =284 kHz-389 kHz =389 Hz =283.6 kHz (2.43) =295 Hz*1.32 =284 kHz-389 kHz =389 Hz =283.6 kHz

CURRENT AMPLIFIER Numerical Analysis - =56 kΩ/1 kΩ+1 + =57 Current Gain I1 R1 1 kΩ IL R2 56 kΩ RL 3 kΩ (2.45) I1 - =56 kΩ/1 kΩ+1 + =57 10~50uF

CURRENT AMPLIFIER =50 uA*57 =10 uA*57 =570uA =2.85 mA

CURRENT AMPLIFIER Numerical Analysis Range of Acceptable Input Currents (2.46) =(1 kΩ*13 V)/〔1 kΩ(56 kΩ+3 kΩ)+(56 kΩ*3 kΩ)〕 =57.3 uA

CURRENT AMPLIFIER Numerical Analysis =13 V/(57*50 uA)-56 kΩ/57 Maximum Load Resistance =13 V/(57*50 uA)-56 kΩ/57 =3.58 kΩ

CURRENT AMPLIFIER Numerical Analysis Input Resistance (2.47)

CURRENT AMPLIFIER =(1.0 kΩ*56 kΩ)/(1.0 kΩ+56 kΩ) (2.47) =(1.0 kΩ*56 kΩ)/(1.0 kΩ+56 kΩ) =〔56 kΩ(982 Ω+3 kΩ)〕/〔982 Ω(1+50000)+3 kΩ〕 =982 Ω =4.54 Ω

CURRENT AMPLIFIER Numerical Analysis =50000*982 Ω =49.1 MΩ Output Resistance (2.48) =50000*982 Ω =49.1 MΩ

HIGH-CURRENT AMPLIFIER Numerical Analysis +15V RF 220kΩ 22uF 27kΩ - (2.49) (MJE1103) CI RI + =750*4 Vo VI RB 22kΩ =3000 Ω RL 4Ω RP + V 5kΩ

HIGH-CURRENT AMPLIFIER (2.50) =10 V-2.5 V =7.5 V/4 Ω =7.5 V =1.88 A

HIGH-CURRENT AMPLIFIER (2.51) =1.88 A/750 =2.51 mA

HIGH-CURRENT AMPLIFIER (2.52) =(10 V+2.5 V)/2 =6.25 V =10 V-2.5 V =7.5 V peak-to-peak

HIGH-CURRENT AMPLIFIER

HIGH-CURRENT AMPLIFIER (2.6) =-(220 kΩ/27 kΩ) =-8.15

HIGH-CURRENT AMPLIFIER (2.1) =7.5/8.15 =0.92 V peak-to-peak

Thanks for your attention