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Presentation transcript:

2017 session 1 TELE3118: Network Technologies Week 10: Transport Layer TCP Slides have been adapted from: Computer Networking: A Top Down Approach, 7th (global) edition. Jim Kurose, Keith Ross. Pearson, April 2016. All material copyright 1996-2016. J.F Kurose and K.W. Ross, All Rights Reserved. Computer Networks, 5th edition. Andrew S. Tanenbaum, David J. Wetherall, Pearson, 2010. Transport Layer

Principles of congestion control informally: “too many sources sending too much data too fast for network to handle” different from flow control! manifestations: lost packets (buffer overflow at routers) long delays (queueing in router buffers) a top-10 problem! Transport Layer

Causes/costs of congestion: scenario 1 original data: lin throughput: lout two senders, two receivers one router, infinite buffers output link capacity: R no retransmission Host A unlimited shared output link buffers Host B R/2 delay lin R/2 lout lin maximum per-connection throughput: R/2 large delays as arrival rate, lin, approaches capacity Transport Layer

Causes/costs of congestion: scenario 2 one router, finite buffers sender retransmission of timed-out packet application-layer input = application-layer output: lin = lout transport-layer input includes retransmissions : lin lin ‘ lin : original data lout l'in: original data, plus retransmitted data Host A finite shared output link buffers Host B Transport Layer

Causes/costs of congestion: scenario 2 lout lin idealization: perfect knowledge sender sends only when router buffers available lin : original data lout copy l'in: original data, plus retransmitted data A free buffer space! finite shared output link buffers Host B Transport Layer

Causes/costs of congestion: scenario 2 Idealization: known loss packets can be lost, dropped at router due to full buffers sender only resends if packet known to be lost lin : original data lout copy l'in: original data, plus retransmitted data A no buffer space! Host B Transport Layer

Causes/costs of congestion: scenario 2 Idealization: known loss packets can be lost, dropped at router due to full buffers sender only resends if packet known to be lost R/2 lin lout when sending at R/2, some packets are retransmissions but asymptotic goodput is still R/2 (why?) lin : original data lout l'in: original data, plus retransmitted data A free buffer space! Host B Transport Layer

Causes/costs of congestion: scenario 2 Realistic: duplicates packets can be lost, dropped at router due to full buffers sender times out prematurely, sending two copies, both of which are delivered R/2 when sending at R/2, some packets are retransmissions including duplicated that are delivered! lout lin R/2 timeout lin lout copy l'in A free buffer space! Host B Transport Layer

Causes/costs of congestion: scenario 2 Realistic: duplicates packets can be lost, dropped at router due to full buffers sender times out prematurely, sending two copies, both of which are delivered R/2 when sending at R/2, some packets are retransmissions including duplicated that are delivered! lout lin R/2 “costs” of congestion: more work (retrans) for given “goodput” unneeded retransmissions: link carries multiple copies of pkt decreasing goodput Transport Layer

Causes/costs of congestion: scenario 3 Q: what happens as lin and lin’ increase ? four senders multihop paths timeout/retransmit A: as red lin’ increases, all arriving blue pkts at upper queue are dropped, blue throughput g 0 Host A lout lin : original data Host B l'in: original data, plus retransmitted data finite shared output link buffers Host D Host C Transport Layer

Causes/costs of congestion: scenario 3 lout lin’ C/2 another “cost” of congestion: when packet dropped, any “upstream transmission capacity used for that packet was wasted! Transport Layer

Approaches towards congestion control Two broad approaches towards congestion control: End-end congestion control: no explicit feedback from network congestion inferred from end-system observed loss, delay approach taken by TCP Network-assisted congestion control: routers provide feedback to end systems single bit indicating congestion (SNA, DECbit, TCP/IP ECN, ATM) explicit rate sender should send at Transport Layer

TCP Congestion Control end-end control (no network assistance) sender limits transmission: LastByteSent-LastByteAcked  CongWin Roughly, cwnd is dynamic, function of perceived network congestion How does sender perceive congestion? loss event = timeout or 3 duplicate acks TCP sender reduces rate (cwnd) after loss event three mechanisms: AIMD slow start conservative after timeout events rate = cwnd RTT Bytes/sec Transport Layer

TCP congestion control: additive increase multiplicative decrease approach: sender increases transmission rate (window size), probing for usable bandwidth, until loss occurs additive increase: increase cwnd by 1 MSS every RTT until loss detected multiplicative decrease: cut cwnd in half after loss additively increase window size … …. until loss occurs (then cut window in half) AIMD saw tooth behavior: probing for bandwidth congestion window size cwnd: TCP sender time Transport Layer

TCP Congestion Control: details TCP sending rate: roughly: send cwnd bytes, wait RTT for ACKS, then send more bytes sender sequence number space cwnd last byte ACKed last byte sent sent, not-yet ACKed (“in-flight”) cwnd RTT sender limits transmission: cwnd is dynamic, function of perceived network congestion rate ~ bytes/sec LastByteSent- LastByteAcked < cwnd Transport Layer

TCP Slow Start Host A Host B when connection begins, increase rate exponentially until first loss event: initially cwnd = 1 MSS double cwnd every RTT done by incrementing cwnd for every ACK received summary: initial rate is slow but ramps up exponentially fast one segment RTT two segments four segments time Transport Layer

TCP: detecting, reacting to loss loss indicated by timeout: cwnd set to 1 MSS; window then grows exponentially (as in slow start) to threshold, then grows linearly loss indicated by 3 duplicate ACKs: TCP RENO dup ACKs indicate network capable of delivering some segments cwnd is cut in half window then grows linearly TCP Tahoe always sets cwnd to 1 (timeout or 3 duplicate acks) Transport Layer

TCP: switching from SS to CA Q: when should the exponential increase switch to linear? A: when cwnd gets to 1/2 of its value before timeout. Implementation: variable ssthresh on loss event, ssthresh is set to 1/2 of cwnd just before loss event * Check out the online interactive exercises for more examples: http://gaia.cs.umass.edu/kurose_ross/interactive/ Transport Layer

Summary: TCP Congestion Control New ACK! congestion avoidance cwnd = cwnd + MSS (MSS/cwnd) dupACKcount = 0 transmit new segment(s), as allowed new ACK . dupACKcount++ duplicate ACK slow start timeout ssthresh = cwnd/2 cwnd = 1 MSS dupACKcount = 0 retransmit missing segment cwnd = cwnd+MSS transmit new segment(s), as allowed new ACK dupACKcount++ duplicate ACK L ssthresh = 64 KB L cwnd > ssthresh timeout ssthresh = cwnd/2 cwnd = 1 MSS dupACKcount = 0 retransmit missing segment ssthresh= cwnd/2 cwnd = ssthresh + 3 retransmit missing segment dupACKcount == 3 timeout ssthresh = cwnd/2 cwnd = 1 dupACKcount = 0 cwnd = ssthresh dupACKcount = 0 New ACK ssthresh= cwnd/2 cwnd = ssthresh + 3 retransmit missing segment dupACKcount == 3 fast recovery cwnd = cwnd + MSS transmit new segment(s), as allowed duplicate ACK Transport Layer

TCP throughput avg. TCP thruput as function of window size, RTT? ignore slow start, assume always data to send W: window size (measured in bytes) where loss occurs avg. window size (# in-flight bytes) is ¾ W avg. thruput is 3/4W per RTT avg TCP thruput = 3 4 W RTT bytes/sec W W/2 Transport Layer

TCP Futures: TCP over “long, fat pipes” example: 1500 byte segments, 100ms RTT, want 10 Gbps throughput requires W = 83,333 in-flight segments throughput in terms of segment loss probability, L [Mathis 1997]: ➜ to achieve 10 Gbps throughput, need a loss rate of L = 2·10-10 – a very small loss rate! new versions of TCP for high-speed TCP throughput = 1.22 . MSS RTT L Transport Layer

TCP Fairness fairness goal: if K TCP sessions share same bottleneck link of bandwidth R, each should have average rate of R/K TCP connection 1 bottleneck router capacity R TCP connection 2 Transport Layer

Why is TCP fair? two competing sessions: additive increase gives slope of 1, as throughout increases multiplicative decrease decreases throughput proportionally R equal bandwidth share loss: decrease window by factor of 2 congestion avoidance: additive increase Connection 2 throughput loss: decrease window by factor of 2 congestion avoidance: additive increase Connection 1 throughput R Transport Layer

Fairness (more) Fairness, parallel TCP connections Fairness and UDP application can open multiple parallel connections between two hosts web browsers do this e.g., link of rate R with 9 existing connections: new app asks for 1 TCP, gets rate R/10 new app asks for 11 TCPs, gets R/2 Fairness and UDP multimedia apps often do not use TCP do not want rate throttled by congestion control instead use UDP: send audio/video at constant rate, tolerate packet loss Transport Layer

Explicit Congestion Notification (ECN) network-assisted congestion control: two bits in IP header (ToS field) marked by network router to indicate congestion congestion indication carried to receiving host receiver (seeing congestion indication in IP datagram) ) sets ECE bit on receiver-to-sender ACK segment to notify sender of congestion TCP ACK segment source destination application transport network link physical application transport network link physical ECE=1 ECN=11 ECN=11 ECN=00 IP datagram Transport Layer

TCP flow control flow control application process application may remove data from TCP socket buffers …. application OS TCP socket receiver buffers … slower than TCP receiver is delivering (sender is sending) TCP code IP code receiver controls sender, so sender won’t overflow receiver’s buffer by transmitting too much, too fast flow control from sender receiver protocol stack Transport Layer

TCP flow control receiver “advertises” free buffer space by including rwnd value in TCP header of receiver-to-sender segments RcvBuffer size set via socket options (typical default is 4096 bytes) many operating systems autoadjust RcvBuffer sender limits amount of unacked (“in-flight”) data to receiver’s rwnd value guarantees receive buffer will not overflow to application process buffered data free buffer space RcvBuffer rwnd TCP segment payloads receiver-side buffering Transport Layer

Connection Management before exchanging data, sender/receiver “handshake”: agree to establish connection (each knowing the other willing to establish connection) agree on connection parameters application application connection state: ESTAB connection variables: seq # client-to-server server-to-client rcvBuffer size at server,client connection state: ESTAB connection Variables: seq # client-to-server server-to-client rcvBuffer size at server,client network network Socket clientSocket = newSocket("hostname","port number"); Socket connectionSocket = welcomeSocket.accept(); Transport Layer

Agreeing to establish a connection 2-way handshake: Q: will 2-way handshake always work in network? variable delays retransmitted messages (e.g. req_conn(x)) due to message loss message reordering can’t “see” other side Let’s talk ESTAB OK ESTAB choose x req_conn(x) ESTAB acc_conn(x) ESTAB Transport Layer

Agreeing to establish a connection 2-way handshake failure scenarios: choose x req_conn(x) ESTAB acc_conn(x) client terminates ESTAB choose x req_conn(x) acc_conn(x) data(x+1) accept connection x completes server forgets x retransmit req_conn(x) ESTAB half open connection! (no client!) retransmit req_conn(x) ESTAB data(x+1) accept client terminates server forgets x connection x completes Transport Layer

TCP 3-way handshake client state server state LISTEN SYNSENT SYNbit=1, Seq=x choose init seq num, x send TCP SYN msg SYN RCVD ESTAB SYNbit=1, Seq=y ACKbit=1; ACKnum=x+1 choose init seq num, y send TCP SYNACK msg, acking SYN ACKbit=1, ACKnum=y+1 received SYNACK(x) indicates server is live; send ACK for SYNACK; this segment may contain client-to-server data received ACK(y) indicates client is live ESTAB Transport Layer

TCP 3-way handshake: FSM closed Socket connectionSocket = welcomeSocket.accept(); L Socket clientSocket = newSocket("hostname","port number"); SYN(x) SYNACK(seq=y,ACKnum=x+1) create new socket for communication back to client listen SYN(seq=x) SYN rcvd SYN sent SYNACK(seq=y,ACKnum=x+1) ACK(ACKnum=y+1) ACK(ACKnum=y+1) ESTAB L Transport Layer

TCP: closing a connection client, server each close their side of connection send TCP segment with FIN bit = 1 respond to received FIN with ACK on receiving FIN, ACK can be combined with own FIN simultaneous FIN exchanges can be handled Transport Layer

TCP: closing a connection client state server state ESTAB ESTAB FIN_WAIT_1 FINbit=1, seq=x can no longer send but can receive data clientSocket.close() CLOSE_WAIT FIN_WAIT_2 ACKbit=1; ACKnum=x+1 wait for server close can still send data can no longer send data LAST_ACK TIMED_WAIT FINbit=1, seq=y CLOSED timed wait for 2*max segment lifetime CLOSED ACKbit=1; ACKnum=y+1 Transport Layer